IIT JEE Practice Question and Answer
8Q: Three persons A, B and C are standing in a queue. There are five persons between A and B and eight persons between B and C. If there be three persons ahead of C and 21 persons behind A, what could be the minimum number of persons in the queue? 5797 05b5cc7f2e4d2b41977751eac
5b5cc7f2e4d2b41977751eac- 141false
- 240false
- 328true
- 427false
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Answer : 3. "28"
Explanation :
Answer: C) 28 Explanation: Three persons A, B, C can be arranged in a queue in six different ways, ie ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements, ie CBA and CAB. We may consider the two cases as under: Case I: ←3C↔8B↔5A→21 Clearly, number of persons in the queue = (3+1+8+1+5+1+21=) 40 Case II: ←3C A↔5B Number of persons between A and C = (8 - 6) = 2 ∵[C↔8B A→21B] Clearly number of persons in the queue = (3+1+2+1+21) = 28 Now, 28 < 40. So, 28 is the minimum number of persons in the queue.
Q: Boy, man, uncle, fireman, grandfather are... 5783 05b5cc6dee4d2b4197774ea51
5b5cc6dee4d2b4197774ea51- 1Feminine titlesfalse
- 2Masculine titlestrue
- 3Both Feminine and Masculine titlesfalse
- 4None of the abovefalse
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Answer : 2. "Masculine titles"
Explanation :
Answer: B) Masculine titles Explanation: As they are the titles of male gender, they are called as Masculine titles.
Q: In a certain coding language, iF GO = 32 & SHE = 49 then SOME will be equal to ? 5736 05b5cc73de4d2b4197774f96d
5b5cc73de4d2b4197774f96d- 156true
- 258false
- 362false
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Answer : 1. "56"
Explanation :
Answer: A) 56 Explanation: If we count letters till the end of the alphabet including that letter in reverse order then Here the values are nothing but the values corresponding to the alphabets when taken in a reverse order,i.e,A=26 ,B=25...,Z=1G = 20 and O = 12 totaling 32S = 8, H = 19 and E = 22 totaling 49 So SOME = 8 + 12 + 14 + 22 = 56.
Q: 2 is to 55 as 6 is to 5733 05b5cc66de4d2b4197774bfe4
5b5cc66de4d2b4197774bfe4- 199true
- 244false
- 39false
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Answer : 1. "99"
Explanation :
Answer: A) 99 Explanation: Given 2 is to 55 2 + 3 = 5 5 x 11 = 55 Similarly, 6 6 + 3 = 9 9 x 11 = 99 Hence, 2 is to 55 as 6 is to 99.
Q: What is the number of digits in 333? Given that log3 = 0.47712? 5704 05b5cc7d0e4d2b41977751209
5b5cc7d0e4d2b41977751209- 112false
- 213true
- 314false
- 415false
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Answer : 2. "13"
Explanation :
Answer: B) 13 Explanation: Let Let x=333 = 333 Then, logx = 33 log3 = 27 x 0.47712 = 12.88224 Since the characteristic in the resultant value of log x is 12 ∴The number of digits in x is (12 + 1) = 13 Hence the required number of digits in 333is 13.
Q: Convent : Cloister :: Eyrie : ? 5703 05b5cc694e4d2b4197774c489
5b5cc694e4d2b4197774c489- 1Showfalse
- 2Openfalse
- 3Hidefalse
- 4Nesttrue
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Answer : 4. "Nest"
Explanation :
Answer: D) Nest Explanation: Here the first two words are synonyms. Similarly, Eyrie means a large nest. So, the synonym of Eyrie is nest. Hence, Convent : Cloister :: Eyrie : Nest.
Q: Amar can do a piece of work in 10 days. He works at it for 4 days and then Arun finishes it in 9 days. In how many days can Amar and Arun together finish the work ? 5696 05b5cc6d6e4d2b4197774e66a
5b5cc6d6e4d2b4197774e66a- 14 daysfalse
- 28 daysfalse
- 33 daysfalse
- 46 daystrue
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Answer : 4. "6 days"
Explanation :
Answer: D) 6 days Explanation: 4/10 + 9/x = 1 => x = 15 Then both can do in 1/10 + 1/15 = 1/6 => 6 days
Q: A group of 10 representatives is to be selected out of 12 seniors and 10 juniors. In how many different ways can the group be selected if it should have at least one senior ? 5674 05b5cc6eee4d2b4197774eed7
5b5cc6eee4d2b4197774eed7- 1²²C₁₀ + 1false
- 2²²C₉ + ¹⁰C₁false
- 3²²C₁₀false
- 4²²C₁₀ - 1true
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Answer : 4. "²²C₁₀ - 1"
Explanation :
Answer: D) ²²C₁₀ - 1 Explanation: The total number of ways of forming the group of ten representatives is ²²C₁₀. The total number of ways of forming the group that consists of no seniors is ¹⁰C₁₀ = 1 way The required number of ways = ²²C₁₀ - 1