Quantitative Aptitude Practice Question and Answer

Q: How many squares with sides 1/2 inch long are needed to cover a rectangle that is 4 ft long and 4 ft wide ? 1866 0

  • 1
    9216
    Correct
    Wrong
  • 2
    10246
    Correct
    Wrong
  • 3
    12345
    Correct
    Wrong
  • 4
    7527
    Correct
    Wrong
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Answer : 1. "9216"
Explanation :

Answer: A) 9216 Explanation: It takes four of those little squares -- each one 1/2 inch on a side -- to cover one square inch. That's because each one is 1/2 x 1/2, or 1/4 of a square inch. In a rectangle that is 48 inches by 48 inches, there are 2304 square inches.(1 ft = 12 inches) Since it takes 4 little squares to cover 1 sq inch, then it would need 2304 x 4 squares (1/2 inch on a side each) to cover a rectangle 4 feet by 4 feet. That is 9,216 of those squares.

Q: Rajitha invested 25% more than Santhosh. Santhosh invested 30% less than Raju, who invested Rs. 6,000. What is the ratio of the amount that Rajitha invested to the total amount invested by all of them together ? 1866 0

  • 1
    25 : 114
    Correct
    Wrong
  • 2
    35 : 103
    Correct
    Wrong
  • 3
    15 : 108
    Correct
    Wrong
  • 4
    41 : 94
    Correct
    Wrong
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Answer : 2. "35 : 103"
Explanation :

Answer: B) 35 : 103 Explanation: Santhosh's investment = 6000 x 70/100 = Rs.4200Rajitha's investment = 4200 x 5/4 = Rs.5250Therefore, total amount invested = 6000 + 4200 + 5250 = Rs.15450.Required ratio = 5250 : 15450 = 35 : 103.

Q: Nine different letters of alphabet are given, words with 5 letters are formed from these given letters. Then, how many such words can be formed which have at least one letter repeated ? 1866 0

  • 1
    43929
    Correct
    Wrong
  • 2
    59049
    Correct
    Wrong
  • 3
    15120
    Correct
    Wrong
  • 4
    0
    Correct
    Wrong
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Answer : 1. "43929"
Explanation :

Answer: A) 43929 Explanation: Number of words with 5 letters from given 9 alphabets formed = 95   Number of words with 5 letters from given 9 alphabets formed such that no letter is repeated is = 9P5   Number of words can be formed which have at least one letter repeated =  95 - 9P5   = 59049 - 15120   = 43929

Q: How many six digit odd numbers can be formed from the digits 0, 2, 3, 5, 6, 7, 8, and 9 (repetition not allowed)? 1866 0

  • 1
    8640
    Correct
    Wrong
  • 2
    720
    Correct
    Wrong
  • 3
    3620
    Correct
    Wrong
  • 4
    4512
    Correct
    Wrong
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Answer : 1. "8640"
Explanation :

Answer: A) 8640 Explanation: Let the 6 digits of the required 6 digit number be abcdef Then, the number to be odd number the last digit must be odd digit i.e 3, 5, 7 or 9 The first digit cannot be ‘0’ => possible digits = 3, 5, 7, 2, 6, 8 Remaining 4 places can be of 6 x 5 x 4 x 3 ways This can be easily understood by Therefore, required number of ways = 6 x 6 x 5 x 4 x 3 x 4 = 36 x 20 x 12 = 720 x 12 = 8640 ways.

Q: 125 over 1000 in Simplest Form? 1864 0

  • 1
    2/9
    Correct
    Wrong
  • 2
    1/8
    Correct
    Wrong
  • 3
    3/8
    Correct
    Wrong
  • 4
    4/7
    Correct
    Wrong
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Answer : 2. "1/8"
Explanation :

Answer: B) 1/8 Explanation: 125 over 1000 in Simplest Form means 1251000 in its simple fraction form.   Now, to get the simplest form of 125/1000, find the HCF or GCD of both numerator and denominator i.e, 125 and 1000.   HCF of 125, 1000 = 125   Then, divide both numerator and denominator by 125 i.e, 1251251000125 = 18   Hence, 18 is the simplest form of 125 over 1000.

Q: A mixture contains 25% milk and rest water. What percent of this mixture must taken out and replaced with milk so that in mixture milk and water may become equal. 1862 0

  • 1
    31.8%
    Correct
    Wrong
  • 2
    31%
    Correct
    Wrong
  • 3
    33.33%
    Correct
    Wrong
  • 4
    29.85%
    Correct
    Wrong
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Answer : 3. "33.33%"
Explanation :

Answer: C) 33.33% Explanation: Now, take percentage of milk and applying mixture rule 25          100        50 50            25  = 2 : 1   Hence required answer =  1/3 or 33.33%

Q: If 4 circles of equal radius are drawn with vertices of a square as the centre , the side of the square being 7 cm, find the area of the circles outside the square ? 1861 0

  • 1
    119.21 sq cm
    Correct
    Wrong
  • 2
    115.395 sq cm
    Correct
    Wrong
  • 3
    104.214 sq cm
    Correct
    Wrong
  • 4
    111.241 sq cm
    Correct
    Wrong
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Answer : 2. "115.395 sq cm"
Explanation :

Answer: B) 115.395 sq cm Explanation: Because each vertice of the square is the center of a circle(1/4) part of the total area of each circle inside of the square.(3/4) part of the total area of each circle outside of the square.Thus total area outside the square is 434×227×3.5×3.5 = 115.3955 sq cm.

Q: If the price of diesel increases by 25% and Karthik intends to spend only an additional 15% on diesel, by how much % will he reduce the quantity of diesel purchased ? 1861 0

  • 1
    6.67 %
    Correct
    Wrong
  • 2
    8 %
    Correct
    Wrong
  • 3
    7.41 %
    Correct
    Wrong
  • 4
    9 %
    Correct
    Wrong
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Answer : 2. "8 %"
Explanation :

Answer: B) 8 % Explanation: Let the price of 1 litre of diesel be Rs.x and let Karthik initially buy 'y' litres of diesel. Therefore, he would have spent Rs. xy on diesel. When the price of diesel increases by 25%, the new price per litre of diesel is 1.25x. Karthik intends to increase the amount he spends on diesel by 15%.i.e., he is willing to spend xy + 15% of xy = 1.15xy Let the new quantity of diesel that he can get be 'q'.Then, 1.25x x q = 1.15xyOr q = (1.15/1.25)y = 0.92y. As the new quantity that he can buy is 0.92y, he gets 0.08y lesser than what he used to get earlier. Or a reduction of 8%.

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