Quantitative Aptitude Practice Question and Answer
8Q: Square units 13 by 9 of an office area is 2008 05b5cc662e4d2b4197774be89
5b5cc662e4d2b4197774be89- 197false
- 2117true
- 3107false
- 4127false
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Answer : 2. "117"
Explanation :
Answer: B) 117 Explanation: Square units 13 by 9 of an office means office of length 13 units and breadth 9 units. Now its area is 13x 9 = 117 square units or units square.
Q: If J is the interest on K and K is the interest on L, the rate and time is the same on both the cases. What is the relation between J, K and L ? 2008 05b5cc6d5e4d2b4197774e5d4
5b5cc6d5e4d2b4197774e5d4- 1J x J = KLfalse
- 2K x K= JLtrue
- 3L x L = JKfalse
- 4JKL = 1false
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Answer : 2. "K x K= JL"
Explanation :
Answer: B) K x K= JL Explanation: Let the Time be 'N' and Rate be 'R' J = (K x NR)/100 K = (L x NR)/100 J/K = NR/100 K/L = NR/100 J/K = K/L K x K = JL
Q: 28% members of a certain group are married. What is the respective ratio between the number of married members to the number of unmarried members?
2007 05d4a9f58108bca202e8a3645
5d4a9f58108bca202e8a3645- 17:17false
- 25: 18false
- 37:18true
- 4Cannot determinedfalse
- 5None of thesefalse
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Answer : 3. "7:18"
Explanation :
Let total number of person is=100
married person=28
unmarried person will be 100-28=72
The ratio will be 28/72=7/18
Q: A, B and C can do a piece of work in 72, 48 and 36 days respectively. For first p/2 days, A & B work together and for next ((p+6))/3days all three worked together. Remaining 125/3% of work is completed by D in 10 days. If C & D worked together for p day then, what portion of work will be remained? 2007 05b5cc669e4d2b4197774bf4d
5b5cc669e4d2b4197774bf4d- 11/5false
- 21/6true
- 31/7false
- 41/8false
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Answer : 2. "1/6"
Explanation :
Answer: B) 1/6 Explanation: Total work is given by L.C.M of 72, 48, 36 Total work = 144 units Efficieny of A = 144/72 = 2 units/day Efficieny of B = 144/48 = 3 units/day Efficieny of C = 144/36 = 4 units/day According to the given data, 2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100 3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54 p = 198/16.5 p = 12 days. Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day (C+D) in p days = (4 + 6) x 12 = 120 unit Remained part of work = (144-120)/144 = 1/6.
Q: In one year, the Amount collected for social welfare, of a village increased by 10% and in the next year, it decreased by 10%. If at the end of 2nd year, the amount was 7920, what was it in the beginning ? 2006 05b5cc6d8e4d2b4197774e773
5b5cc6d8e4d2b4197774e773- 18800false
- 28650false
- 38000true
- 48980false
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Answer : 3. "8000"
Explanation :
Answer: C) 8000 Explanation: Let the amount collected be 'A'Then, from the given conditions,A x 110/100 x 90/100 = 7920 A x 0.99 = 7920 A = 7920/0.99=> 8000
Q: The milk and water in two vessels A and B are in the ratio 4:3 and 2:3 respectively. In what ratio the liquids in both the vessels be mixed to obtain a new mixture in vessel c consisting half milk and half water? 2005 05b5cc6bde4d2b4197774d8e8
5b5cc6bde4d2b4197774d8e8- 18:3false
- 26:7false
- 37:5true
- 411:7false
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Answer : 3. "7:5"
Explanation :
Answer: C) 7:5 Explanation: Milk in 1-litre mixture of A = 4/7 litre. Milk in 1-litre mixture of B = 2/5 litre. Milk in 1-litre mixture of C = 1/2 litre. By rule of alligation we have required ratio X:Y X : Y 4/7 2/5 \ / (Mean ratio) (1/2) / \ (1/2 – 2/5) : (4/7 – 1/2) 1/10 1/1 4 So Required ratio = X : Y = 1/10 : 1/14 = 7:5
Q: With an average speed of 40 km/hr, a train reaches its destination in time. If it goes with an average speed of 35 km/hr, it is late by 15 minutes. Find the length of the total journey? 2005 05b5cc662e4d2b4197774be9c
5b5cc662e4d2b4197774be9c- 170 kmstrue
- 260 kmsfalse
- 345 kmsfalse
- 430 kmsfalse
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Answer : 1. "70 kms"
Explanation :
Answer: A) 70 kms Explanation: Let the time taken by train be 't' hrs. Then, 40t = 35t + 1560 40t = 35t + 35/4 t = 7/4 hrs Therefore, Required length of the total journey d = s x t = 40 x 7/4 = 70 kms.
Q: In the following number series only one number is wrong. Find out the wrong number ? 6, 15, 35, 63, 143, 221, 323 2004 05b5cc6c8e4d2b4197774df41
5b5cc6c8e4d2b4197774df41- 1143false
- 263true
- 3323false
- 435false
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Answer : 2. "63"
Explanation :
Answer: B) 63 Explanation: Here the series follows the pattern that, product of succesive prime numbers i.e, 2 × 3 = 6 3 × 5 = 15 5 × 7 = 35 7 × 11 = 77 11 × 13 = 143 13 × 17 = 221 17 × 19 = 323 So here in place of 77 the number 63 is written. So the wrong number is 63.