Given Exp. = √4096 + √40.96 +√0.004096

= 64 + 6.4 + 0.064

(6767+ 67) = 67(6766 + 166)

As 66 is an even number

We know   6766 is an even number

We know   (6766 + 1) is perfectly divisible by (67 + 1)

i.e. 68

We know   The remainder = 66

(6767+ 67) = 67(6766 + 166)

Let the consecutive odd numbers be x and (x+2)

We know that x2 + (x + 2)2 = 394

We know   x2 + x2 + 4x + 4 = 394

We know   2 x2 +4x – 390 = 0

We know   x2 + 2x – 195 = 0

We know  (x +15) (x-13) = 0

We know   x = 13

We know    Required sum = 13 +15 =28

Let √6+√6+√6+…. be x.

We know x =√6+x

We know x2 = 6+x

We know x2 - x – 6 = 0

We know (x-3) (x+2) = 0

(81)3.6 * (9)2.7/(81)4.2 * (3) = (3)14.4 * (3)5.4/(3)16.8 * (3)

= 314.4+5.4-16.8-1

= 32

Let the numbers be x and y .

We know   xy = 1575

And  x/y = 9/7

We know   xy/x/y = 1575/9/7

We know    y2  = 1225

We know  y = 35 and x = 45

We know   The sum of the numbers = 45+35

= 80