Quantitative Aptitude Practice Question and Answer
8Q: Amar can do a piece of work in 10 days. He works at it for 4 days and then Arun finishes it in 9 days. In how many days can Amar and Arun together finish the work ? 5917 05b5cc6d6e4d2b4197774e66a
5b5cc6d6e4d2b4197774e66a- 14 daysfalse
- 28 daysfalse
- 33 daysfalse
- 46 daystrue
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Answer : 4. "6 days"
Explanation :
Answer: D) 6 days Explanation: 4/10 + 9/x = 1 => x = 15 Then both can do in 1/10 + 1/15 = 1/6 => 6 days
Q: If today is Saturday, what will be the day 350 days from now ? 5912 05b5cc6dbe4d2b4197774e8eb
5b5cc6dbe4d2b4197774e8eb- 1Saturdaytrue
- 2Fridayfalse
- 3Sundayfalse
- 4Mondayfalse
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Answer : 1. "Saturday"
Explanation :
Answer: A) Saturday Explanation: 350 days, 350/7 = 50, no odd days, so it will be a Saturday.
Q: A sum of Rs. 427 is to be divided among A, B and C in such a way that 3 times A’s share, 4 times B’s share and 7 times C’s share are all equal. The share of C is ? 5895 05b5cc72ce4d2b4197774f792
5b5cc72ce4d2b4197774f792- 164false
- 276false
- 384true
- 498false
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Answer : 3. "84"
Explanation :
Answer: C) 84 Explanation: Given total sum = Rs. 427And given that 3 times A’s share, 4 times B’s share and 7 times C’s share are all equal.=> 3A = 4B = 7CBut given=> A + B + C = 427Now express A and B in terms of C i.e=> (7C/3) + (7C/4) + C = 427=> C = 84
Q: What is the number of digits in 333? Given that log3 = 0.47712? 5872 05b5cc7d0e4d2b41977751209
5b5cc7d0e4d2b41977751209- 112false
- 213true
- 314false
- 415false
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Answer : 2. "13"
Explanation :
Answer: B) 13 Explanation: Let Let x=333 = 333 Then, logx = 33 log3 = 27 x 0.47712 = 12.88224 Since the characteristic in the resultant value of log x is 12 ∴The number of digits in x is (12 + 1) = 13 Hence the required number of digits in 333is 13.
Q: A group of 10 representatives is to be selected out of 12 seniors and 10 juniors. In how many different ways can the group be selected if it should have at least one senior ? 5848 05b5cc6eee4d2b4197774eed7
5b5cc6eee4d2b4197774eed7- 1²²C₁₀ + 1false
- 2²²C₉ + ¹⁰C₁false
- 3²²C₁₀false
- 4²²C₁₀ - 1true
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Answer : 4. "²²C₁₀ - 1"
Explanation :
Answer: D) ²²C₁₀ - 1 Explanation: The total number of ways of forming the group of ten representatives is ²²C₁₀. The total number of ways of forming the group that consists of no seniors is ¹⁰C₁₀ = 1 way The required number of ways = ²²C₁₀ - 1
Q: Cost price of 21 objects is equal to selling price of 15 objects. What is the profit? 5767 05d132f44925caa2d5bbbff66
5d132f44925caa2d5bbbff66- 125%false
- 230%false
- 333%false
- 440%true
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Answer : 4. "40%"
Q: Two persons start running simultaneously around a circular track of length 300 m from the same point at speeds of 15 km/hr and 25 km/hr. When will they meet for the first time any where on the track if they are moving in opposite directions ? 5751 05b5cc6e5e4d2b4197774ecf2
5b5cc6e5e4d2b4197774ecf2- 127 sectrue
- 231 secfalse
- 323 secfalse
- 429 secfalse
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Answer : 1. "27 sec"
Explanation :
Answer: A) 27 sec Explanation: Time taken to meet for the first time anywhere on the track = length of the track / relative speed = 300 / (15 + 25)5/18 = 300x 18 / 40 x 5 = 27 seconds.
Q: 7 9 19 18 31 29 Find the odd number in the given Number Series? 5747 05b5cc6b9e4d2b4197774d770
5b5cc6b9e4d2b4197774d770- 131false
- 229true
- 318false
- 419false
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Answer : 2. "29"
Explanation :
Answer: B) 29 Explanation: Here the given number series follows a pattern of two alternate series. 1. 7 19 31 ...(Difference of 12) 2. 9 18 27 ...(Difference of 9) Here the odd number is 29 instead of 27 And the next number is 31 + 12 = 43 & 27 + 9 = 36