IIT JEE Practice Question and Answer
8Q: Ram and Raj start a business with investments of Rs. 2500 and Rs. 2250 respectively. After 2 months, Ram takes out Rs.1250 from his capital. After 1 more month, Raj takes out Rs.750 of his capital while Rakesh joins them with a capital of Rs. 3500. At the end of 6 months, they earn a profit of Rs. 2540. Which of the following is the share of each member in the profit ? 3065 05b5cc72ce4d2b4197774f783
5b5cc72ce4d2b4197774f783- 1Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 840true
- 2Ram - Rs. 900, Raj - Rs. 800, Rakesh - Rs. 840false
- 3Ram - Rs. 840, Raj - Rs. 920, Rakesh - Rs. 840false
- 4Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 940false
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Answer : 1. "Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 840"
Explanation :
Answer: A) Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 840 Explanation: Initial investment of Ram = Rs.2500.After 2 months he withdraw Rs.1250 from his capital.Therefore, we have, Ram invested Rs.2500 for 2 months and Rs.(2500-1250=) 1250 for 4 months. Raj invested Rs. 2250 for 3 months and Rs.(2250-750=) 1500 for 3 months. And, Rakesh invested Rs.3500 for 3 months; Their investing ratio:Ram:Raj:Rakesh = (2500x2 + 1250x4):(2250x3 + 1500x3):(3500x3)= (10,000):(11,250):(10,500) = 1000:1125:1050 = 40:45:42 Total profit for 6 months = Rs.2540Therefore, Ram's share = Rs.(2540 x 40/(40+45+42)) = Rs.(2540 x 40/127) = Rs.800Raj's share = Rs.(2540 x 45/127) = Rs.900Rakesh's share = Rs.(2540 x 42/127) = Rs.840
Q: What is the next number of the following sequence ? 21, 77, 165, 285, ...... 3062 05b5cc74ae4d2b4197774fab8
5b5cc74ae4d2b4197774fab8- 1404false
- 2415false
- 3426false
- 4437true
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Answer : 4. "437"
Explanation :
Answer: D) 437 Explanation: The series follow the rule, 21 = 77 = 92-4165 = 132-4285 = 172-4 5,9,13,17,21,(+4)...In the same way next no. will be 212-4 = 441 - 4 = 437
Q: A bird lover was asked how many birds he had in the basket. He replied that there were all parrots but six, all pigeons but six, and all koel but six. How many birds he had in the basket in all ? 3059 05b5cc71ee4d2b4197774f5a9
5b5cc71ee4d2b4197774f5a9- 18false
- 218false
- 39true
- 410false
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Answer : 3. "9"
Explanation :
Answer: C) 9 Explanation: There were all parrots but six means that six birds were not parrots but only pigeons and koels. Similarly, number of parrots + number of koels = 6 and number of parrots + number of pigeons = 6. This is possible when there are 3 parrots, 3 pigeons and 3 koels i.e. 9 birds in all.
Q: In these series, you will be looking at both the letter pattern and the number pattern. Fill the blank in the middle of the series or end of the series.SCD, TEF, UGH, ____, WKL 3048 05b5cc720e4d2b4197774f609
5b5cc720e4d2b4197774f609- 1UJIfalse
- 2VIJtrue
- 3XLMfalse
- 4DOPfalse
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Answer : 2. "VIJ"
Explanation :
Answer: B) VIJ Explanation: First letter series S,T,U,Vsecond and third letter series CD,EF,GH,IJ...so answer = VIJ
Q: If 34 men completed 2/5th of a work in 8 days working 9 hours a day. How many more man should be engaged to finish the rest of the work in 6 days working 9 hours a day ? 3045 05b5cc6d9e4d2b4197774e807
5b5cc6d9e4d2b4197774e807- 1101 menfalse
- 2112 menfalse
- 3102 mentrue
- 4120 menfalse
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Answer : 3. "102 men"
Explanation :
Answer: C) 102 men Explanation: From the above formula i.e (m1 x t1/w1) = (m2 x t2/w2) so, [(34 x 8 x 9)/(2/5)] = [(M x 6 x 9)/(3/5)] so, M = 136 men Number of men to be added to finish the work = 136-34 = 102 men.
Q: स्मृति से बनी होती है 3042 15b5cc651e4d2b4197774bd14
5b5cc651e4d2b4197774bd14- 1कोशिकाओं की बड़ी संख्याtrue
- 2तारों का सेटfalse
- 3सर्किट का सेटfalse
- 4इनमे से कोई भी नहींfalse
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Answer : 1. "कोशिकाओं की बड़ी संख्या"
Explanation :
Answer: A) बड़ी संख्या में सेल स्पष्टीकरण: कंप्यूटिंग में, मेमोरी कंप्यूटर हार्डवेयर एकीकृत सर्किट को संदर्भित करता है जो कंप्यूटर में तत्काल उपयोग के लिए जानकारी संग्रहीत करता है। अधिकांश सेमीकंडक्टर मेमोरी को मेमोरी सेल या बिस्टेबल फ्लिप-फ्लॉप में व्यवस्थित किया जाता है, प्रत्येक एक बिट (0 या 1) को स्टोर करता है।
Q: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ? 3038 05b5cc6dce4d2b4197774e960
5b5cc6dce4d2b4197774e960- 15:3false
- 21:4false
- 34:1false
- 49:1true
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Answer : 4. "9:1"
Explanation :
Answer: D) 9:1 Explanation: Milk = 3/5 x 20 = 12 liters, water = 8 liters If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters. Remaining milk = 12 - 6 = 6 liters Remaining water = 8 - 4 = 4 liters 10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters. The ratio of milk and water in the new mixture = 16:4 = 4:1 If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 x 10 = 8 liters. Amount of water removed = 2 liters. Remaining milk = (16 - 8) = 8 liters. Remaining water = (4 -2) = 2 liters. Now 10 lts milk is added => total milk = 18 lts The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
Q: What grows when it eats but dies when it drinks? 3038 05b5cc64de4d2b4197774bcac
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Answer :
Explanation :
A fire grows when it eats but dies when it drinks.