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Q: From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ? 519 328 746 495 837 1972 0

Answer : 1. "146"
Explanation :
Answer: A) 146 Explanation: From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ? Now arranging the given numbers in descending order.837 746 519 495 328 519 - 746/2 = 519 - 373 = 146.

Q: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is 1970 0

Answer : 3. "40"
Explanation :
Answer: C) 40 Explanation: Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)On dividing (i) by (ii), we get: x = 40 km.

Q: A jogger running at 9 km/hr along side a railway track is 260 m ahead of the engine of a 140 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger ? 1967 0

Answer : 2. "40 sec"
Explanation :
Answer: B) 40 sec Explanation: Speed of train relative to jogger = 45 - 9 = 36 km/hr.= 36 x 5/18 = 10 m/sec. Distance to be covered = 260 + 140 = 400 m. Time taken = 400/10 = 40 sec.

Q: Find the next number in the following number series? 410, 409, 413, 404, ? 1967 0

Answer : 4. "420"
Explanation :
Answer: D) 420 Explanation: The given number series 410, 409, 413, 404, ? , follows a pattern that 410 410 - 13 = 409409 + 22 = 413413 - 33 = 404404 + 42 = 420 Hence, the next number in the given series is 420.

Q: A can do a piece of work in 30 days. He works at it for 6 days and then B finishes it in 18 days. In what time can A and B together it ? 1966 0

Answer : 4. "12 6/7 days"
Explanation :
Answer: D) 12 6/7 days Explanation: Let 'B' alone can do the work in 'x' days 6/30 + 18/x = 1 => x = 22.5 1/30 + 1/22.5 = 7/90 => 90/7 = 12 6/7 days

Q: Four person A, B, C and D. The sum of their present age is 176. Four years ago ratio of their age was 11: 9 : 6 : 14, then find who is eldest and youngest among them ? 1965 0

Answer : 2. "D is eldest & C is youngest"
Explanation :
Answer: B) D is eldest & C is youngest Explanation: Given sum of present ages of A, B, C & D A + B + C + D = 176 and also given that, (A-4) : (B-4) : (C-4) : (D-4) = 11 : 9 : 6 : 14 Let the ratio = x => A-4 + B-4 + C-4 + D-4 = 11x + 9x + 6x + 14x => (A + B + C + D ) - 16 = 40x => 176 - 16 = 40x => x = 4 => A = 44 + 4 = 48 => B = 40 => C = 28 => D = 60 Therefore, from the above conclusions D is eldest with 60 years and C is youngest with 28 years of ages.

Q: Nine different letters of alphabet are given, words with 5 letters are formed from these given letters. Then, how many such words can be formed which have at least one letter repeated ? 1964 0

Answer : 1. "43929"
Explanation :
Answer: A) 43929 Explanation: Number of words with 5 letters from given 9 alphabets formed = 95 Number of words with 5 letters from given 9 alphabets formed such that no letter is repeated is = 9P5 Number of words can be formed which have at least one letter repeated = 95 - 9P5 = 59049 - 15120 = 43929

Q: A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ? 1963 0

Answer : 3. "36 sec"
Explanation :
Answer: C) 36 sec Explanation: Given speed of jogger = 9 kmph Speed of train = 45 kmphAs they are in same direction, Relative speed = 45 - 9 = 36 kmph = 36x5/18 = 10 m/sDistance = 240 + 120 = 360 mts Time = distance/speed = 360/10 = 36 sec.

Q: From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ? 519 328 746 495 837 1972 0

Q: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is 1970 0

Answer : 3. "40"
Explanation :
Answer: C) 40 Explanation: Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)On dividing (i) by (ii), we get: x = 40 km.

Q: A jogger running at 9 km/hr along side a railway track is 260 m ahead of the engine of a 140 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger ? 1967 0

Answer : 2. "40 sec"
Explanation :
Answer: B) 40 sec Explanation: Speed of train relative to jogger = 45 - 9 = 36 km/hr.= 36 x 5/18 = 10 m/sec. Distance to be covered = 260 + 140 = 400 m. Time taken = 400/10 = 40 sec.

Q: Find the next number in the following number series? 410, 409, 413, 404, ? 1967 0

Answer : 4. "420"
Explanation :
Answer: D) 420 Explanation: The given number series 410, 409, 413, 404, ? , follows a pattern that 410 410 - 13 = 409409 + 22 = 413413 - 33 = 404404 + 42 = 420 Hence, the next number in the given series is 420.

Q: A can do a piece of work in 30 days. He works at it for 6 days and then B finishes it in 18 days. In what time can A and B together it ? 1966 0

Answer : 4. "12 6/7 days"
Explanation :
Answer: D) 12 6/7 days Explanation: Let 'B' alone can do the work in 'x' days 6/30 + 18/x = 1 => x = 22.5 1/30 + 1/22.5 = 7/90 => 90/7 = 12 6/7 days

Q: Four person A, B, C and D. The sum of their present age is 176. Four years ago ratio of their age was 11: 9 : 6 : 14, then find who is eldest and youngest among them ? 1965 0

Q: Nine different letters of alphabet are given, words with 5 letters are formed from these given letters. Then, how many such words can be formed which have at least one letter repeated ? 1964 0

Q: A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ? 1963 0

Answer : 3. "36 sec"
Explanation :
Answer: C) 36 sec Explanation: Given speed of jogger = 9 kmph Speed of train = 45 kmphAs they are in same direction, Relative speed = 45 - 9 = 36 kmph = 36x5/18 = 10 m/sDistance = 240 + 120 = 360 mts Time = distance/speed = 360/10 = 36 sec.

