IIT JEE Practice Question and Answer
8Q: Happiness is to 517768399 as senipah is to 3341 05b5cc64de4d2b4197774bc57
5b5cc64de4d2b4197774bc57- 19836715false
- 29386615false
- 39386715true
- 49386517false
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Answer : 3. "9386715"
Explanation :
Answer: C) 9386715 Explanation: If each consecutive letter in "happiness" relates to the consecutive numbers in 517768399, then H=5, A=1, P=7, I=6, N=8, E=3 and S=9. Using the numbers that relate to the letters in 'senipah', you will arrive at SENIPAH = 9386715. Hence, Happiness is to 517768399 as senipah is to 9386715.
Q: The shadow zone exists because 3341 05b5cc607e4d2b4197774b55d
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Answer :
Explanation :
The shadow zone is the area of the earth from angular distances of 104 to 140 degrees from a given earthquake that does not receive any direct P waves. The shadow zone results from S waves being stopped entirely by the liquid core and P waves being bent (refracted) by the liquid core. There are two types of Shadow zones: one for P waves and one for S waves. P wave shadows between 104-140 degree, both sides; S wave shadow from 105 of one side to 105 of the other.
Q: Tract of land used for raising crops or livestock. 3340 05b5cc683e4d2b4197774c283
5b5cc683e4d2b4197774c283- 1A fieldfalse
- 2A farmfalse
- 3Both A & Btrue
- 4None of the abovefalse
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Answer : 3. "Both A & B"
Explanation :
Answer: C) Both A & B Explanation: A tract of land used for raising crops or livestockcan be called a field or a farm.
Q: Why are yeast cells frequently used as hosts for cloning? 3339 05b5cc690e4d2b4197774c438
5b5cc690e4d2b4197774c438- 1they are eukaryotic cellstrue
- 2they do not have plasmidsfalse
- 3only yeast cells allow the gene to be clonedfalse
- 4they easily form coloniesfalse
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Answer : 1. "they are eukaryotic cells"
Explanation :
Answer: A) they are eukaryotic cells Explanation: If you were to produce a protein in bacterial cloning systems, you would not get the same post transcriptional and post translational modifications because the prokaryotic and eukaryotic systems work differently on the modifications. Thus human recombinant protein genes are usually cloned in yeast cells. Also since they have a short generation time, they can be easily culture.
Q: Select the correct statement about cellular respiration? 3334 05b5cc6a3e4d2b4197774cc34
5b5cc6a3e4d2b4197774cc34- 1All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide moleculetrue
- 2All the carbon atoms in glucose ultimately incorporated during cellular respiration into NADH moleculefalse
- 3All the carbon atoms in glucose ultimately incorporated during cellular respiration into ATP moleculefalse
- 4All the carbon atoms in glucose ultimately incorporated during cellular respiration into water moleculefalse
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Answer : 1. "All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecule"
Explanation :
Answer: A) All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecule Explanation: All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecules.
Q: Paw : Cat :: Hoof : ? 3334 05b5cc75ce4d2b4197774fc66
5b5cc75ce4d2b4197774fc66- 1Donkeyfalse
- 2Lionfalse
- 3Elephantfalse
- 4Horsetrue
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Answer : 4. "Horse"
Explanation :
Answer: D) Horse Explanation: The cat's foot is called a paw. The horse's foot is called a hoof.
Q: The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8,748, its purchase price was ? 3329 05b5cc75ce4d2b4197774fc2f
5b5cc75ce4d2b4197774fc2f- 1Rs.14,000false
- 2Rs.12,000true
- 3Rs. 12,800false
- 4Rs. 15,000false
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Answer : 2. "Rs.12,000"
Explanation :
Answer: B) Rs.12,000 Explanation: We have P = 8748, R = -10 and n = 3Therefore, the purchase price of the machine= P1+R100n= 87481-101003= 8748 x (100/90) x (100/90) x (100/90)= 12,000. Therefore, the purchase price of the machine was Rs. 12,000.
Q: In an election between two candidates K and L, the number of valid votes received by K exceeds those received by L by 15% of the total number of votes polled. If 20% of the votes polled were invalid and a total of 8720 votes were polled, then how many valid votes did L get ? 3323 05b5cc6d7e4d2b4197774e6fb
5b5cc6d7e4d2b4197774e6fb- 13241false
- 22457false
- 32642false
- 42834true
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Answer : 4. "2834"
Explanation :
Answer: D) 2834 Explanation: Let the total number of votes polled in the election be 100k.Number of valid votes = 100k - 20% (100k) = 80kLet the number of votes polled in favour of K and L be a and b respectively.a - b = 15% (100k) => a = b + 15k=> a + b = b + 15k + bNow, 2b + 15k = 80k and hence b = 32.5kIt is given that 100k = 872032.5k = 32.5k/100k x 8720 = 2834 The number of valid votes polled in favour of L is 2834.

