Answer: B) Monosaccharides can be classified according to the spatial arrangement of their atoms. Explanation: Monosaccharides, also called simple sugars, are the most basic units of carbohydrates. They are fundamental units of carbohydrates and cannot be further hydrolyzed to simpler compounds.   Hence, Monosaccharides can be classified according to the spatial arrangement of their atoms is true about Monosaccharides.

Answer: A) 23 Explanation: 23 chromosomes are in a human gamete. Human somatic cells have 46 chromosomes(23 pairs) but a gamete(germ cell) gets half the amount, i.e. 23 chromosomes, (one from each pair). There will be half the number of chromosomes an organism has in its somatic cells (all other body cells except gametes).   For example in humans, the somatic cells contain 46 chromosomes which are the diploid number (2n) and each sperm and egg has 23 chromosomes where one of them is the sex chromosome.

Answer: C) Jim Laker Explanation: Jim Laker was the first player to take all 10 wickets in a Test match innings. Ten for 53 in the Australians 2nd innings of the 4th Ashes Test at Old Trafford in 1956.   The only other bowler to achieve the feat is India's Anil Kumble, who took ten for 74 at Delhi's Feroz Shah Kotla against Pakistan in 1999.

Answer: D) Mitochondria Explanation: Mitochondria are present in both plant and animal cells.

11 P in a CT means 11 Players in a Cricket Team.

There are nearly about 75000 enzymes of 3 classes are there in the human body. They are : 1. Metabolic Enzymes - Enzymes that help to run our Bodies 2. Digestive Enzymes - Enzymes that help in digesting Food 3. Food Enzymes - Enzymes from raw foods that start our Food digestion.

Answer: C) 246 Explanation: A Committee of 5 persons is to be formed from 6 gentlemen and 4 ladies by taking.    (i) 1 lady out of 4 and 4 gentlemen out of 6  (ii) 2 ladies out of 4 and 3 gentlemen out of 6  (iii) 3 ladies out of 4 and 2 gentlemen out of 6  (iv) 4 ladies out of 4 and 1 gentlemen out of 6    In case I the number of ways = C14×C46 = 4 x 15 = 60  In case II the number of ways = C24×C36 = 6 x 20 = 120  In case III the number of ways = C34×C26 = 4 x 15 = 60 In case IV the number of ways = C44×C16 = 1 x 6 = 6    Hence, the required number of ways = 60 + 120 + 60 + 6 = 246

It is a Postbox or a Mailbox which contains thousands of letters or mails or messages.