Directions: The pie– chart shows the proposed outlay for different sectors during a Five–Year plan of Government of India. Total outlay is Rs. 40,000 crores. By reading the pie–chart answer the following three questions.

What is the ratio between the proposed outlay of Irrigation and Communication?

Diagonal of a given square is 4√2 cm. What is the diagonal of the other square whose area is double of the given square?

If the speed of a boat in still water is 20 km/hr and the speed of the current is 5km / hr, then the time taken by the boat to travel 100km with the current is

If a store room of a house is in the shape of a cuboid having a length of 3 m, a width of 2 m, and a height of 4m, find the total area of its four walls.

A man had ₹ 16,000, part of which he lent at 4% and the rest at 5% per annum simple interest. If the total interest received was 700 in one year, the money lent at 4% per annum was

Directions: Read the following data carefully and answer the questions given below:

There are 6300 students in Manipur University in the academic year 2020. The ratio of the boys to the girls in the University is 5 : 4. All the students are enrolled in different indoor activities (Chess, Carom, Debating, Painting, and Quiz) and one student is enrolled in only one indoor activity. The number of boys enrolled in the Painting is 621. The ratio of the number of boys who enrolled in Chess to the number of boys who enrolled in Carom is 5 : 3. 36% of the students are enrolled in Quiz. The number of boys enrolled in Debating is 25% of the total number of boys. The number of girls enrolled in Quiz is 640 which is 150 less than the number of girls enrolled in Carom. The number of girls enrolled in Chess is 186 more than the number of boys enrolled in the same activity. The total number of students enrolled in Painting is 816.

The difference in the number of boys and girls who are enrolled in painting is what percentage of the total number of students who are enrolled in Debating? (approximately)

Direction: In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

I. x² + 13x + 42 = 0
II. y² – 2y - 63 = 0

If x = 2 - 2^1/3 + 2^2/3, then the value of x³– 6x² + 18x + 18 is