IIT JEE Practice Question and Answer
8Q: A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's husband age is ? 2858 05b5cc720e4d2b4197774f613
5b5cc720e4d2b4197774f613- 145false
- 224false
- 342false
- 454true
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Answer : 4. "54"
Explanation :
Answer: D) 54 Explanation: By trial and error method from the given options, as 54 - 45 = (1/11) x (45+54) = 99/11 = 9 Hence this satisfies the given conditions. Then the woman's husband age is 54.
Q: Ratio of the ages of Mahesh and Nilesh is 5 : x. Mahesh is 18 years younger to Ramesh. After nine years Ramesh will be 47 years old. If the difference between the ages of Mahesh and Nilesh is same as the age of Ramesh, what is the value of x ? 2855 05b5cc6dce4d2b4197774e9bf
5b5cc6dce4d2b4197774e9bf- 111.8false
- 212.9false
- 313.7false
- 414.5true
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Answer : 4. "14.5"
Explanation :
Answer: D) 14.5 Explanation: Let the present ages of Mahesh, Nilesh and Ramesh be k, l and m respectively.k/l = 5/x ------ (1)k = m - 18 ------ (2)m + 9 = 47 ------ (3)k - l = m ----- (4)(3) => m = 47 - 9 = 38 years(2) => k = 38 -18 = 20 years(1) => 20/l = 5/x => l = 4x(4) => 4x - 20 = 38=> 4x = 58 => x = 14.5
Q: Which type of memory is not directly addressable by the CPU and requires special software called EMS ? 2855 25b5cc6c0e4d2b4197774dadf
5b5cc6c0e4d2b4197774dadf- 1Expandedtrue
- 2Basefalse
- 3Conventionalfalse
- 4Nonefalse
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Answer : 1. "Expanded"
Explanation :
Answer: A) Expanded Explanation:
Q: Programs stored in ROM are called 2850 15b5cc6a9e4d2b4197774ceef
5b5cc6a9e4d2b4197774ceef- 1Hardwarefalse
- 2Firmwaretrue
- 3Freewarefalse
- 4Softwarefalse
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Answer : 2. "Firmware"
Explanation :
Answer: B) Firmware Explanation: The programs which are as permanent as hardware and stored in ROM are known as Firmware. Data stored in ROM can only be modified slowly, with difficulty, or not at all, so it is mainly used to store firmware (software that is closely tied to specific hardware, and unlikely to need frequent updates) or application software in plug-in cartridges.
Q: A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement ? 2849 05b5cc6e7e4d2b4197774edb0
5b5cc6e7e4d2b4197774edb0- 11900true
- 22100false
- 31700false
- 42000false
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Answer : 1. "1900"
Explanation :
Answer: A) 1900 Explanation: Given 2000 ---- 54 days The provisions for 2000 men for 39 days can be completed by 'm' men for only 20 days. i.e, 2000 ----- 39 days == m ---- 20 days => m x 20 = 2000 x 39 m = 3900 So total men for 20 days is 3900 => 2000 old and 1900 new reinforcement. Hence, reinforcement = 1900.
Q: Find the odd man out in the following number series? 5, 4, 9, 32, 273 2846 05b5cc695e4d2b4197774c500
5b5cc695e4d2b4197774c500- 14false
- 29false
- 332true
- 4273false
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Answer : 3. "32"
Explanation :
Answer: C) 32 Explanation: The given number series follows 5, 4, 9, 32, 308 pattern that 5 5 x 1 - 1 = 4 4 x 3 - 3 = 9 9 x 5 - 5 = 40 (not equals to 32) 40 x 7 - 7 = 273 Hence, the odd man in the given number series is 32.
Q: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ? 2844 05b5cc6dce4d2b4197774e960
5b5cc6dce4d2b4197774e960- 15:3false
- 21:4false
- 34:1false
- 49:1true
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Answer : 4. "9:1"
Explanation :
Answer: D) 9:1 Explanation: Milk = 3/5 x 20 = 12 liters, water = 8 liters If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters. Remaining milk = 12 - 6 = 6 liters Remaining water = 8 - 4 = 4 liters 10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters. The ratio of milk and water in the new mixture = 16:4 = 4:1 If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 x 10 = 8 liters. Amount of water removed = 2 liters. Remaining milk = (16 - 8) = 8 liters. Remaining water = (4 -2) = 2 liters. Now 10 lts milk is added => total milk = 18 lts The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
Q: Which veda deals with medicine? 2841 05b5cc662e4d2b4197774be75
5b5cc662e4d2b4197774be75- 1Atharva Vedatrue
- 2Yajur Vedafalse
- 3Sama Vedafalse
- 4Rig Vedafalse
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Answer : 1. "Atharva Veda"
Explanation :
Answer: A) Atharva Veda Explanation: The Vedas are considered the earliest literary record of Indo-Aryan civilization. It is the most sacred scriptures of India. There are four Vedas in Hinduism. They are: 1. The Rig Veda, 2. Sama Veda, 3. Yajur Veda and 4. Atharva Veda. Most ailments, both physical and mental, were attributed to malevolent spirits and cures consisted of rituals, charms, mantras, medicines and surgical intervention. The hymns in the Atharva Veda, the last of the four Vedas, and largely composed after the Aryans were well settled in the sub-continent, indicate that indigenous non-Aryan healing practices had influenced the Vedic Aryan healers.