IIT JEE Practice Question and Answer
8Q: The ages of Anushka, Kajal and Charu latha together are 57 years. Bharti is thrice as old as Anushka and Charu latha is 12 years older than Anushka. Then, the respective age of Anushka, Kajal and Charu latha is ? 3125 05b5cc741e4d2b4197774f9b8
5b5cc741e4d2b4197774f9b8- 127, 9, 21false
- 29, 21, 27false
- 321, 27, 9false
- 49, 27, 21true
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Answer : 4. "9, 27, 21"
Explanation :
Answer: D) 9, 27, 21 Explanation: Let Anushka age = XCharu latha 12 yrs older than Anushka so Charu latha age = x+12Kajal is thrice as old as Anushka so Kajal age = 3xThe ages of Anushka, Kajal and Charu latha together are 57 yearsi.e x + (x+12) + 3x = 57=> 5x = 45:- x = 9Anushka age = 9Kajal age = 3x = 27Charu latha age = x+12 = 21
Q: Find the odd one out of the floowing number series? 270, 261, 279, 252, 289, 243 3124 05b5cc639e4d2b4197774ba8c
5b5cc639e4d2b4197774ba8c- 1270false
- 2279false
- 3289true
- 4243false
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Answer : 3. "289"
Explanation :
Answer: C) 289 Explanation: Here the given number series is 270, 261, 279, 252, 289, 243 270 - 9 = 261 261 + 18 = 279 279 - 27 = 252 252 + 36 = 288 (not equals to 289) 288 - 45 = 243 Hence, the odd number in the given number series is 289.
Q: A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement ? 3123 05b5cc6e7e4d2b4197774edb0
5b5cc6e7e4d2b4197774edb0- 11900true
- 22100false
- 31700false
- 42000false
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Answer : 1. "1900"
Explanation :
Answer: A) 1900 Explanation: Given 2000 ---- 54 days The provisions for 2000 men for 39 days can be completed by 'm' men for only 20 days. i.e, 2000 ----- 39 days == m ---- 20 days => m x 20 = 2000 x 39 m = 3900 So total men for 20 days is 3900 => 2000 old and 1900 new reinforcement. Hence, reinforcement = 1900.
Q: What will come in place of question mark(?) in the following number series ? 6859 5832 ? 4096 3375 3120 05b5cc6c0e4d2b4197774db1e
5b5cc6c0e4d2b4197774db1e- 14589false
- 24913true
- 35013false
- 45169false
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Answer : 2. "4913"
Explanation :
Answer: B) 4913 Explanation: The given series follows a pattern that, 19 x 19 x 19 = 6859 18 x 18 x 18 = 5832 17 x 17 x 17 = 4913 16 x 16 x 16 = 4096 15 x 15 x 15 = 3375 So, the missing number in the given series = 4913
Q: Sum of the ages of Rajesh, Suresh, Mahesh and Dinesh is 76 years. 7 years hence, their age ratio is 7:6:5:8. Find Mahesh’s present age ? 3119 05b5cc6c2e4d2b4197774dba5
5b5cc6c2e4d2b4197774dba5- 117 yearsfalse
- 213 yearstrue
- 314 yearsfalse
- 416 yearsfalse
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Answer : 2. "13 years"
Explanation :
Answer: B) 13 years Explanation: Given R + S + M + D = 76 => R+7 : S+7 : M+7 : D+7 = 7:6:5:8 => Let the ratio = x => M+7 = 5x => M = 5x-7 => R = 7x-7 => S = 6x-7 => D = 8x-7 => R + S + M + D = 76 => 7x-7 + 6x-7 + 5x-7 + 8x-7 = 76 => 26x - 28 = 76 => 26x = 104 => x = 4 => Mahesh's present age = 5x-7 = 20 - 7 = 13 years.
Q: Three men, four women and six children can complete a work in 9 days. A women does double the work a man does and a child does half the work a man does. How many women alone can complete this work in 9 days? 3113 05b5cc6b2e4d2b4197774d374
5b5cc6b2e4d2b4197774d374- 17true
- 28false
- 39false
- 46false
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Answer : 1. "7"
Explanation :
Answer: A) 7 Explanation: Given (3 Men + 4 Women + 6 Children) -----> 9 days But W = 2M and C = M/2 Now, convert Men and Children into Women by 3W2 + 4W + 6W4=> 32 + 4 + 32 = 7 Women Therefore, 7 women alone can complete this work in 9 days.
Q: How many parallelograms will be formed if 7 parallel horizontal lines intersect 6 parallel vertical lines? 3112 05b5cc754e4d2b4197774fbb4
5b5cc754e4d2b4197774fbb4- 1215false
- 2315true
- 3415false
- 4115false
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Answer : 2. "315"
Explanation :
Answer: B) 315 Explanation: Parallelograms are formed when any two pairs of parallel lines (where each pair is not parallel to the other pair) intersect. Hence, the given problem can be considered as selecting pairs of lines from the given 2 sets of parallel lines. Therefore, the total number of parallelograms formed = 7C2 x 6C2 = 315
Q: What holds the sides of the DNA ladder together? 3104 05b5cc69ae4d2b4197774c78c
5b5cc69ae4d2b4197774c78c- 1Polar covalent bondsfalse
- 2Ionic bondsfalse
- 3Metallic bondsfalse
- 4Covalent bondstrue
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Answer : 4. "Covalent bonds"
Explanation :
Answer: D) Covalent bonds Explanation: Deoxyribose, which is a pentose, and a phosphate group are the two molecules together form the two sides of the DNA i.e, A sugar (deoxyribose) and a phosphate. DNA is a double-stranded molecule twisted into a helix (think of a spiral staircase). Each spiraling strand, comprised of a sugar-phosphate backbone and attached bases, is connected to a complementary strand by non-covalent hydrogen bonding between paired bases. The bases are adenine (A), thymine (T), cytosine (C) and guanine (G). A and T are connected by two hydrogen bonds. G and C are connected by three hydrogen bonds.

