IIT JEE Practice Question and Answer
8Q: What is the systematic name of NH4ClO3? 2453 05b5cc6aae4d2b4197774cf74
5b5cc6aae4d2b4197774cf74- 1Ammonium Chloridefalse
- 2Ammonium Chloratetrue
- 3Ammonium Chloranefalse
- 4Ammonium Chlorinefalse
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Answer : 2. "Ammonium Chlorate"
Explanation :
Answer: B) Ammonium Chlorate Explanation: In common we all call the systematic name of NH4ClO3 as Ammonium Chlorate. But originally the systematic name is azanium trioxidochlorate.
Q: Only if Sheela is happy, then she does not go to work. 2446 05b5cc761e4d2b4197774fd20
5b5cc761e4d2b4197774fd20- 1Sheela is not happy and she goes to work.true
- 2Sheela is happy and she does not go to workfalse
- 3Sheela is not happy and she does not go to work.false
- 4Sheela is happy and she goes to work.false
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Answer : 1. "Sheela is not happy and she goes to work."
Explanation :
Answer: A) Sheela is not happy and she goes to work. Explanation: The event of "Sheela is not going to work" happens only when the event "Sheela is happy" happens. Also, if the event "Sheela is happy" does not happen, then the event "Sheela is not going to work" will not happen. In other words, if it is true that Sheela is not happy, then it means that Sheela is going to work.
Q: A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 15%, he is only able to save Rs. 400 per month. What is his monthly salary ? 2444 05b5cc6e1e4d2b4197774ebf2
5b5cc6e1e4d2b4197774ebf2- 1Rs. 6000false
- 2Rs. 4500false
- 3Rs. 5000true
- 4Rs. 6500false
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Answer : 3. "Rs. 5000"
Explanation :
Answer: C) Rs. 5000 Explanation: Income = Rs. 100 Expenditure = Rs. 80 Savings = Rs. 20 Present Expenditure 80x(15/100) = Rs. 12 = 80 + 12 = Rs. 92 Present Savings = 100 – 92 = Rs. 8 100 ------ 8? --------- 400 => 5000 His salary = Rs. 5000
Q: X can complete the work in 10 days, Y can do the same in 15 days. If they are hired for 5 days to do the work together, what is the work that left unfinished? 2443 05b5cc6bfe4d2b4197774da0a
5b5cc6bfe4d2b4197774da0a- 11/3false
- 22/3false
- 31/6true
- 45/6false
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Answer : 3. "1/6"
Explanation :
Answer: C) 1/6 Explanation: Given X can do in 10 days => 1 day work of X = 1/10 Y can do in 15 days => 1 day work of Y = 1/15 1day work of (X + Y) = 1/10 + 1/15 = 1/6 Given they are hired for 5 days => 5 days work of (X + Y) = 5 x 1/6 = 5/6 Therefore, Unfinished work = 1 - 5/6 = 1/6
Q: If 15% of x = 20% of y, then x:y is ___? 2442 05b5cc6bde4d2b4197774d929
5b5cc6bde4d2b4197774d929- 14:3true
- 25:4false
- 34:5false
- 43:4false
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Answer : 1. "4:3"
Explanation :
Answer: A) 4:3 Explanation: Given 15% of x = 20% of y => 15x = 20y => x/y = 20/15 => x : y = 4 : 3
Q: The correct order of events during meiosis is 2442 05b5cc651e4d2b4197774bccb
5b5cc651e4d2b4197774bccb- 1prophase I, metaphase I, anaphase I, telophase I, cytokinesis, meiosis II.true
- 2anaphase I, telophase I, prophase I, cytokinesis, meiosis II.false
- 3cytokinesis, metaphase I, anaphase I, telophase I,false
- 4telophase I, prophase I, cytokinesis, meiosis II, anaphasefalse
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Answer : 1. "prophase I, metaphase I, anaphase I, telophase I, cytokinesis, meiosis II."
Explanation :
Answer: A) prophase I, metaphase I, anaphase I, telophase I, cytokinesis, meiosis II. Explanation: The correct order of events during meiosis is: prophase I, metaphase I, anaphase I, telophase I, cytokinesis, and meiosis II.
Q: A shopkeeper has a job to print certain number of documents and there are three machines P, Q and R for this job. P can complete the job in 3 days, Q can complete the job in 4 days and R can complete the job in 6 days. How many days the shopkeeper will it take to complete the job if all the machines are used simultaneously ? 2442 05b5cc758e4d2b4197774fbf4
5b5cc758e4d2b4197774fbf4- 14/3 daystrue
- 22 daysfalse
- 33/2 daysfalse
- 44 daysfalse
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Answer : 1. "4/3 days"
Explanation :
Answer: A) 4/3 days Explanation: Let the total number of documents to be printed be 12. The number of documents printed by P in 1 day = 4. The number of documents printed by Q in 1 day = 3. The number of documents printed by R in 1 day = 2. Thus, the total number of documents that can be printed by all the machines working simultaneously in a single day = 9. Therefore, the number of days taken to complete the whole work = 12/9 = 4/3 days.
Q: A can do a piece of work in 10 days, B in 15 days. They work together for 5 days, the rest of the work is finished by C in two more days. If they get Rs. 3000 as wages for the whole work, what are the daily wages of A, B and C respectively (in Rs): 2441 05b5cc7d0e4d2b419777511d6
5b5cc7d0e4d2b419777511d6- 1200, 250, 300false
- 2300, 200, 250true
- 3200, 300, 400false
- 4None of thesefalse
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Answer : 2. "300, 200, 250"
Explanation :
Answer: B) 300, 200, 250 Explanation: A's 5 days work = 50% B's 5 days work = 33.33% C's 2 days work = 16.66% [100- (50+33.33)] Ratio of contribution of work of A, B and C = 50 : 3313 : 1623 = 3 : 2 : 1 A's total share = Rs. 1500 B's total share = Rs. 1000 C's total share = Rs. 500 A's one day's earning = Rs.300 B's one day's earning = Rs.200 C's one day's earning = Rs.250