Answer: C) 166252 Explanation: Given 92613 x 62742241 = ? + 89   Using unit digit method,   On LHS,   1 x 1 x 1 = 1   sqrt of last digit 1 => it must end with either 9 or 1   so now   1 x 1 = 1   1 x 9 = 9   On RHS,   ? + 89   => ? = ...1 - 89 = last digit is 11- 9 = 2   or   => ? = ...9 - 89 = last digit is 9 - 9 = 0   Here in the options last digit 2 is option C.

Answer: C) 36 sec Explanation: Given speed of jogger = 9 kmph Speed of train = 45 kmphAs they are in same direction, Relative speed = 45 - 9 = 36 kmph = 36x5/18 = 10 m/sDistance = 240 + 120 = 360 mts Time = distance/speed = 360/10 = 36 sec.

Answer: C) 12.5 cm Explanation: Let the required height of the building be x meter More shadow length, More height(direct proportion) Hence we can write as (shadow length) 40.25 : 28.75 :: 17.5 : x⇒ 40.25 × x = 28.75 × 17.5⇒ x = 28.75 × 17.5/40.25= 2875 × 175/40250= 2875 × 7/1610= 2875/230= 575/46= 12.5 cm

Answer: A) 146 Explanation: From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ? Now arranging the given numbers in descending order.837 746 519 495 328 519 - 746/2 = 519 - 373 = 146.

Answer: D) 7 Explanation:    1 1    8 A 9 + 4 C 6 -  6 B 2    7 2 3 We may represent the given sum, as shown below:1 + A + C - B = 12 A + C - B = 11 Now,giving the maximum values to A and C, i.e.A = 9 and C = 9, we get B = 7.

Answer: B) 80 kgs Explanation: Say total cost price of tea is x.Then total profit at a rate of 15% is = (15x/100)According to question,15x/100 = 60so x = 400C.p of the tea is Rs. 400.so total selling price will be = (400+60) = Rs.460so the quantity of the tea will be = (460/5.75) = 80kg.

Answer: D) 84.8 Explanation: Let 'M' be the maximum marks in the examination. Therefore, Madhu got 32% of M = 32M/100 = 0.32MAnd Kumar got 42% of M = 42M/100 = 0.42M.In terms of the maximum marks Kumar got 0.42M - 0.32M = 0.1M more than Madhu. ---- (1) The problem however, states that Kumar got 16 marks more than the cut-off mark and Madhu got 8 marks less than the cut-off mark. Therefore, Kumar has got 16 + 8 = 24 marks more than Madhu. ---- (2) Now, Equating (1) and (2), we get0.1M = 24 => M = 24/0.1 = 240'M' is the maximum mark and is equal to 240 marks.We know that Madhu got 32% of the maximum marks.Therefore, Madhu got 32 x 240/100 = 76.8 marks.We also know that Madhu got 8 marks less than the cut-off marks. Therefore, the cut-off marks will be 8 marks more than what Madhu got = 76.8 + 8 = 84.8.

Answer: C) 7:5 Explanation: Milk in 1-litre mixture of A = 4/7 litre.  Milk in 1-litre mixture of B = 2/5 litre.  Milk in 1-litre mixture of C = 1/2 litre.   By rule of alligation we have required ratio X:Y       X                  :                 Y     4/7                                2/5              \                      /               (Mean ratio)                   (1/2)             /                      \  (1/2 – 2/5)     :       (4/7 – 1/2)       1/10                      1/1 4    So Required ratio = X : Y = 1/10 : 1/14 = 7:5