IIT JEE Practice Question and Answer

Q: A Conical tent was erected by the army at a base camp with height 3 m and base diameter 10 m. If every person requires 3.92 cu.m air, then how many persons can be seated in that tent approximately? 2333 0

  • 1
    20
    Correct
    Wrong
  • 2
    19
    Correct
    Wrong
  • 3
    17
    Correct
    Wrong
  • 4
    22
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 1. "20"
Explanation :

Answer: A) 20 Explanation: Given height of the conical tent = 3 m Diameter = 10 => Radius = D/2 = 10/2 = 5 m  Now, as the tent is in the conical form Volume of the conical tent = πr2h3  => (22 x 5 x 5 x 3) / (7 x 3)  = 22 x 25/7  = 78.54 cu.m  Given each person requires 3.92 cu.m of air  => Number of persons can be seated in the tent = 78.54/3.92 = 20.03 =~ 20

Q: Which day is observed as Rashtriya Ekta Diwas every year in India? 2062 0

  • 1
    31st July
    Correct
    Wrong
  • 2
    31st March
    Correct
    Wrong
  • 3
    31st January
    Correct
    Wrong
  • 4
    31st October
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 4. "31st October"
Explanation :

Answer: D) 31st October Explanation:

Q: According to a survey, which country has become the second largest smartphone market in the world? 1323 0

  • 1
    Japan
    Correct
    Wrong
  • 2
    China
    Correct
    Wrong
  • 3
    India
    Correct
    Wrong
  • 4
    USA
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 3. "India"
Explanation :

Answer: C) India Explanation: According to a Report by analyst firm Canalys, India has become the second largest smartphone market in the world.

Q: Crack the Missing Letter Puzzle? 2194 0

  • 1
    I
    Correct
    Wrong
  • 2
    K
    Correct
    Wrong
  • 3
    L
    Correct
    Wrong
  • 4
    W
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 3. "L"
Explanation :

Answer: C) L Explanation: 13 x 2 = 26 => Z (opposite side) 12 x 2 = 24 => X (opposite side) 13 x 1 = 13 => M (opposite side) 12 x 1 = 12 => L (opposite side)

Q: A boat whose speed in still water is 9 kmph, goes 12 km downstream and comes back in 3 hrs. Find the speed of the stream? 1230 0

  • 1
    1 kmph
    Correct
    Wrong
  • 2
    3 kmph
    Correct
    Wrong
  • 3
    5 kmph
    Correct
    Wrong
  • 4
    4 kmph
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 2. "3 kmph"
Explanation :

Answer: B) 3 kmph Explanation: Let the speed of the stream = x kmph   From the given data,    129+x+129-x=3 hrs 3x2 = 27   => x = 3 kmph   Therefore, the speed of the stream = 3 kmph

Q: 12 students of class IX took part in GK quiz. If the number of boys is 4 more than the number of girls. Find the number of boys and girls took part in the quiz ? 1698 0

  • 1
    7, 5
    Correct
    Wrong
  • 2
    9, 3
    Correct
    Wrong
  • 3
    8, 4
    Correct
    Wrong
  • 4
    6, 6
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 3. "8, 4"
Explanation :

Answer: C) 8, 4 Explanation: Let the number of girls = x => x + x + 4 = 12 => 2x = 8 => x = 4 => Number of girls = 4 => Number of boys = 4 + 4 = 8

Q: Social Rights will not include _____ of the following? 1553 0

  • 1
    Adivasi
    Correct
    Wrong
  • 2
    Women
    Correct
    Wrong
  • 3
    Care for Political Section
    Correct
    Wrong
  • 4
    Children
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 3. "Care for Political Section"
Explanation :

Answer: C) Care for Political Section Explanation:

Q: The solution of 3(2u + v) = 7 uv and 3(u + 3v) = 11 uv is _____ 1418 0

  • 1
    u = 1, v = 0
    Correct
    Wrong
  • 2
    u = 1, v = 3/2
    Correct
    Wrong
  • 3
    u = 0, v = 3/4
    Correct
    Wrong
  • 4
    u = 0, v = 1
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 2. "u = 1, v = 3/2"
Explanation :

Answer: B) u = 1, v = 3/2 Explanation: Using Trial and error method, From the options  u = 1, v = 3/2 satisfies both the equations.

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully