Quantitative Aptitude Practice Question and Answer
8Q: Calender Puzzle 1608 05b5cc6d5e4d2b4197774e629
5b5cc6d5e4d2b4197774e629- 1Afalse
- 2Bfalse
- 3Cfalse
- 4Dtrue
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Answer : 4. "D"
Explanation :
Answer: D) D Explanation: We can't determine the last day of the next month which has 31 days because we don't know the days in present month which may be 30 or 31. And the next month may be March which contains 31 days which implies that the present month may be February which contains 28 or 29 days.
Q: If 25% of a number is subtracted from a second number, the second number reduces to its four-sixth. What is the ratio of the first number to the second number ? 1605 05b5cc6dee4d2b4197774ea46
5b5cc6dee4d2b4197774ea46- 14:3true
- 22:3false
- 33:2false
- 45:3false
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Answer : 1. "4:3"
Explanation :
Answer: A) 4:3 Explanation: Let the numbers be p & q q-p/4 = 4q/6 => q-4q/6 = p/4 => 2q/6 = p/4 => p/q = 4/3
Q: Two pipes A and B can separately fill a cistern in 60 min and 75 min respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 min. In how much time, the third pipe alone can empty the cistern ? 1604 05b5cc6e7e4d2b4197774edb5
5b5cc6e7e4d2b4197774edb5- 185 minfalse
- 295 minfalse
- 3105 minfalse
- 4100 mintrue
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Answer : 4. "100 min"
Explanation :
Answer: D) 100 min Explanation: Work done by the third pipe in 1 min = 1/50 - (1/60 + 1/75) = - 1/100.[-ve sign means emptying] The third pipe alone can empty the cistern in 100 min.
Q: In a joint family, there are 24 members whose age is decreased by 4 months, when one girl aged 24 years is replaced by a new boy. Find the age of the new boy ? 1604 05b5cc6c5e4d2b4197774dd73
5b5cc6c5e4d2b4197774dd73- 118 yearsfalse
- 212 yearsfalse
- 315 yearsfalse
- 416 yearstrue
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Answer : 4. "16 years"
Explanation :
Answer: D) 16 years Explanation: Age of new boy = (Age of moved girl) – (Number of family members × Decreased in average) = 24 – 24×4/12 = 24 – 8 = 16 years.
Q: 5 + 2 x 10/2 = ? 1604 05b5cc6a6e4d2b4197774cd33
5b5cc6a6e4d2b4197774cd33- 115true
- 235false
- 310false
- 420false
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Answer : 1. "15"
Explanation :
Answer: A) 15 Explanation: Using BODMAS Rule, First solve division, mutiplication and Addition So here 10/2 = 5 Then 2 x 5 = 10 Now, 5 + 10 = 15. Hence, 5 + 2 x 10/2 = 15.
Q: One lady has 2 children, one of her child is boy, what is the probability of having both are boys ? 1603 05b5cc728e4d2b4197774f72d
5b5cc728e4d2b4197774f72d- 11/3true
- 21/2false
- 32/3false
- 42/5false
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Answer : 1. "1/3"
Explanation :
Answer: A) 1/3 Explanation: In a family with 2 children there are four possibilities:1) the first child is a boy and the second child is a boy (bb)2) the first child is a boy and the second child is a girl (bg)3) the first child is a girl and the second child is a boy (gb)4) the first child is a girl and the second child is a girl (gg) But already given that one child is boy. So we have three possibilities of (bb)(bg)(gb).n(E)= both are boys=BB=1n(S)= 3Required probability P = n(E)/n(S) = 1/3.
Q: 5 sin(x)+ 12 cos(x) + r is always greater than or equal to zero. What is the smallest value satisfied by 'r' ? 1600 05b5cc77fe4d2b419777501bf
5b5cc77fe4d2b419777501bf- 1-13false
- 211false
- 313true
- 4-11false
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Answer : 3. "13"
Explanation :
Answer: C) 13 Explanation: Given, 5sinx + 12cosx ≥ -r ⇒13513sin x + 1213cos x ≥ -rcosx) ≥ -r 513= cosA => sinA =1213 => 13(sinx cosA + sinA cosx) ≥ -r => 13(sin(x + A)) ≥ -r we know that , -1 ≤ sin (angle) ≤ 1 => 13sin (x + A) ≥ -13 ⇒rmin =13
Q: Maneela lent Rs. 8000 partly at the rate of 5% and partly at the rate of 6% per annum simple interest. The total interest she get after 2 years is Rs. 820, then in which ratio will Rs. 8000 is to be divided? 1599 05b5cc6bee4d2b4197774d9b5
5b5cc6bee4d2b4197774d9b5- 17:1true
- 213:5false
- 315:7false
- 42:7false
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Answer : 1. "7:1"
Explanation :
Answer: A) 7:1 Explanation: Maneela lent Rs. 8000 in two parts,

