Quantitative Aptitude Practice Question and Answer
8Q: At a certain rate of interest the compound interest of 3 years and simple interest of 5 years for certain sum of money is respectively Rs. 1513.2 and Rs. 2400. Find the common rate of interest per annum ? 2828 05b5cc6cde4d2b4197774e1cc
5b5cc6cde4d2b4197774e1cc- 15%true
- 26%false
- 34%false
- 43%false
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Answer : 1. "5%"
Explanation :
Answer: A) 5% Explanation: Given compound interest for 3 years = Rs. 1513.2 and simple interest for 5 years = Rs. 2400 Now, we know that C.I = P1+R100n - 1 => 1513.2 = P1+R1003 - 1 ...........(A) And S.I = PTR/100 => 2400 = P5R/100 ..................(B) By solving (A) & (B), we get R = 5%.
Q: A vertical toy 18 cm long casts a shadow 8 cm long on the ground. At the same time a pole casts a shadow 48 m. long on the ground. Then find the height of the pole ? 3860 05b5cc6cde4d2b4197774e1c2
5b5cc6cde4d2b4197774e1c2- 11080 cmfalse
- 2180 mfalse
- 3108 mtrue
- 4118 cmfalse
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Answer : 3. "108 m"
Explanation :
Answer: C) 108 m Explanation: We know the rule that, At particular time for all object , ratio of height and shadow are same. Let the height of the pole be 'H' Then 188=H48 => H = 108 m.
Q: Raju sold an article by giving a discount of 8% for Rs. 17,940 and earn profit of 19.6 %. If he did not give discount then how much profit percentage he gets ? 1535 05b5cc6cde4d2b4197774e1a9
5b5cc6cde4d2b4197774e1a9- 127%false
- 230%true
- 332%false
- 425%false
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Answer : 2. "30%"
Explanation :
Answer: B) 30% Explanation: Let the M.R.P of an article be 100 % Selling price of article =Rs. 17940 If he give a discount of 8 % then S.P = 92 % 92 % = 17490 100 % = 19500 Now C.P of the article is 17490 x 100/119.6 = 15000 If he did not give the discount, then Required profit percentage =
Q: The length of two superfast trains are 140 mts and 160 mts respectively. If they run at the speed of 60 km/hr and 80 km/hr respectively in opposite direction, find the time in which they will cross each other ? 1492 05b5cc6cde4d2b4197774e1ae
5b5cc6cde4d2b4197774e1ae- 17.71 sectrue
- 210.48 secfalse
- 39.36 secfalse
- 48.45 secfalse
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Answer : 1. "7.71 sec"
Explanation :
Answer: A) 7.71 sec Explanation: Given L1 = 140 m L2 = 160 m S1 = 60 km/hr S2 = 80 km/hr From the question we get, S1 + S2 = (L1 + L2) / T => (60 + 80) 5/18 m/s = 140 + 160/T => T = 54/7 = 7.71 sec
Q: The average of marks in 3 subjects is 224. The first subject marks is twice the second and the second subject marks is twice the third. Find the second subject marks ? 1337 05b5cc6cce4d2b4197774e17c
5b5cc6cce4d2b4197774e17c- 1384false
- 296false
- 3192true
- 4206false
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Answer : 3. "192"
Explanation :
Answer: C) 192 Explanation: Let the third subject marks be 'x'=> Second subject marks = 2x=> Third subject marks = 4xGiven avg = 224x + 2x + 4x = 224 x 3=> 7x = 224 x 3=> x = 96Hence, Second subject marks = 2x = 2 x 96 = 192.
Q: A person can row 8 1/2 km an hour in still water and he finds that it takes him twice as long to row up as to row down the river. The speed of the stream ? 918 05b5cc6cce4d2b4197774e172
5b5cc6cce4d2b4197774e172- 11.78 kmphfalse
- 22.35 kmphfalse
- 32.83 kmphtrue
- 43.15 kmphfalse
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Answer : 3. "2.83 kmph"
Explanation :
Answer: C) 2.83 kmph Explanation: Given speed of the person = 8 1/2 = 17/2 kmphLet the speed of the stream = x kmphspeed of upstream = 17/2 - xspeed of downstream = 17/2 + xBut given that,2(17/2 - x) = 17/2 + x=> 3x = 17/2=> x = 2.83 kmph.
Q: In a mixture of three varities of oils , the ratio of their weight is 4 : 5 : 8. If 5 kg of oils of the first variety, 10 kg of the second variety and some quantity of oils of the third variety are added to the mixture, the ratio of the weights of three varieties of oils becomes as 5 : 7 : 9 in the final mixture, find the quantity of third variety of oil was ? 1965 05b5cc6cce4d2b4197774e177
5b5cc6cce4d2b4197774e177- 115 kgfalse
- 225 kgfalse
- 335 kgfalse
- 445 kgtrue
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Answer : 4. "45 kg"
Explanation :
Answer: D) 45 kg Explanation: Let the ratio of initial quantity of oils be 'x' => 4x, 5x & 8x.Let k be the quantity of third variety of oil in the final mixture.Let the ratio of initial quantity of oils be 'y'From given details,4x + 5 = 5y ..... (1)5x + 10 = 7y .....(2)8x + k = 9y ......(3) By solving (1) & (2), we getx = 5 & y = 5 From (3) => k = 5 Therefore, quantity of third variety of oil was 9y = 9(5) = 45kg.
Q: A contractor undertake to finish a certain work in 124 days and employed 120 men. After 64 days, he found that he had already done 2/3 of the work. How many men can be discharged so that the work may finish in time ? 1274 05b5cc6cce4d2b4197774e16c
5b5cc6cce4d2b4197774e16c- 164false
- 262false
- 358false
- 456true
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Answer : 4. "56"
Explanation :
Answer: D) 56 Explanation: Days remaining 124 – 64 = 60 days Remaining work = 1 - 2/3 = 1/3 Let men required men for working remaining days be 'm' So men required = (120 x 64)/2 = (m x 60)/1 => m = 64 Men discharge = 120 – 64 = 56 men.