IIT JEE Practice Question and Answer
8Q: Why are yeast cells frequently used as hosts for cloning? 3122 05b5cc690e4d2b4197774c438
5b5cc690e4d2b4197774c438- 1they are eukaryotic cellstrue
- 2they do not have plasmidsfalse
- 3only yeast cells allow the gene to be clonedfalse
- 4they easily form coloniesfalse
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Answer : 1. "they are eukaryotic cells"
Explanation :
Answer: A) they are eukaryotic cells Explanation: If you were to produce a protein in bacterial cloning systems, you would not get the same post transcriptional and post translational modifications because the prokaryotic and eukaryotic systems work differently on the modifications. Thus human recombinant protein genes are usually cloned in yeast cells. Also since they have a short generation time, they can be easily culture.
Q: A does half as much work as Band C does half as much work as A and B together. If C alone can finish the work in 40 days, then together ,all will finish the work in ? 3120 05b5cc728e4d2b4197774f714
5b5cc728e4d2b4197774f714- 117 + 4/7 daysfalse
- 213 + 1/3 daystrue
- 315 + 3/2 daysfalse
- 416 daysfalse
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Answer : 2. "13 + 1/3 days"
Explanation :
Answer: B) 13 + 1/3 days Explanation: C alone can finish the work in 40 days.As given C does half as much work as A and B together => (A + B) can do it in 20 days(A + B)s 1 days wok = 1/20.A's 1 days work : B's 1 days Work = 1/2 : 1 = 1:2(given)A's 1 day’s work = (1/20) x (1/3) = (1/60) [Divide 1/20 in the raio 1:2]B's 1 days work = (1/20) x (2/3) = 1/30(A+B+C)'s 1 day's work = (1/60) + (1/30) + (1/40) = 9/120 = 3/40 All the three together will finish it in 40/3 = 13 and 1/3 days.
Q: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ? 3119 05b5cc74fe4d2b4197774fb35
5b5cc74fe4d2b4197774fb35- 1145false
- 2165false
- 3175true
- 4135false
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Answer : 3. "175"
Explanation :
Answer: C) 175 Explanation: Given that, working days = 5 working hours = 8 A man get rupess per hour is Rs.2.40 So in one day the man get total rupees is 2.40 x 8 = 19.2 So in 5 days week the man get total rupees is 19.2 x 5 = 96 So in 4 week the man get total rupees is 96 x 4 = 384 So the man worked for = 160hours in 4 weeks But given that the man earned Rs.432 Hence remaning money is (432-384 = 48)which is earn by doing overtime work Overtime hours = 48/3.20 = 15 So total worked hours is = 15 + 160 = 175.
Q: Which pair of atoms has the highest electronegativity difference? (Calcium's electronegativity is 1.0 Fluorine's electronegativity is 4.0 Hydrogen's electronegativity is 2.2 Sodium's electronegativity is 0.93) 3118 05b5cc669e4d2b4197774bf7c
5b5cc669e4d2b4197774bf7c- 1F-Ffalse
- 2Ca-Ffalse
- 3H-Ffalse
- 4Na-Ftrue
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Answer : 4. "Na-F"
Explanation :
Answer: D) Na-F Explanation: F-F = 4 - 4 = 0 Ca-F = 4 - 1 = 3.0 H-F = 4 - 2.2 = 1.8 Na-F = 4 - 0.93 = 3.07 Hence, the highest electronegativity difference is in Na-F.
Q: A person sold two cows each for Rs.9900. If he gained 10% on one and lost 20% on the other, then which of the following is true ? 3116 05b5cc6dde4d2b4197774e9e2
5b5cc6dde4d2b4197774e9e2- 1He lost Rs. 200false
- 2He gained Rs. 200false
- 3Neither he gained nor lostfalse
- 4None of the abovetrue
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Answer : 4. "None of the above"
Explanation :
Answer: D) None of the above Explanation: In first he got Rs. 990 But in second he lost Rs. 1980 So he lost Rs. 990.
Q: __________ cookies are also known as transient cookies. 3114 55b5cc6c4e4d2b4197774dc95
5b5cc6c4e4d2b4197774dc95- 1Persistentfalse
- 2Second partyfalse
- 3Sessiontrue
- 4Third partyfalse
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Answer : 3. "Session"
Explanation :
Answer: C) Session Explanation:
Q: P and Q were assigned to do a work for an amount of 1200. P alone can do it in 15 days while Q can do it in 12 days. With the help of R they finish the work in 6 days. Find the share of R ? 3114 05b5cc731e4d2b4197774f814
5b5cc731e4d2b4197774f814- 1120true
- 2240false
- 3360false
- 4180false
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Answer : 1. "120"
Explanation :
Answer: A) 120 Explanation: 1/15 + 1/12 + 1/R = 1/6, we got R = 60 (it means R will take 60 days to complete the work alone) so ratio of work done by P:Q:R = 1/15 : 1/12 : 1/60 = 5 : 4 : 1 so R share = (1/10) x 1200 = 120.
Q: Equal quantities of three mixtures of milk and water are mixed in the ratio 1:2, 2:3 and 3:4. The ratio of water and milk in the mixture is ? 3111 05b5cc73ae4d2b4197774f8c9
5b5cc73ae4d2b4197774f8c9- 1193 : 122true
- 297 : 102false
- 3115 : 201false
- 4147 : 185false
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Answer : 1. "193 : 122"
Explanation :
Answer: A) 193 : 122 Explanation: Given the three mixtures ratio as (1:2),(2:3),(3:4) (1+2),(2+3),(3+4) Total content = 3,5,7 Given equal quantities of the three mixtures are mixed, then LCM of 3, 5, 7 = 105 105/3 = 35 , 105/5 = 21 , 105/7 = 15 Now, the individual equal quantity ratios are (35x1, 35x2), (21x2, 21x3), (15x3, 15x4) i.e (35,70), (42,63), (45,60) So overall mixture ratio of milk and water is 35+42+45 : 70+63+60 122:193 But in the question asked the ratio of water to milk = 193 : 122