IIT JEE Practice Question and Answer
8Q: If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ? 2836 15b5cc761e4d2b4197774fd67
5b5cc761e4d2b4197774fd67- 11false
- 22true
- 34false
- 48false
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Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: Given a2 + b2 = c2 Now 1logc+ab + 1logc-ab = logbc+a + logbc-a = logbc2-a2 = 2logbb = 2
Q: In what time will Rs. 3300 becomes Rs. 3399 at 6% per annum interest compounded half-yearly ? 2835 05b5cc701e4d2b4197774f175
5b5cc701e4d2b4197774f175- 1Quarter monthsfalse
- 2Half yeartrue
- 32 yearsfalse
- 41 yearfalse
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Answer : 2. "Half year"
Explanation :
Answer: B) Half year Explanation: 3300 ----- 3% ↑ (1st time interval, 99) → 3399. Here, time interval is given as half-yearly i.e. 6 months.
Q: 18 H on GC?
$$6 {4\over 9}$$ % ..???kkk
2835 05b5cc607e4d2b4197774b533
5b5cc607e4d2b4197774b533- 1sstrue
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Answer : 1. "ss"
Explanation :
The given letters equation states that 18 H on a GC means 18 Holes on a Golf Course.
Q: Choose the antonym of the word given from the following options ? MUNDANE 2835 05b5cc75ce4d2b4197774fc52
5b5cc75ce4d2b4197774fc52- 1Extraordinarytrue
- 2Regularfalse
- 3Visionaryfalse
- 4Routinefalse
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Answer : 1. "Extraordinary"
Explanation :
Answer: A) Extraordinary Explanation:
Q: At a certain rate of interest the compound interest of 3 years and simple interest of 5 years for certain sum of money is respectively Rs. 1513.2 and Rs. 2400. Find the common rate of interest per annum ? 2828 05b5cc6cde4d2b4197774e1cc
5b5cc6cde4d2b4197774e1cc- 15%true
- 26%false
- 34%false
- 43%false
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Answer : 1. "5%"
Explanation :
Answer: A) 5% Explanation: Given compound interest for 3 years = Rs. 1513.2 and simple interest for 5 years = Rs. 2400 Now, we know that C.I = P1+R100n - 1 => 1513.2 = P1+R1003 - 1 ...........(A) And S.I = PTR/100 => 2400 = P5R/100 ..................(B) By solving (A) & (B), we get R = 5%.
Q: Simplify the following : 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 ? 2826 05b5cc6cae4d2b4197774dffc
5b5cc6cae4d2b4197774dffc- 1100true
- 21false
- 34false
- 40false
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Answer : 1. "100"
Explanation :
Answer: A) 100 Explanation: Given 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 It is in the form of a3+b3+c3-3abca2+b2+c2-ab-bc-ca= a + b + c Here a = 37, b = 35 & c = 28 => a + b + c = 37 + 35 + 28 = 100 Therefore, = 100
Q: A supplier supplies cartridges to a news paper publishing house. He earns a profit of 25% by selling cartridges for Rs. 1540. Find the cost price of the Cartridges ? 2824 05b5cc741e4d2b4197774f9a9
5b5cc741e4d2b4197774f9a9- 1Rs. 1100false
- 2Rs. 1793.4false
- 3Rs. 1440false
- 4Rs. 1232true
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Answer : 4. "Rs. 1232"
Explanation :
Answer: D) Rs. 1232 Explanation: Let Cost Price(C.P) = Pgain% = {(S.P-C.P)/C.P} x 10025 = {(1540-P)/P} x 10025/100 = (1540-P)/P=> P = 4(1540)-4P=> 5P = 4(1540)=> P = 1232So, Cost Price = Rs. 1232
Q: Word length of a personal computer is 2822 05b5cc642e4d2b4197774bb7c
5b5cc642e4d2b4197774bb7c- 132 bitfalse
- 216 bitfalse
- 38 bittrue
- 44 bitfalse
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Answer : 3. "8 bit"
Explanation :
Answer: C) 8 bit Explanation: Word length refers to the number of bits processed by a computer's CPU in one go. These days, typically 32 bits or 64 bits are used. Data bus size, instruction size, address size are usually multiples of the word size.