Quantitative Aptitude Practice Question and Answer
8Q: Ajay and his wife Reshmi appear in an interview for two vaccancies in the same post. The Probability of Ajay's selection is 1/7 and that of his wife Reshmi's selection is 1/5. What is the probability that only one of them will be selected? 1914 05b5cc7d0e4d2b41977751222
5b5cc7d0e4d2b41977751222- 15/7false
- 21/5false
- 32/7true
- 42/35false
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Answer : 3. "2/7"
Explanation :
Answer: C) 2/7 Explanation: P( only one of them will be selected) = p[(E and not F) or (F and not E)] = PE∩F∪F∩E = PEPF+PFPE =17×45+15×67=27
Q: Lucky started working 2 years ago. Her starting salary was half of Karthik's salary at that time. Each year since then Lucky and Karthik have received a rise of 10% in their respective salary. What percentage (to the nearest percent) of Karthik's current salary is Lucky's current salary ? 1913 05b5cc6cfe4d2b4197774e2f9
5b5cc6cfe4d2b4197774e2f9- 175%false
- 222.5%false
- 335%false
- 450%true
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Answer : 4. "50%"
Explanation :
Answer: D) 50% Explanation: Let the salary of Karthik 2 years ago be Rs.100So, Lucky's salary 2 years ago was Rs.50 Karthik's present salary has seen two 10 percent increases. So as Lucky's salary. So, Karthik's salary 1 year ago = 100 + 10% of 100 = 100 + 10 = 110.Karthik's present salary = 110 + 10% of 110 = 110 + 11 = 121. Lucky's salary 1 year ago = 50 + 10% of 50 = 50 + 5 = 55Lucky's present salary = 55 + 10% of 55 = 55 + 5.5 = 60.5 Lucky's present salary of 60.5 = 50% of Karthik's present salary of 121.
Q: Three friends had dinner at a restaurant. When the bill was received, Akshitha paid 2/3 as much as Veena paid and Veena paid 1/2 as much as Lasya paid. What fraction of the bill did Veena pay ? 1911 05b5cc71ee4d2b4197774f5ae
5b5cc71ee4d2b4197774f5ae- 111/3false
- 22/13false
- 33/11true
- 413/4false
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Answer : 3. "3/11"
Explanation :
Answer: C) 3/11 Explanation: Let Veena paid x,so Akshitha paid 2x/3 , and Lasya paid 2x,So total bill paid is given byx+(2x/3) +2x = 1, we geti.e. x = 3/11
Q: One lady has 2 children, one of her child is boy, what is the probability of having both are boys ? 1911 05b5cc728e4d2b4197774f72d
5b5cc728e4d2b4197774f72d- 11/3true
- 21/2false
- 32/3false
- 42/5false
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Answer : 1. "1/3"
Explanation :
Answer: A) 1/3 Explanation: In a family with 2 children there are four possibilities:1) the first child is a boy and the second child is a boy (bb)2) the first child is a boy and the second child is a girl (bg)3) the first child is a girl and the second child is a boy (gb)4) the first child is a girl and the second child is a girl (gg) But already given that one child is boy. So we have three possibilities of (bb)(bg)(gb).n(E)= both are boys=BB=1n(S)= 3Required probability P = n(E)/n(S) = 1/3.
Q: How many 4-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHMS', if repetition of letters is not allowed ? 1911 05b5cc731e4d2b4197774f805
5b5cc731e4d2b4197774f805- 15040true
- 22525false
- 32052false
- 44521false
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Answer : 1. "5040"
Explanation :
Answer: A) 5040 Explanation: The Word LOGARITHMS contains 10 letters. To find how many 4 letter words we can form from that = P410 =10x9x8x7 = 5040.
Q: A Bus travels first half distance between two places with a speed of 40 kmph and the rest half distance with a speed of 60 kmph. The average speed of the Bus is ? 1911 05b5cc764e4d2b4197774fda3
5b5cc764e4d2b4197774fda3- 148 kmphtrue
- 250 kmphfalse
- 346 kmphfalse
- 442 kmphfalse
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Answer : 1. "48 kmph"
Explanation :
Answer: A) 48 kmph Explanation: we know that speed = distance traveled/time takenlet the total distance traveled by the car is 2x km.then time taken by it to cover first half is x/60 hour.and for second half is x/40 hour.Then average speed= total distance travelled / total time taken. i.e. 2xx60+x40 => 2x5x120 = 48 kmph.
Q: Out of seven consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed ? 1909 05b5cc774e4d2b41977750007
5b5cc774e4d2b41977750007- 125200true
- 225000false
- 325225false
- 424752false
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Answer : 1. "25200"
Explanation :
Answer: A) 25200 Explanation: Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4) =( C37×C24 ) = 210. Number of groups, each having 3 consonants and 2 vowels =210 Each group contains 5 letters. Number of ways of arranging 5 letters among themselves = 5! = 120. Required number of words = (210 x 120) = 25200.
Q: The cost price of an article is 54% of the marked price. Calculate the gain percent after allowing a discount of 15% ? 1906 05b5cc6d6e4d2b4197774e660
5b5cc6d6e4d2b4197774e660- 151.32 %false
- 249.23 %false
- 348.4 %true
- 446.8 %false
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Answer : 3. "48.4 %"
Explanation :
Answer: C) 48.4 % Explanation: Let marked price = Rs. 100. Then, C.P. = RS. 54, S.P. = Rs. 85Gain % = 31/64 x 100 = 48.4%.