Quantitative Aptitude Practice Question and Answer

Q: A jogger running at 9 km/hr along side a railway track is 260 m ahead of the engine of a 140 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger ? 2137 0

  • 1
    25 sec
    Correct
    Wrong
  • 2
    40 sec
    Correct
    Wrong
  • 3
    38 sec
    Correct
    Wrong
  • 4
    32 sec
    Correct
    Wrong
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Answer : 2. "40 sec"
Explanation :

Answer: B) 40 sec Explanation: Speed of train relative to jogger = 45 - 9 = 36 km/hr.= 36 x 5/18 = 10 m/sec. Distance to be covered = 260 + 140 = 400 m. Time taken = 400/10 = 40 sec.

Q: A work which could be finished in 11 days was finished 4 days earlier after 4 more men joined. The number of men employed was ? 2136 0

  • 1
    7
    Correct
    Wrong
  • 2
    8
    Correct
    Wrong
  • 3
    9
    Correct
    Wrong
  • 4
    10
    Correct
    Wrong
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Answer : 1. "7"
Explanation :

Answer: A) 7 Explanation: As the work is sameM1D1 = M2D2 Here Let the number of men employed was M=> 11M = 7(M+4)=> 11M - 7M = 28=> M = 7

Q: Raghu earns 25% on an investment but loses 10% on another investment. If the ratio of the two investment is 3:5. What is the gain or loss on two investments taken together ? 2136 0

  • 1
    1.251 %
    Correct
    Wrong
  • 2
    3.125 %
    Correct
    Wrong
  • 3
    7.21 %
    Correct
    Wrong
  • 4
    9.451 %
    Correct
    Wrong
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Answer : 2. "3.125 %"
Explanation :

Answer: B) 3.125 % Explanation: Taking the 2 investments to be 3x and 5x respectivelyTotal income of Raghu = (3x) x 1.25 + (5x) x 0.9 = 8.25Therefore, Gain% = 0.25/8 x 100 = 3.125 %.

Q: The sum of one-half, one-third and one-fourth of a number exceeds the number by 22. The number is 2133 0

  • 1
    264
    Correct
    Wrong
  • 2
    284
    Correct
    Wrong
  • 3
    215
    Correct
    Wrong
  • 4
    302
    Correct
    Wrong
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Answer : 1. "264"
Explanation :

Answer: A) 264 Explanation: Let the number be 'x'. Then, from given data x/2 + x/3 + x/4 = x+2213x/12 = x+22x = 264

Q: A can do a piece of work in 30 days. He works at it for 6 days and then B finishes it in 18 days. In what time can A and B together it ? 2133 0

  • 1
    14 1/2 days
    Correct
    Wrong
  • 2
    11 days
    Correct
    Wrong
  • 3
    13 1/4 days
    Correct
    Wrong
  • 4
    12 6/7 days
    Correct
    Wrong
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Answer : 4. "12 6/7 days"
Explanation :

Answer: D) 12 6/7 days Explanation: Let 'B' alone can do the work in 'x' days 6/30 + 18/x = 1 => x = 22.5   1/30 + 1/22.5 = 7/90  => 90/7 = 12 6/7 days

Q: A Bus travels first half distance between two places with a speed of 40 kmph and the rest half distance with a speed of 60 kmph. The average speed of the Bus is ? 2132 0

  • 1
    48 kmph
    Correct
    Wrong
  • 2
    50 kmph
    Correct
    Wrong
  • 3
    46 kmph
    Correct
    Wrong
  • 4
    42 kmph
    Correct
    Wrong
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Answer : 1. "48 kmph"
Explanation :

Answer: A) 48 kmph Explanation: we know that speed = distance traveled/time takenlet the total distance traveled by the car is 2x km.then time taken by it to cover first half is x/60 hour.and for second half is x/40 hour.Then average speed= total distance travelled / total time taken.   i.e. 2xx60+x40   => 2x5x120   = 48 kmph.

Q: Find the remainder when 629 is divided by 5 ? 2132 0

  • 1
    0
    Correct
    Wrong
  • 2
    1
    Correct
    Wrong
  • 3
    3
    Correct
    Wrong
  • 4
    5
    Correct
    Wrong
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Answer : 2. "1"
Explanation :

Answer: B) 1 Explanation: All powers of 6 has 6 in units place so answer will definitely be 1.

Q: A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days  ? 2131 0

  • 1
    9 days
    Correct
    Wrong
  • 2
    11 days
    Correct
    Wrong
  • 3
    13 days
    Correct
    Wrong
  • 4
    15 days
    Correct
    Wrong
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Answer : 3. "13 days"
Explanation :

Answer: C) 13 days Explanation: Ratio of times taken by A and B = 100 : 130 = 10 : 13.Suppose B takes x days to do the work. Then, 10 : 13 :: 23 : x     =>     x = ( 23 x 13/10 )     =>     x = 299 /10. A's 1 day's work = 1/23 ;B's 1 day's work = 10/299 . (A + B)'s 1 day's work = ( 1/23 + 10/299 ) = 23/299 = 113 . Therefore, A and B together can complete the work in 13 days.

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