Quantitative Aptitude Practice Question and Answer
8Q: A Bus is running at 9/10 of its own speed reached a place in 22 hours. How much time could be saved if the bus would run at its own speed ? 1654 05b5cc6dde4d2b4197774ea00
5b5cc6dde4d2b4197774ea00- 11.5 hrsfalse
- 21.7 hrsfalse
- 32.2 hrstrue
- 43.5 hrsfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "2.2 hrs"
Explanation :
Answer: C) 2.2 hrs Explanation: Let the original Speed be "s" kmphAnd the usual time be "t" hrsGiven that if the bus is running at 9s/10 kmph the time is 22 hrs=> [9s/10] x 22 = t x s=> 99/5 = t => t = 19.8 hrs Hence, if bus runs at its own speed, the time saved = 22 - 19.8 = 2.2 hrs.
Q: Four person A, B, C and D. The sum of their present age is 176. Four years ago ratio of their age was 11: 9 : 6 : 14, then find who is eldest and youngest among them ? 1654 05b5cc6c1e4d2b4197774db82
5b5cc6c1e4d2b4197774db82- 1A is eldest & C is youngestfalse
- 2D is eldest & C is youngesttrue
- 3C is eldest & A is youngestfalse
- 4A is eldest & B is youngestfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "D is eldest & C is youngest"
Explanation :
Answer: B) D is eldest & C is youngest Explanation: Given sum of present ages of A, B, C & D A + B + C + D = 176 and also given that, (A-4) : (B-4) : (C-4) : (D-4) = 11 : 9 : 6 : 14 Let the ratio = x => A-4 + B-4 + C-4 + D-4 = 11x + 9x + 6x + 14x => (A + B + C + D ) - 16 = 40x => 176 - 16 = 40x => x = 4 => A = 44 + 4 = 48 => B = 40 => C = 28 => D = 60 Therefore, from the above conclusions D is eldest with 60 years and C is youngest with 28 years of ages.
Q: In a 48 ltr mixture, the ratio of milk and water is 5:3. How much water should be added in the mixture so as the ratio will become 3:5 ? 1653 05b5cc6c2e4d2b4197774dbff
5b5cc6c2e4d2b4197774dbff- 124 litfalse
- 216 litfalse
- 332 littrue
- 48 litfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "32 lit"
Explanation :
Answer: C) 32 lit Explanation: Given mixture = 48 lit Milk in it = 48 x 5/8 = 30 lit => Water in it = 48 - 30 = 18 lit Let 'L' lit of water is added to make the ratio as 3:5 => 30/(18+L) = 3/5 => 150 = 54 + 3L => L = 32 lit.
Q: The difference between simple interest and compound interest of a certain sum of money at 20% per annum for 2 years is Rs. 56. Then the sum is : 1653 05b5cc6afe4d2b4197774d269
5b5cc6afe4d2b4197774d269- 1Rs. 3680false
- 2Rs. 2650false
- 3Rs. 1400true
- 4Rs. 1170false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "Rs. 1400"
Explanation :
Answer: C) Rs. 1400 Explanation: We know thatThe Difference between Compound Interest and Simple Interest for n years at R rate of interest is given by C.In - S.In = PR100n Here n = 2 years, R = 20%, C.I - S.I = 56 56 = P201002=> P = 56 x 52=> P = 56 x 25=> P = Rs. 1400
Q: A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ? 1651 05b5cc6dee4d2b4197774ea5b
5b5cc6dee4d2b4197774ea5b- 110 secfalse
- 248 secfalse
- 336 sectrue
- 456 secfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "36 sec"
Explanation :
Answer: C) 36 sec Explanation: Given speed of jogger = 9 kmph Speed of train = 45 kmphAs they are in same direction, Relative speed = 45 - 9 = 36 kmph = 36x5/18 = 10 m/sDistance = 240 + 120 = 360 mts Time = distance/speed = 360/10 = 36 sec.
Q: Find the odd one in the number series given below ? 17, 9, 10, 18.5, 35, 90 1651 05b5cc6c5e4d2b4197774dd91
5b5cc6c5e4d2b4197774dd91- 19false
- 210false
- 318.5true
- 490false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "18.5"
Explanation :
Answer: C) 18.5 Explanation: The given series pattern follows 17 9 10 18.5 35 90 × 0.5 + 0.5, × 1 + 1, × 1.5 + 1.5, × 2 + 2, × 2.5 + 2.5 So here 17x0.5 + 0.5 = 9 9x1 + 1 = 10 10x1.5 + 1.5 = 16.5 16.5x2 + 2 = 35 35x2.5 + 2.5 = 90 Here the odd man in the given series is 18.5
Q: If the C.I. on a sum for 2 years at 12 1/2 % per annum is Rs. 510, the S.I. on the same sum at the same rate for the same period of time is ? 1650 05b5cc6e0e4d2b4197774eb2a
5b5cc6e0e4d2b4197774eb2a- 1Rs. 580false
- 2Rs. 480true
- 3Rs. 550false
- 4Rs. 470false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "Rs. 480"
Explanation :
Answer: B) Rs. 480 Explanation: Let the sum be Rs. P. Then, P1+252x1002-P= 510 P[982- 1] = 510. Sum = Rs. 1920 So, S.I. = (1920 x 25 x 2) / (2 x 100) = Rs. 480
Q: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is 1648 05b5cc6d9e4d2b4197774e816
5b5cc6d9e4d2b4197774e816- 130false
- 236false
- 340true
- 442false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "40"
Explanation :
Answer: C) 40 Explanation: Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)On dividing (i) by (ii), we get: x = 40 km.

