Maths Practice Question and Answer

Q:

The sum of weights of A and B is 80 kg. 50% of A's weight is $${5\over6}$$ times the weight of B. Find the difference between their weights. 

1443 0

  • 1
    20 kg
    Correct
    Wrong
  • 2
    10 kg
    Correct
    Wrong
  • 3
    25 kg
    Correct
    Wrong
  • 4
    15 kg
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 1. "20 kg"
Explanation :

Let's denote the weight of A as 𝑥x kg and the weight of B as 𝑦y kg.

Given:

  1. 𝑥+𝑦=80x+y=80 (Sum of weights of A and B is 80 kg)
  2. 0.5𝑥=56𝑦0.5x=65y (50% of A's weight is 5665 times the weight of B)

We can solve these two equations to find the values of 𝑥x and 𝑦y, and then calculate the difference between their weights.

From equation 2: 0.5𝑥=56𝑦0.5x=65y Multiply both sides by 2 to get rid of the fraction: 𝑥=56𝑦×2x=65y×2 𝑥=106𝑦x=610y 𝑥=53𝑦x=35y

Now substitute this expression for 𝑥x into equation 1: 53𝑦+𝑦=8035y+y=80 83𝑦=8038y=80 Multiply both sides by 3883: 𝑦=80×38y=80×83 𝑦=30y=30

Now that we have found the weight of B, we can find the weight of A using equation 1: 𝑥+30=80x+30=80 𝑥=80−30x=80−30 𝑥=50x=50

So, the weight of A is 50 kg and the weight of B is 30 kg.

Now, let's find the difference between their weights: Difference=Weight of A−Weight of BDifference=Weight of A−Weight of B Difference=50−30Difference=50−30 Difference=20Difference=20

Therefore, the difference between their weights is 20 kg.

Q:

If A : B = 3 : 2, then (3A – 2B): (2A – B) is equal to

1443 0

  • 1
    5 : 4
    Correct
    Wrong
  • 2
    7 : 3
    Correct
    Wrong
  • 3
    6 : 5
    Correct
    Wrong
  • 4
    3 : 1
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 1. "5 : 4"

Q:

If (a-b)=-3 , (b-c)=5 and (c-a)=-2, then the value of $$ {a^{3}+b^{3}+c^{3}-3abc\over a+b+c}$$.

1442 0

  • 1
    18
    Correct
    Wrong
  • 2
    17
    Correct
    Wrong
  • 3
    10.5
    Correct
    Wrong
  • 4
    20.5
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 2. "17"

Q:

If (x11+1) is divided by (x+1), then the remainder is :

1442 0

  • 1
    0
    Correct
    Wrong
  • 2
    2
    Correct
    Wrong
  • 3
    1
    Correct
    Wrong
  • 4
    10
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 1. "0"

Q:

A shopkeeper marks an article 24% above its cost price and allows a 15% discount on the marked price. If he earns a profit of Rs. 27 by selling the article, then the selling price of the article is:

1442 0

  • 1
    Rs. 522
    Correct
    Wrong
  • 2
    Rs. 508
    Correct
    Wrong
  • 3
    Rs. 527
    Correct
    Wrong
  • 4
    Rs. 517
    Correct
    Wrong
  • 5
    Rs. 817
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 3. "Rs. 527"

Q:

A solid cube, whose diagonal is $$ 128 {\ sqrt {2}} \ cm $$, is molded to form a cuboid. The length and width of the cuboid are 512 cm and 160 cm, respectively. What is the height of the cuboid?

1442 0

  • 1
    16 cm
    Correct
    Wrong
  • 2
    25.6 cm
    Correct
    Wrong
  • 3
    20.8 cm
    Correct
    Wrong
  • 4
    16.4 cm
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 2. "25.6 cm"

Q:

The ratio of the outer and the inner perimeter of a circular path is 23 : 22, If the path is 5 meters wide the diameter of the inner circle is : 

1442 0

  • 1
    110 m
    Correct
    Wrong
  • 2
    55 m
    Correct
    Wrong
  • 3
    220 m
    Correct
    Wrong
  • 4
    230 m
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 3. "220 m "

Q:

The angle of elevation of the top of two vertical towers as seen from the middle point of the line joining the foot of the towers are 60° and 30°, respectively. The ratio of the heights of the tower is

1441 0

  • 1
    2 : 1
    Correct
    Wrong
  • 2
    √3 : 1
    Correct
    Wrong
  • 3
    3 : 2
    Correct
    Wrong
  • 4
    3 : 1
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 4. "3 : 1"

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully