Quantitative Aptitude Practice Question and Answer
8Q: Ali and Faizer are 27m apart. They both start walking and meet 9 hrs later, if they travel in the same direction and meet after 3 hrs if they walk in opposite dirction, Ali’s speed must most likely be ? 2161 05b5cc715e4d2b4197774f44f
5b5cc715e4d2b4197774f44f- 19 m/hfalse
- 23 m/hfalse
- 36 m/htrue
- 412 m/hfalse
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Answer : 3. "6 m/h"
Explanation :
Answer: C) 6 m/h Explanation: let, speed of Ali=X mph and Faizer=Y mph Now, relative speed when Ali is walking int the same direction with Faizer= (X-Y)mphhence, according to question, 27/(X-Y)=9 ; solving X-Y=3; --- (1) Now relative speed when walking in the opposite direction= (X+Y) mphhence, according to question, 27/(X+y)=3; solving X+Y=9; --- (2) solving 1 and 2 we get X=6 and Y=3, where X is the speed of Ali.
Q: If A1, A2, A3, A4, ..... A10 are speakers for a meeting and A1 always speaks after, A2 then the number of ways they can speak in the meeting is 2161 05b5cc7b4e4d2b419777508a6
5b5cc7b4e4d2b419777508a6- 19!false
- 29!/2false
- 310!false
- 410!/2true
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Answer : 4. "10!/2"
Explanation :
Answer: D) 10!/2 Explanation: As A1 speaks always after A2, they can speak only in 1st to 9th places and A2 can speak in 2nd to 10 the places only when A1 speaks in 1st place A2 can speak in 9 places the remaining A3, A4, A5,...A10 has no restriction. So, they can speak in 9.8! ways. i.e when A2 speaks in the first place, the number of ways they can speak is 9.8!. When A2 speaks in second place, the number of ways they can speak is 8.8!. When A2 speaks in third place, the number of ways they can speak is 7.8!. When A2 speaks in the ninth place, the number of ways they can speak is 1.8! Therefore,Total Number of ways they can speak = (9+8+7+6+5+4+3+2+1) 8! = 92(9+1)8! = 10!/2
Q: Find the compound interest on Rs. 6,500 for 4 years if the rate of interest is 10% p.a. for the first 2 years and 20% per annum for the next 2 years? 2160 05b5cc6abe4d2b4197774cfe0
5b5cc6abe4d2b4197774cfe0- 1Rs. 3845false
- 2Rs. 4826true
- 3Rs. 5142false
- 4Rs. 4415false
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Answer : 2. "Rs. 4826"
Explanation :
Answer: B) Rs. 4826 Explanation: We know the formula for calculating The compound interest C = P1 + r100n - 1 where P = amount, r = rate of interest, n = time Here P = 5000, r1 = 10, r2 = 20 Then C = 65001 + 101002 x 1 + 201002 - 1= 6500 x 18562500= 65 x 185625 C = Rs. 4826.
Q: What will come in place of the question mark (?) in the following number series ? 12, 24, 26.5, 79.5, ?, 330 2160 05b5cc6c1e4d2b4197774db5f
5b5cc6c1e4d2b4197774db5f- 1211false
- 2101.5false
- 382.5true
- 499false
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Answer : 3. "82.5"
Explanation :
Answer: C) 82.5 Explanation: The given series 12 24 26.5 79.5 ? 330 follows a pattern that, 12 x 2 = 24 24 + 2.5 = 26.5 26.5 x 3 = 79.5 79.5 + 3 = 82.5 82.5 x 4 = 330 Hence, the missing number is 82.5
Q: 28% members of a certain group are married. What is the respective ratio between the number of married members to the number of unmarried members?
2160 05d4a9f58108bca202e8a3645
5d4a9f58108bca202e8a3645- 17:17false
- 25: 18false
- 37:18true
- 4Cannot determinedfalse
- 5None of thesefalse
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Answer : 3. "7:18"
Explanation :
Let total number of person is=100
married person=28
unmarried person will be 100-28=72
The ratio will be 28/72=7/18
Q: 2/3 as a decimal 2159 05b5cc651e4d2b4197774bcf4
5b5cc651e4d2b4197774bcf4- 10.47false
- 26.77false
- 30.67true
- 40.07false
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Answer : 3. "0.67"
Explanation :
Answer: C) 0.67 Explanation: To convert a fraction into decimal, just take the number on top which we called the numerator and divide it by the number at the bottom which we called the denominator. 2/3 How it comes : 2 ÷ 3 = 0 bring down the decimal point. 20 ÷ 3 = 6 and carry the remainder 2 to make 20 20 ÷ 3 = 6 and carry the remainder 2 to make 20 20 ÷ 3 = 6 and carry the remainder 2 to make 20 etc... This gives the recurring decimal 0.6666... If we round off to two decimals , then it becomes 0.67. Hence, decimal fraction of 2/3 = 0.67.
Q: If 4 circles of equal radius are drawn with vertices of a square as the centre , the side of the square being 7 cm, find the area of the circles outside the square ? 2159 05b5cc718e4d2b4197774f490
5b5cc718e4d2b4197774f490- 1119.21 sq cmfalse
- 2115.395 sq cmtrue
- 3104.214 sq cmfalse
- 4111.241 sq cmfalse
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Answer : 2. "115.395 sq cm"
Explanation :
Answer: B) 115.395 sq cm Explanation: Because each vertice of the square is the center of a circle(1/4) part of the total area of each circle inside of the square.(3/4) part of the total area of each circle outside of the square.Thus total area outside the square is 434×227×3.5×3.5 = 115.3955 sq cm.
Q: A girl want to read a complete book. She read 2/5 part of a book on 1st day, 34% on second day and remaining pages in next two days. On those two days she read equal number of pages. If she read 52 pages on last day, then find out total number of pages that the book contain ? 2158 05b5cc6cbe4d2b4197774e108
5b5cc6cbe4d2b4197774e108- 1400true
- 2525false
- 3325false
- 4475false
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Answer : 1. "400"
Explanation :
Answer: A) 400 Explanation: Let the total number of pages in the book be 'x'. From given data, 2x/5 + 34x/100 + 52 + 52 = x => 40x + 34x + 10400 = 100x => 26x = 10400 => x = 400. Hence, total pages in the book are 400.

