Quantitative Aptitude Practice Question and Answer
8Q: Twelve children take sixteen days to complete a work which can be completed by 8 adults in 12 days. After working for 3 days, sixteen adults left and six adults and four children joined them. How many days will they take to complete the remaining work ? 1929 05b5cc758e4d2b4197774fbf9
5b5cc758e4d2b4197774fbf9- 13 daysfalse
- 22 daysfalse
- 36 daystrue
- 412 daysfalse
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Answer : 3. "6 days"
Explanation :
Answer: C) 6 days Explanation: From the given data, 12 children 16 days work,One child’s one day work = 1/192. 8 adults 12 days work,One adult’s one day’s work = 1/96. Work done in 3 days = ((1/96) x 16 x 3) = 1/2 Remaining work = 1 – 1/2 = 1/2 (6 adults+ 4 children)’s 1 day’s work = 6/96 + 4/192 = 1/12 1/12 work is done by them in 1 day. 1/2 work is done by them in 12 x (1/2) = 6 days.
Q: 50 men can build a tank in 40days, but though they begin the work together, 5 men quit every ten days. The time needed to build the tank is ? 1929 05b5cc76fe4d2b4197774ff71
5b5cc76fe4d2b4197774ff71- 150 daystrue
- 248 daysfalse
- 347.5 daysfalse
- 449 daysfalse
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Answer : 1. "50 days"
Explanation :
Answer: A) 50 days Explanation: 50 men can build a tank in 40 days Assume 1 man does 1 unit of work in 1 day Then the total work is 50×40 = 2000 units 50 men work in the first 10 days and completes 50×10 = 500 units of work 45 men work in the next 10 days and completes 45×10 = 450 units of work 40 men work in the next 10 days and completes 40×10 = 400 units of work 35 men work in the next 10 days and completes 35×10 = 350 units of work So far 500 + 450 + 400 + 350 = 1700 units of work is completed and Remaining work is 2000 - 1700 = 300 units 30 men work in the next 10 days. In each day, they does 30 units of work. Therefore, additional days required = 300/30 =10 Thus, total 10+10+10+10+10 = 50 days required.
Q: A trader marked the price of the T.V. 30% above the cost price of the T.V. and gave the purchaser 10% discount on the marked price, thereby gaining Rs.340. Find the cost price of the T.V ? 1928 05b5cc6e0e4d2b4197774eb9d
5b5cc6e0e4d2b4197774eb9d- 1Rs. 2000true
- 2Rs. 1600false
- 3Rs. 2200false
- 4Rs. 2100false
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Answer : 1. "Rs. 2000"
Explanation :
Answer: A) Rs. 2000 Explanation: Let 'x' be the cost price.Now Marked price = x + 30x/100 = 13x/1010% discount = 10/100 x 13x/10 = 13x/100 Selling price = 13x/10 - 13x/100 = 117x/100Given gain = 340Here gain = 117x/100 - x = 17x/100 = 340 => x = Rs. 2000.
Q: At an examination in which maximum marks are 500. P got 10% less than Q, Q got 25% more than R and R got 20% less than S. If P got 360 marks what percentage of marks was obtained by S ? 1928 05b5cc6c3e4d2b4197774dc54
5b5cc6c3e4d2b4197774dc54- 177false
- 274false
- 380true
- 483false
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Answer : 3. "80"
Explanation :
Answer: C) 80 Explanation: Let marks obtained by S = M R's marks = 0.80M Q's marks = 1.25 (0.80M) P's marks = (0.90) (1.25) (0.80M) = 0.9M But 0.9M = 360 M = ? M = 400 Hence % of marks obtained by S = 400/500 x 100 = 80%.
Q: An individual deposited 20% of 25% of 30% of what he had into his account with a bank. If he deposited Rs.750, how much was he having initially with him before depositing ? 1928 05b5cc71ee4d2b4197774f595
5b5cc71ee4d2b4197774f595- 1Rs. 38000false
- 2Rs. 47000false
- 3Rs. 50000true
- 4Rs. 35000false
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Answer : 3. "Rs. 50000"
Explanation :
Answer: C) Rs. 50000 Explanation: Let 'x' be the amount he had in the bank. => 20/100(25/100(30/100(x))) = 750 x = 750 x 8000/120 = Rs. 50000
Q: Find the next two numbers in the sequence 4, 12, 6, 18, 12, 26, 30, ?, ? 1927 05b5cc6b8e4d2b4197774d655
5b5cc6b8e4d2b4197774d655- 136 & 90true
- 290 & 41false
- 345 & 36false
- 441 & 36false
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Answer : 1. "36 & 90"
Explanation :
Answer: A) 36 & 90 Explanation: the next 2 number in series we need to divide the series into 2 different series First series : 4 , 6, 12, 30 ?? Second Series : 12,18,26, ?? So we need to see for the pattern for those series in order to find the next two number , we can do this by finding the difference or division , multiplication logic whatever may apply : Pattern of Series 1 : 6 divide 4 : 1.5 Next number i.e 12 divided by 6=2 Next number i.e 30 divided by 12 =2.5 So series is going in multiples of 1.5, 2, 2.5, 3 , so on So first series will look like 4 , 6, 12, 30, 30x3 =90 Pattern of Series 2 : 12,18,26, ?? Its simple Adding numbers with iterative logic (i.e 6, 8, then followed by 10, 12) Series will be like 12,18,26,36. For the next two numbers : Series will be like 4, 12, 6, 18, 12, 26, 30, 36, 90
Q: Laxmi and Prasanna set on a journey. Laxmi moves northwards at a speed of 20kmph and Prasanna moves southward at a speed of 30 kmph. How far will be Prasanna from Laxmi after 60 minutes ? 1924 05b5cc74fe4d2b4197774fae0
5b5cc74fe4d2b4197774fae0- 124 kmfalse
- 250 kmtrue
- 342 kmfalse
- 430 kmfalse
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Answer : 2. "50 km"
Explanation :
Answer: B) 50 km Explanation: We know 60 min = 1 hrTotal northward Laxmi's distance = 20kmph x 1hr = 20 kmTotal southward Prasanna's distance = 30kmph x 1hr = 30 kmTotal distance between Prasanna and Laxmi is = 20 + 30 = 50 km.
Q: A fair coin is tossed 11 times. What is the probability that only the first two tosses will yield heads ? 1921 05b5cc6c8e4d2b4197774df23
5b5cc6c8e4d2b4197774df23- 1(1/2)^11true
- 2(9)(1/2)false
- 3(11C2)(1/2)^9false
- 4(1/2)false
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Answer : 1. "(1/2)^11"
Explanation :
Answer: A) (1/2)^11 Explanation: Probability of occurrence of an event, P(E) = Number of favorable outcomes/Numeber of possible outcomes = n(E)/n(S) ⇒ Probability of getting head in one coin = ½, ⇒ Probability of not getting head in one coin = 1- ½ = ½, Hence, All the 11 tosses are independent of each other. ∴ Required probability of getting only 2 times heads =122×129=1211

