IIT JEE Practice Question and Answer
8Q: A batsman in his 17th innings makes a score of 85 and their by increasing his average by 3. What is his average after the 17th innings ? 3271 05b5cc6e9e4d2b4197774ee01
5b5cc6e9e4d2b4197774ee01- 134false
- 236false
- 335false
- 437true
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Answer : 4. "37"
Explanation :
Answer: D) 37 Explanation: 16x + 85 = 17(x + 3) x = 34 + 3 = 37
Q: Find the odd one out of the following options. 3266 05b5cc6d6e4d2b4197774e679
5b5cc6d6e4d2b4197774e679- 1Sapphirefalse
- 2Rubyfalse
- 3Topazfalse
- 4Granitetrue
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Answer : 4. "Granite"
Explanation :
Answer: D) Granite Explanation: Except Granite all other options belong to the group of precious stones.
Q: 8 couples (husband and wife) attend a dance show "Nach Baliye' in a popular TV channel ; A lucky draw in which 4 persons picked up for a prize is held, then the probability that there is atleast one couple will be selected is : 3262 05b5cc7d0e4d2b41977751218
5b5cc7d0e4d2b41977751218- 18/39false
- 215/39true
- 312/13false
- 4None of thesefalse
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Answer : 2. "15/39"
Explanation :
Answer: B) 15/39 Explanation: P( selecting atleast one couple) = 1 - P(selecting none of the couples for the prize) = 1-16C1× 14C1×12C1×10C116C4=1539
Q: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m ? 3260 05b5cc6e5e4d2b4197774ed42
5b5cc6e5e4d2b4197774ed42- 1127.5 mtrue
- 2254 mfalse
- 3184 mfalse
- 4212 mfalse
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Answer : 1. "127.5 m"
Explanation :
Answer: A) 127.5 m Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = (600 x 212.5)/1000 = 127.5 m.
Q: If NAMO = 172 and OM = 56 then, SHIVAY = ? 3256 05b5cc6cee4d2b4197774e237
5b5cc6cee4d2b4197774e237- 1606false
- 2415false
- 3504true
- 4404false
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Answer : 3. "504"
Explanation :
Answer: C) 504 Explanation: (COUNTING OF LETTERS) NAMO = 14 + 1 + 13 + 15 = 43 x 4 = 172, OM = 15 + 13 = 28 x 2 = 56, SHIVAY = 19 + 8 + 9 + 22 + 1 + 25 = 84 x 6 = 504
Q: From the following pairs, find the one which is correctly matched? 3250 05b5cc6bee4d2b4197774d960
5b5cc6bee4d2b4197774d960- 1Scurvy- Thiaminefalse
- 2Tuberculosis- ATSfalse
- 3Tetanus- BCGfalse
- 4Malaria- Chloroquinetrue
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Answer : 4. "Malaria- Chloroquine"
Explanation :
Answer: D) Malaria- Chloroquine Explanation: Chloroquine is a medication used to prevent and to treat malaria.
Q: The wildcard in a WHERE clause is useful when 3250 05b5cc65ee4d2b4197774be3b
5b5cc65ee4d2b4197774be3b- 1An exact match is not possible in a SELECT statement.true
- 2An exact match is necessary in a CREATE statement.false
- 3An exact match is not possible in a CREATE statement.false
- 4An exact match is necessary in a SELECT statement.false
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Answer : 1. "An exact match is not possible in a SELECT statement."
Explanation :
Answer: A) An exact match is not possible in a SELECT statement. Explanation:
Q: Which statement best describes an O3 molecule? 3249 05b5cc6b3e4d2b4197774d432
5b5cc6b3e4d2b4197774d432- 1The double bond in ozone switches back and forth between the two outer oxygen atomsfalse
- 2An ozone molecule contains one single bond and one double bondtrue
- 3Each atom in ozone is connected to another atom by 1.5 bonds.false
- 4Nonefalse
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Answer : 2. "An ozone molecule contains one single bond and one double bond"
Explanation :
Answer: B) An ozone molecule contains one single bond and one double bond Explanation: Ozone molecule has one single bond and one double bond.