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Q: From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ? 519 328 746 495 837 1972 05b5cc73ae4d2b4197774f8a6

Q: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is 1970 05b5cc6d9e4d2b4197774e816

Answer : 3. "40" Explanation :Answer: C) 40 Explanation: Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)On dividing (i) by (ii), we get: x = 40 km.

Q: A jogger running at 9 km/hr along side a railway track is 260 m ahead of the engine of a 140 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger ? 1967 05b5cc6e5e4d2b4197774ed29

Answer : 2. "40 sec" Explanation :Answer: B) 40 sec Explanation: Speed of train relative to jogger = 45 - 9 = 36 km/hr.= 36 x 5/18 = 10 m/sec. Distance to be covered = 260 + 140 = 400 m. Time taken = 400/10 = 40 sec.

Q: Find the next number in the following number series? 410, 409, 413, 404, ? 1967 05b5cc662e4d2b4197774bea6

Answer : 4. "420" Explanation :Answer: D) 420 Explanation: The given number series 410, 409, 413, 404, ? , follows a pattern that 410 410 - 13 = 409409 + 22 = 413413 - 33 = 404404 + 42 = 420 Hence, the next number in the given series is 420.

Q: A can do a piece of work in 30 days. He works at it for 6 days and then B finishes it in 18 days. In what time can A and B together it ? 1966 05b5cc6d8e4d2b4197774e755

Answer : 4. "12 6/7 days" Explanation :Answer: D) 12 6/7 days Explanation: Let 'B' alone can do the work in 'x' days 6/30 + 18/x = 1 => x = 22.5 1/30 + 1/22.5 = 7/90 => 90/7 = 12 6/7 days

Q: Four person A, B, C and D. The sum of their present age is 176. Four years ago ratio of their age was 11: 9 : 6 : 14, then find who is eldest and youngest among them ? 1965 05b5cc6c1e4d2b4197774db82

Q: Nine different letters of alphabet are given, words with 5 letters are formed from these given letters. Then, how many such words can be formed which have at least one letter repeated ? 1964 05b5cc6c6e4d2b4197774de0e

Q: A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ? 1963 05b5cc6dee4d2b4197774ea5b

Answer : 3. "36 sec" Explanation :Answer: C) 36 sec Explanation: Given speed of jogger = 9 kmph Speed of train = 45 kmphAs they are in same direction, Relative speed = 45 - 9 = 36 kmph = 36x5/18 = 10 m/sDistance = 240 + 120 = 360 mts Time = distance/speed = 360/10 = 36 sec.

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Q: From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ? 519 328 746 495 837 1972 0

Q: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is 1970 0

Answer : 3. "40"
Explanation :
Answer: C) 40 Explanation: Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)On dividing (i) by (ii), we get: x = 40 km.

Q: A jogger running at 9 km/hr along side a railway track is 260 m ahead of the engine of a 140 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger ? 1967 0

Answer : 2. "40 sec"
Explanation :
Answer: B) 40 sec Explanation: Speed of train relative to jogger = 45 - 9 = 36 km/hr.= 36 x 5/18 = 10 m/sec. Distance to be covered = 260 + 140 = 400 m. Time taken = 400/10 = 40 sec.

Q: Find the next number in the following number series? 410, 409, 413, 404, ? 1967 0

Answer : 4. "420"
Explanation :
Answer: D) 420 Explanation: The given number series 410, 409, 413, 404, ? , follows a pattern that 410 410 - 13 = 409409 + 22 = 413413 - 33 = 404404 + 42 = 420 Hence, the next number in the given series is 420.

Q: A can do a piece of work in 30 days. He works at it for 6 days and then B finishes it in 18 days. In what time can A and B together it ? 1966 0

Answer : 4. "12 6/7 days"
Explanation :
Answer: D) 12 6/7 days Explanation: Let 'B' alone can do the work in 'x' days 6/30 + 18/x = 1 => x = 22.5 1/30 + 1/22.5 = 7/90 => 90/7 = 12 6/7 days

Q: Four person A, B, C and D. The sum of their present age is 176. Four years ago ratio of their age was 11: 9 : 6 : 14, then find who is eldest and youngest among them ? 1965 0

Q: Nine different letters of alphabet are given, words with 5 letters are formed from these given letters. Then, how many such words can be formed which have at least one letter repeated ? 1964 0

Q: A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ? 1963 0

Answer : 3. "36 sec"
Explanation :
Answer: C) 36 sec Explanation: Given speed of jogger = 9 kmph Speed of train = 45 kmphAs they are in same direction, Relative speed = 45 - 9 = 36 kmph = 36x5/18 = 10 m/sDistance = 240 + 120 = 360 mts Time = distance/speed = 360/10 = 36 sec.