Quantitative Aptitude Practice Question and Answer
8Q: If 4 circles of equal radius are drawn with vertices of a square as the centre , the side of the square being 7 cm, find the area of the circles outside the square ? 1781 05b5cc718e4d2b4197774f490
5b5cc718e4d2b4197774f490- 1119.21 sq cmfalse
- 2115.395 sq cmtrue
- 3104.214 sq cmfalse
- 4111.241 sq cmfalse
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Answer : 2. "115.395 sq cm"
Explanation :
Answer: B) 115.395 sq cm Explanation: Because each vertice of the square is the center of a circle(1/4) part of the total area of each circle inside of the square.(3/4) part of the total area of each circle outside of the square.Thus total area outside the square is 434×227×3.5×3.5 = 115.3955 sq cm.
Q: A Bus is running at 9/10 of its own speed reached a place in 22 hours. How much time could be saved if the bus would run at its own speed ? 1780 05b5cc6dde4d2b4197774ea00
5b5cc6dde4d2b4197774ea00- 11.5 hrsfalse
- 21.7 hrsfalse
- 32.2 hrstrue
- 43.5 hrsfalse
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Answer : 3. "2.2 hrs"
Explanation :
Answer: C) 2.2 hrs Explanation: Let the original Speed be "s" kmphAnd the usual time be "t" hrsGiven that if the bus is running at 9s/10 kmph the time is 22 hrs=> [9s/10] x 22 = t x s=> 99/5 = t => t = 19.8 hrs Hence, if bus runs at its own speed, the time saved = 22 - 19.8 = 2.2 hrs.
Q: 30% of 500 rupees is? 1780 05b5cc690e4d2b4197774c460
5b5cc690e4d2b4197774c460- 1Rs. 180false
- 2Rs. 150true
- 3Rs. 120false
- 4Rs. 240false
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Answer : 2. "Rs. 150"
Explanation :
Answer: B) Rs. 150 Explanation: Given 30% of 500 = 30100 x 500= 30 x 5= 150 Hence, 30% of Rs. 500 = Rs. 150.
Q: The length, breadth and height of a room are in the ratio 7:3:1. If the breadth and height are doubled while the length is halved, then by what percent the total area of the 4 walls of the room will be increased ? 1777 05b5cc6c6e4d2b4197774de18
5b5cc6c6e4d2b4197774de18- 190%true
- 288%false
- 385%false
- 484%false
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Answer : 1. "90%"
Explanation :
Answer: A) 90% Explanation: Let length, breadth and height of the room be 7, 3, 1 unit respectively. Area of walls = 2(l+b)xh = 2(7+3)x1 = 20 sq. unit. Now, length, breadth and height of room will become 3.5, 6 and 2 respectively. Area of walls = 2(l+b)xh = 2(3.5+6)x2 = 38 sq. unit. % Increase in the area of walls = (38-20)x100/20 = 90%.
Q: The cost price of an article is 54% of the marked price. Calculate the gain percent after allowing a discount of 15% ? 1777 05b5cc6d6e4d2b4197774e660
5b5cc6d6e4d2b4197774e660- 151.32 %false
- 249.23 %false
- 348.4 %true
- 446.8 %false
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Answer : 3. "48.4 %"
Explanation :
Answer: C) 48.4 % Explanation: Let marked price = Rs. 100. Then, C.P. = RS. 54, S.P. = Rs. 85Gain % = 31/64 x 100 = 48.4%.
Q: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is 1776 05b5cc6d9e4d2b4197774e816
5b5cc6d9e4d2b4197774e816- 130false
- 236false
- 340true
- 442false
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Answer : 3. "40"
Explanation :
Answer: C) 40 Explanation: Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)On dividing (i) by (ii), we get: x = 40 km.
Q: 125 over 1000 in Simplest Form? 1776 05b5cc6abe4d2b4197774d034
5b5cc6abe4d2b4197774d034- 12/9false
- 21/8true
- 33/8false
- 44/7false
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Answer : 2. "1/8"
Explanation :
Answer: B) 1/8 Explanation: 125 over 1000 in Simplest Form means 1251000 in its simple fraction form. Now, to get the simplest form of 125/1000, find the HCF or GCD of both numerator and denominator i.e, 125 and 1000. HCF of 125, 1000 = 125 Then, divide both numerator and denominator by 125 i.e, 1251251000125 = 18 Hence, 18 is the simplest form of 125 over 1000.
Q: P alone can do a piece of work in 24 days. The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work. How many days are required to complete by P and Q working together ? 1776 05b5cc6c2e4d2b4197774dbaa
5b5cc6c2e4d2b4197774dbaa- 19 3/5 daystrue
- 27 daysfalse
- 36 3/7 daysfalse
- 48 daysfalse
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Answer : 1. "9 3/5 days"
Explanation :
Answer: A) 9 3/5 days Explanation: Let the total work be 'W' As per the given information, P can complete the work 'W' in 24 days. => one day work of P = W/24 And also given that, The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work => PW/3 = QW/2 => P's 1 day = W/24 ? = W/3 => ? = 24W/3W = 8 => QW/2 = 8 days => Q alone can complete the work W in 16 days => P + Q can complete the work in 1/24 + 1/16 = 5/48 => 48/5 days = 9 3/5 days.