IIT JEE Practice Question and Answer
8Q: A box contains 4 different black balls, 3 different red balls and 5 different blue balls. In how many ways can the balls be selected if every selection must have at least 1 black ball and one red ball ? 2579 05b5cc6f4e4d2b4197774f004
5b5cc6f4e4d2b4197774f004- 124 - 1false
- 22425-1false
- 3(24-1)(23-1)25true
- 4Nonefalse
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Answer : 3. "(24-1)(23-1)25"
Explanation :
Answer: C) C Explanation: It is explicitly given that all the 4 black balls are different, all the 3 red balls are different and all the 5 blue balls are different. Hence this is a case where all are distinct objects. Initially let's find out the number of ways in which we can select the black balls. Note that at least 1 black ball must be included in each selection. Hence, we can select 1 black ball from 4 black ballsor 2 black balls from 4 black balls.or 3 black balls from 4 black balls.or 4 black balls from 4 black balls. Hence, number of ways in which we can select the black balls = 4C1 + 4C2 + 4C3 + 4C4= 24-1 ........(A) Now let's find out the number of ways in which we can select the red balls. Note that at least 1 red ball must be included in each selection. Hence, we can select 1 red ball from 3 red ballsor 2 red balls from 3 red ballsor 3 red balls from 3 red balls Hence, number of ways in which we can select the red balls= 3C1 + 3C2 + 3C3=23-1........(B) Hence, we can select 0 blue ball from 5 blue balls (i.e, do not select any blue ball. In this case, only black and red balls will be there)or 1 blue ball from 5 blue ballsor 2 blue balls from 5 blue ballsor 3 blue balls from 5 blue ballsor 4 blue balls from 5 blue ballsor 5 blue balls from 5 blue balls. Hence, number of ways in which we can select the blue balls= 5C0 + 5C1 + 5C2 + … + 5C5= 25..............(C) From (A), (B) and (C), required number of ways= 2524-123-1
Q: The circumference of a circular base of Cylinder is 44 cm and its hight is 15 cm. Then the volume of the cylinder is? 2577 05b5cc6ade4d2b4197774d109
5b5cc6ade4d2b4197774d109- 12759 cub. cmfalse
- 22247 cub. cmfalse
- 32614 cub. cmfalse
- 42311 cub. cmtrue
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Answer : 4. "2311 cub. cm"
Explanation :
Answer: D) 2311 cub. cm Explanation: Given Circumference of a circular base of a cylinder = 44 cm We know that Circumference of a circle = 2πr = 44⇒r = 22π Now given the height of a cylinder h = 15 cm Volume of a cylinder V = πr2h = π22π215 = 22 x 22 x 153.14 = 2311 cm3.
Q: If two fractions, each of which has a value between 0 and 1, are multiplied together, the product will be : 2577 05b5cc6cfe4d2b4197774e303
5b5cc6cfe4d2b4197774e303- 1always greater than either of the original fractionsfalse
- 2always less than either of the original fractionstrue
- 3sometimes greater and sometimes less than either of the original fractionsfalse
- 4remains the samefalse
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Answer : 2. "always less than either of the original fractions"
Explanation :
Answer: B) always less than either of the original fractions Explanation: We can easily Answer this by taking some values. The question states that the two fractions, each have values between 0 and 1.Let us say one of the fraction is 1/2 and the other fraction is 1/3 .The product of the two fractions is 1/2 x 1/3 = 1/6 . is lesser than both 1/2 and 1/3 .So, the correct answer is that the product is always less than either of the original fractions.
Q: Most important weather phenomena occur in the 2577 05b5cc6a3e4d2b4197774cc2f
5b5cc6a3e4d2b4197774cc2f- 1Tropospherefalse
- 2Stratospherefalse
- 3Ionospherefalse
- 4Thermospheretrue
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Answer : 4. "Thermosphere"
Explanation :
Answer: D) Thermosphere Explanation: Most important weather phenomena occur in the layer of Thermosphere. Most of the weather phenomenon occur in the layer of Troposphere.
Q: Size of the primary memory of a pc ranges between 2577 05b5cc694e4d2b4197774c4a2
5b5cc694e4d2b4197774c4a2- 1256 kb to 640 kbtrue
- 264 kb to 256 kbfalse
- 3256 kb to 512 kbfalse
- 42 kb to 8 kbfalse
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Answer : 1. "256 kb to 640 kb"
Explanation :
Answer: A) 256 kb to 640 kb Explanation: Size of the primary memory of a PC ranges between 256 KB to 640 KB.
Q: Assertive sentences examples list. 2575 05b5cc604e4d2b4197774b4ec
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Answer :
Explanation :
An assertive sentence is a sentence that state, assert, or declare something. It means it is a simple statement making thing. As it declares something, is also called as Declarative sentence. Examples of assertive sentence or statements :: 1. Anamika loves him very much. 2. He picks her daily. 3. Attitude is everything. 4. The sun sets in the west. 5. She likes roses. 6. He is a student. 7. Karthik planned a tour. 8. Peacock is a beautiful bird. 9. India is our country. 10. Joel want to be a doctor.
Q: If a quarter kg of carrots costs 60 paise, how many paise will 200 gms cost ? 2573 05b5cc6d7e4d2b4197774e70a
5b5cc6d7e4d2b4197774e70a- 178 paisefalse
- 248 paisetrue
- 354 paisefalse
- 462 paisefalse
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Answer : 2. "48 paise"
Explanation :
Answer: B) 48 paise Explanation: Quarter of Kg means 250 gm Less weight, less price (Direct Proportion) So, 250 : 200 :: 60 : x => x = 48 So 200 gm will cost 48 paise.
Q: In a race of 800m Kaushik gives Piyush a start of 200m and then loses the race by 20 seconds. What is the speed of Piyush and Kaushik respectively ? If the ratio of respective speeds be 3:2. 2573 05b5cc7d0e4d2b419777511f4
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Answer :
Explanation :
Let the speed of Kaushik be Sk and speed of Piyush be Sp and let the time taken by Piyush be t second then, SkSp = 800t+20600t = 23since given ratio t = 20 s Speed of Piyush = Sp = 600/20 = 30 m/s and Speed of Kaushik = 800/40 = 20 m/s

