Maths Practice Question and Answer
8 Q: AB is a diameter of a circle with centre O. The tangents at C meets AB produced at Q. If ∠CAB = 34°, then measure of ∠CBA is
1087 064104ac4a37bb1a5e17c78fb
64104ac4a37bb1a5e17c78fb- 156°true
- 268°false
- 334°false
- 4124°false
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Answer : 1. "56° "
Q:What approximate value should come in the place of question mark (?) in the following question?
1/3 of 785.99 – 11/8 of 1031.99 = ? – 13/4 of 527.98
1087 064e499a9de1aa1b70fd56044
64e499a9de1aa1b70fd56044- 1428false
- 2559true
- 3592false
- 4487false
- 5507false
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Answer : 2. "559"
Q: If a ≠ b, then which of the following statement is true ?
1086 05f1e9da626299776aa421043
5f1e9da626299776aa421043- 1$${a+b\over 2}= \sqrt{ab} $$false
- 2$${a+b\over 2}> \sqrt{ab} $$true
- 3$${a+b\over 2}< \sqrt{ab} $$false
- 4All of the abovefalse
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Answer : 2. "$${a+b\over 2}> \sqrt{ab} $$"
Q: If a shopkeeper sells an article at 10% loss by giving half discount on the marked price, then what will be its cost price?
1086 0630dedbd7c72c077845c5660
630dedbd7c72c077845c5660- 11/9 of the face valuefalse
- 24/9 of the face valuefalse
- 35/9 of the face valuetrue
- 47/9 of the face valuefalse
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Answer : 3. "5/9 of the face value"
Q: Manoj deposited ₹ 29400 for 6 years at a simple interest. He got ₹ 4200 as interest after 6 years. The annual rate of interest was-
1086 065423c754a7ba1cb6049bb4a
65423c754a7ba1cb6049bb4a- 1$$2{8\over21}$$true
- 2$$2{7\over20}$$false
- 3$$3{8\over21}$$false
- 4$$4{8\over21}$$false
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Answer : 1. "$$2{8\over21}$$"
Explanation :

Q: The L.C.M. of two numbers is 1820 and their H.C.F. is 26. If one number is 130 then the other number is:
1085 062f11ac906679c6dabc703f9
62f11ac906679c6dabc703f9- 170false
- 21690false
- 3364true
- 41264false
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Answer : 3. "364 "
Q: A man buys a cycle for ₹1400 and sells it at a loss of 15%. What is the selling price of the cycle?
1085 06246c67a398e4a497b43d0bd
6246c67a398e4a497b43d0bd- 1₹1160false
- 2₹1000false
- 3₹1202false
- 4₹1190true
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Answer : 4. "₹1190 "
Explanation :

Q:Directions: In the following question, two equations are given in variables X and Y. You have to solve these equations and determine the relation between X and Y.
I. X2 – 5x + 6 = 0
II. 2y2 – 7y +3 = 0
1084 064e5eab4646d8ab6ebd7b2c3
64e5eab4646d8ab6ebd7b2c3II. 2y2 – 7y +3 = 0
- 1X > Yfalse
- 2X < Yfalse
- 3X ≥ Yfalse
- 4X ≤ Yfalse
- 5X = Y or no relation can be establishedtrue
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