IIT JEE Practice Question and Answer
8 Q: 18 H on GC?
$$6 {4\over 9}$$ % ..???kkk
3786 05b5cc607e4d2b4197774b533
5b5cc607e4d2b4197774b533- 1sstrue
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Answer : 1. "ss"
Explanation :
The given letters equation states that 18 H on a GC means 18 Holes on a Golf Course.
Q: _ tu _ rt _ s _ _ usrtu _ 3785 05b5cc6d9e4d2b4197774e843
5b5cc6d9e4d2b4197774e843- 1rsutrrfalse
- 2rsurtrfalse
- 3rsurtstrue
- 4rtusrufalse
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Answer : 3. "rsurts"
Explanation :
Answer: C) rsurts Explanation: The series rtus/rtus/rtus/rtus. Thus, the pattern 'rtus' is repeated.
Q: A merchant buys two articles for Rs.600. He sells one of them at a profit of 22% and the other at a loss of 8% and makes no profit or loss in the end. What is the selling price of the article that he sold at a loss ? 3776 05b5cc71be4d2b4197774f4fe
5b5cc71be4d2b4197774f4fe- 1Rs. 404.80true
- 2Rs. 536.80false
- 3Rs.440false
- 4Rs. 160false
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Answer : 1. "Rs. 404.80"
Explanation :
Answer: A) Rs. 404.80 Explanation: Let C1 be the cost price of the first article and C2 be the cost price of the second article.Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%. We know, C1 + C2 = 600.The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2. The total selling price of the first and second article = 1.22C1 + 0.92C2. As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2. Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get1.22C1 + 0.92(600 - C1) = 600or 1.22C1 - 0.92C1 = 600 - 0.92*600or 0.3C1 = 0.08*600 = 48or C1 = 48/(0.3) = 160.If C1 = 160, then C2 = 600 - 160 = 440.The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.
Q: From the following pairs, find the one which is correctly matched? 3767 05b5cc6bee4d2b4197774d960
5b5cc6bee4d2b4197774d960- 1Scurvy- Thiaminefalse
- 2Tuberculosis- ATSfalse
- 3Tetanus- BCGfalse
- 4Malaria- Chloroquinetrue
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Answer : 4. "Malaria- Chloroquine"
Explanation :
Answer: D) Malaria- Chloroquine Explanation: Chloroquine is a medication used to prevent and to treat malaria.
Q: P and Q can complete a job in 24 days working together. P alone can complete it in 32 days. Both of them worked together for 8 days and then P left. The number of days Q will take to complete the remaining work is ? 3754 05b5cc6c0e4d2b4197774db05
5b5cc6c0e4d2b4197774db05- 156 daysfalse
- 254 daysfalse
- 360 daysfalse
- 464 daystrue
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Answer : 4. "64 days"
Explanation :
Answer: D) 64 days Explanation: (P+Q)'s 1 day work = 1/24 P's 1 day work = 1/32 => Q's 1 day work = 1/24 - 1/32 = 1/96 Work done by (P+Q) in 8 days = 8/24 = 1/3 Remainining work = 1 - 1/3 = 2/3 Time taken by Q to complete the remaining work = 2/3 x 96 = 64 days.
Q: Find the odd one out of the following number series? 9 5 6 14 56 488 3750 05b5cc66de4d2b4197774bfb0
5b5cc66de4d2b4197774bfb0- 156true
- 26false
- 314false
- 45false
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Answer : 1. "56"
Explanation :
Answer: A) 56 Explanation: The given number series follows a pattern that, 9 9 x 0.5 + 0.5 = 5 5 x 1 + 1 = 6 6 x 2 + 2 = 14 14 x 4 + 4 = 60 (not equals to 56) 60 x 8 + 8 = 488. Hence, the odd one in the given number series is 56.
Q: Paw : Cat :: Hoof : ? 3749 05b5cc75ce4d2b4197774fc66
5b5cc75ce4d2b4197774fc66- 1Donkeyfalse
- 2Lionfalse
- 3Elephantfalse
- 4Horsetrue
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Answer : 4. "Horse"
Explanation :
Answer: D) Horse Explanation: The cat's foot is called a paw. The horse's foot is called a hoof.
Q: __________ cookies are also known as transient cookies. 3747 55b5cc6c4e4d2b4197774dc95
5b5cc6c4e4d2b4197774dc95- 1Persistentfalse
- 2Second partyfalse
- 3Sessiontrue
- 4Third partyfalse
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Answer : 3. "Session"
Explanation :
Answer: C) Session Explanation:

