Quantitative Aptitude Practice Question and Answer
8Q: If every seconds Saturday and all Sundays are holidays in a 30 days month beginning on Saturday, then how many working days are there in that month ? (Month starts from Saturday) 1591 05b5cc6f8e4d2b4197774f054
5b5cc6f8e4d2b4197774f054- 125false
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Answer : 4. "23"
Explanation :
Answer: D) 23 Explanation: As month begins on Saturday, so 2nd, 9th, 16th, 23rd, 30th days will be Sundays. While 8th and 22nd days are second Saturdays. Thus, there are 7 holidays in all. Hence, no. of working days = 30 – 7 =23
Q: Manideep purchases 30kg of barley at the rate of 11.50/kg and 20kg at the rate of 14.25/kg. He mixed the two and sold the mixture in the shop. At what price per kg should he sell the mixture to make 30% profit to him ? 1590 05b5cc6c5e4d2b4197774ddc3
5b5cc6c5e4d2b4197774ddc3- 115.84false
- 214.92false
- 313.98false
- 416.38true
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Answer : 4. "16.38"
Explanation :
Answer: D) 16.38 Explanation: Given, Manideep purchases 30kg of barley at the rate of 11.50/kg nad 20kg at the rate of 14.25/kg. Total cost of the mixture of barley = (30 x 11.50) + (20 x 14.25) => Total cost of the mixture = Rs. 630 Total kgs of the mixture = 30 + 20 = 50kg Cost of mixture/kg = 630/50 = 12.6/kg To make 30% of profit => Selling price for manideep = 12.6 + 30% x 12.6 => Selling price for manideep = 12.6 + 3.78 = 16.38/kg.
Q: A sum is equally invested in two different schemes on CI at the rate of 15% and 20% for two years. If interest gained from the sum invested at 20% is Rs. 528.75 more than the sum invested at 15%, find the total sum? 1590 05b5cc658e4d2b4197774bde2
5b5cc658e4d2b4197774bde2- 1Rs. 7000false
- 2Rs. 4500false
- 3Rs. 9000true
- 4Rs. 8200false
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Answer : 3. "Rs. 9000"
Explanation :
Answer: C) Rs. 9000 Explanation: Let Rs. K invested in each scheme Two years C.I on 20% = 20 + 20 + 20x20/100 = 44% Two years C.I on 15% = 15 + 15 + 15x15/100 = 32.25% Now, (P x 44/100) - (P x 32.25/100) = 528.75 => 11.75 P = 52875 => P = Rs. 4500 Hence, total invested money = P + P = 4500 + 4500 = Rs. 9000.
Q: After working for 8 days, Arun finds that only 13 rd of the work has been done. He employs Akhil who is 60% as efficient as Arun. How many days more would Akhil take to complete the work? 1590 05b5cc76fe4d2b4197774ff67
5b5cc76fe4d2b4197774ff67- 124.5 daysfalse
- 226.6 daystrue
- 325 daysfalse
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Answer : 2. "26.6 days"
Explanation :
Answer: B) 26.6 days Explanation: Arun has completed 13rd of the work in 8 days Then he can complete the total work in 13 ---- 8 1 ---- ? = 24 days But given Akhil is only 60% as efficient as Arun Akhil =124×60100=140 Akhil can complete the total work in 40 days Now, remaining 2/3rd of work can be completed in 1 ------ 40 23 ------ ? = 26.66 days.
Q: What is 15 of 80 with simple method and examples? 1589 05b5cc6b3e4d2b4197774d46d
5b5cc6b3e4d2b4197774d46d- 112.5%false
- 218.75%true
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Answer : 2. "18.75%"
Explanation :
Answer: B) 18.75% Explanation: Given that to find 15 of 80 => What % of 80 is 15 Let it be 'p' => p% of 80 = 15 => p x 80100 = 15⇒p = 15 x 10080⇒p = 150080 = 18.75 Therefore, 15 is 18.75% of 80 => 18.75% of 80 = 15 Example:: Now, in the similar way we can find 15% of 80 =? => 15x80/100 = p => p = 4 x 3 = 12 Therefore, 15% of 80 = 12
Q: A room contains 3 brown, 5 black and 4 white chairs. Two chairs are picked and are put in the lawn. What is the probability that none of the chairs picked is white ? 1588 05b5cc6c5e4d2b4197774ddbe
5b5cc6c5e4d2b4197774ddbe- 114/33true
- 214/55false
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Answer : 1. "14/33"
Explanation :
Answer: A) 14/33 Explanation: Total number of chairs = (3 + 5 + 4) = 12. Let S be the sample space. Then, n(s)= Number of ways of picking 2 chairs out of 12 = 12×11/2×1 = 66 Let n(E) = number of events of selecting 2 chairs for selecting no white chairs. => 8C2 = 8×7/2×1 = 28 Therefore required probability = 28/66 = 14/33.
Q: A class is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the class room ? 1587 05b5cc6e7e4d2b4197774ed6a
5b5cc6e7e4d2b4197774ed6a- 1115false
- 2117true
- 3116false
- 4114false
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Answer : 2. "117"
Explanation :
Answer: B) 117 Explanation: Length = 6 m 24 cm = 624 cmWidth = 4 m 32 cm = 432 cmHCF of 624 and 432 = 48Number of square tiles required = (624 x 432)/(48 x 48) = 13 x 9 = 117.
Q: In a competitive examination, the average marks for the entire examination was 60 marks. If 20% of the applicants scored 85 marks and 25% scored 95 marks. What was the average marks of the remaining applicants in the examination ? 1587 05b5cc76fe4d2b4197774ff7b
5b5cc76fe4d2b4197774ff7b- 160false
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Answer : 4. "35"
Explanation :
Answer: D) 35 Explanation: Let the total applicants be 100 Then, 20% got 85 marks i.e 20 x 85 = 1700 and 25% got 95 marks i.e 25 x 95 = 2375 Now, the remaining applicants are 55 and let the average marks scored by them be x. Therefore, 2375 + 1700 + 55x = 60×100 6000 - 4075 = 55x 55x=1925 x=35.