Quantitative Aptitude Practice Question and Answer
8Q: The perimeter of a square is equal to twice the perimeter of a rectangle of length 8cm and breadth 7cm. What is the circumference of a semicircle whose diameter is equal to the side of the square ? 1896 05b5cc736e4d2b4197774f841
5b5cc736e4d2b4197774f841- 155.12 cmfalse
- 222.54 cmfalse
- 342.51 cmfalse
- 438.57 cmtrue
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Answer : 4. "38.57 cm"
Explanation :
Answer: D) 38.57 cm Explanation: We know that perimeter of rectangle = 2(l+b) = 2(8+7)= 30cmGiven perimeter of square is twice the perimeter of rectangle = 2(30) = 60cmTherefore, side of the square is = 1/4 x 60 = 15cmCircumference of the required semicircle = πr + 2r = 227× 152 + 2×152 = 23.57 + 15 = 38.57cm.
Q: A train 125 m long passes a man, running at 4 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is: 1896 05b5cc6d6e4d2b4197774e65b
5b5cc6d6e4d2b4197774e65b- 149 kmphtrue
- 250 kmphfalse
- 351 kmphfalse
- 452 kmphfalse
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Answer : 1. "49 kmph"
Explanation :
Answer: A) 49 kmph Explanation: Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) x (18/5)] km/hr = 45 km/hr. Let the speed of the train be 'x' km/hr. Then, relative speed = (x - 4) km/hr. x - 4 = 45 => x = 49 km/hr.
Q: In a competitive examination, the average marks for the entire examination was 60 marks. If 20% of the applicants scored 85 marks and 25% scored 95 marks. What was the average marks of the remaining applicants in the examination ? 1892 05b5cc76fe4d2b4197774ff7b
5b5cc76fe4d2b4197774ff7b- 160false
- 252false
- 345false
- 435true
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Answer : 4. "35"
Explanation :
Answer: D) 35 Explanation: Let the total applicants be 100 Then, 20% got 85 marks i.e 20 x 85 = 1700 and 25% got 95 marks i.e 25 x 95 = 2375 Now, the remaining applicants are 55 and let the average marks scored by them be x. Therefore, 2375 + 1700 + 55x = 60×100 6000 - 4075 = 55x 55x=1925 x=35.
Q: There are 3 bags, in 1st there are 9 Mangoes, in 2nd 8 apples & in 3rd 6 bananas. There are how many ways you can buy one fruit if all the mangoes are identical, all the apples are identical, & also all the Bananas are identical ? 1892 05b5cc705e4d2b4197774f253
5b5cc705e4d2b4197774f253- 123true
- 2432false
- 322false
- 4431false
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Answer : 1. "23"
Explanation :
Answer: A) 23 Explanation: As in this problem , buying any fruit is different case , as buying apple is independent from buying banana. so ADDITION rule will be used. C19+C18+C16 = 23 will be answer.
Q: The mean of 100 observations is 40. It is found that an observation 84 was misread as 48. Then the correct mean is ? 1890 05b5cc6c0e4d2b4197774dab2
5b5cc6c0e4d2b4197774dab2- 140.36true
- 241.24false
- 341.92false
- 442.05false
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Answer : 1. "40.36"
Explanation :
Answer: A) 40.36 Explanation: Given, mean of 100 observations is 40 => Total of 100 observations = 40 x 100 = 4000 84 is misread as 48 => Difference = 84 - 48 = 36 => Now, new total of 100 observations = 4000 + 36 = 4036 Correct Mean = 4036/100 = 40.36
Q: The total simple interest earned on a sum of money increases by Rs. 600 when the rate of interest increases by 2% per annum. If the investment was made for 5 years, find the sum of money that was invested ? 1890 05b5cc6cae4d2b4197774e03b
5b5cc6cae4d2b4197774e03b- 1Rs. 6000true
- 2Rs. 5550false
- 3Rs. 7500false
- 4Rs. 6580false
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Answer : 1. "Rs. 6000"
Explanation :
Answer: A) Rs. 6000 Explanation: Let the sum invested be Rs. P Let the rate of interest be R% per annum => Interest earned for 5 years = (P x 5 x R/100) = PR/20 Now, given that the interest earned increased by Rs. 600 if the Rate increased to (R+2)% => SI = (P x 5 x (R+2))/100 = PR/20 + 10P/100 Hence, PR/20 + 10P/100 = PR/20 + 600 => P = 6000 Therefore, the sum invested is Rs. 6000
Q: In a bag, there are 8 red, 7 blue and 6 green flowers. One of the flower is picked up randomly. What is the probability that it is neither red nor green ? 1889 05b5cc774e4d2b41977750016
5b5cc774e4d2b41977750016- 113true
- 2821false
- 3621false
- 42021false
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Answer : 1. "13"
Explanation :
Answer: A) Option A Explanation: Total number of flowers = (8+7+6) = 21. Let E = event that the flower drawn is neither red nor green. = event taht the flower drawn is blue. --> n(E)= 7 --> P(E)= 721=13
Q: Second & fourth Saturdays and every Sunday is a holiday. How many working days will be there in a month of 31 days beginning on a Friday ? 1889 05b5cc6d0e4d2b4197774e338
5b5cc6d0e4d2b4197774e338- 124true
- 223false
- 322false
- 425false
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Answer : 1. "24"
Explanation :
Answer: A) 24 Explanation: Given that the month begins on a Friday and has 31 days Sundays = 3rd, 10th, 17th, 24th, 31st=> Total Sundays = 5 Every second & fourth Saturday is holiday. 2nd & 4th Saturday in every month = 2 Total days in the month = 31 Total working days = 31 - (5 + 2) = 24 days.