Quantitative Aptitude Practice Question and Answer

Q: If 5 men and 2 boys working together, can do four times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time  ? 1967 0

  • 1
    1:2
    Correct
    Wrong
  • 2
    1:3
    Correct
    Wrong
  • 3
    3:1
    Correct
    Wrong
  • 4
    2:1
    Correct
    Wrong
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Answer : 4. "2:1"
Explanation :

Answer: D) 2:1 Explanation: 5M + 2B = 4(1M + 1B) 5M + 2B = 4M + 4B 1M = 2B The required ratio of work done by a man and a boy = 2:1

Q: A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ? 1963 0

  • 1
    45, 10
    Correct
    Wrong
  • 2
    10, 50
    Correct
    Wrong
  • 3
    9, 50
    Correct
    Wrong
  • 4
    50, 15
    Correct
    Wrong
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Answer : 3. "9, 50"
Explanation :

Answer: C) 9, 50 Explanation: Let the age of A = A, B = B and C = C From given A = 3B 4 years ago, C-4 = 2(A-4); After 4 years A + 4 = 31; A = 27;sub in above B, we get B = 9 C = 2(27 - 4) + 4 = 46 + 4 = 50 Hence B = 9yrs and C = 50yrs.

Q: A jeep travels a certain distance taking 6 hrs in forward journey, during the return journey increased speed 12km/hr takes the times 4 hrs. What is the distance travelled by the jeep is ? 1963 0

  • 1
    244 km
    Correct
    Wrong
  • 2
    144 km
    Correct
    Wrong
  • 3
    444 km
    Correct
    Wrong
  • 4
    344 km
    Correct
    Wrong
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Answer : 2. "144 km"
Explanation :

Answer: B) 144 km Explanation: Given a jeep travels a certain distance taking 6 hrs in forward journeyDuring the return journey, it takes 4 hrs with an increased speed 12 km/hrLet 'x' be the distance.Now, speed is given by distance/time.Here the difference between both speeds = 12  x4 - x6 = 12  3x - 2x12 = 12   => x = 144 km   Therefore, the distance travelled by the jeep in forward or return journey is x = 144 km.

Q: Find the odd one in the number series given below ? 17, 9, 10, 18.5, 35, 90 1962 0

  • 1
    9
    Correct
    Wrong
  • 2
    10
    Correct
    Wrong
  • 3
    18.5
    Correct
    Wrong
  • 4
    90
    Correct
    Wrong
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Answer : 3. "18.5"
Explanation :

Answer: C) 18.5 Explanation: The given series pattern follows   17       9       10       18.5       35       90   × 0.5 + 0.5,   × 1 + 1,   × 1.5 + 1.5,   × 2 + 2,   × 2.5 + 2.5   So here    17x0.5 + 0.5 = 9   9x1 + 1 = 10   10x1.5 + 1.5 = 16.5   16.5x2 + 2 = 35   35x2.5 + 2.5 = 90   Here the odd man in the given series is 18.5

Q: The total simple interest earned on a sum of money increases by Rs. 600 when the rate of interest increases by 2% per annum. If the investment was made for 5 years, find the sum of money that was invested ? 1961 0

  • 1
    Rs. 6000
    Correct
    Wrong
  • 2
    Rs. 5550
    Correct
    Wrong
  • 3
    Rs. 7500
    Correct
    Wrong
  • 4
    Rs. 6580
    Correct
    Wrong
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Answer : 1. "Rs. 6000"
Explanation :

Answer: A) Rs. 6000 Explanation: Let the sum invested be Rs. P Let the rate of interest be R% per annum => Interest earned for 5 years = (P x 5 x R/100) = PR/20 Now, given that the interest earned increased by Rs. 600 if the Rate increased to (R+2)% => SI = (P x 5 x (R+2))/100 = PR/20 + 10P/100 Hence, PR/20 + 10P/100 = PR/20 + 600 => P = 6000 Therefore, the sum invested is Rs. 6000

Q: 74.99% of 1299 + 8.98% of 1899 = ? 1960 0

  • 1
    1378
    Correct
    Wrong
  • 2
    1301
    Correct
    Wrong
  • 3
    1212
    Correct
    Wrong
  • 4
    1197
    Correct
    Wrong
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Answer : 3. "1212"
Explanation :

Answer: C) 1212 Explanation: 74.99% of 1299 + 8.98% of 1899 = ?  ? = 75 x 1400100 + 9 x 1800100 ? = 1050 + 162? = 1212.

Q: One lady has 2 children, one of her child is boy, what is the probability of having both are boys ? 1960 0

  • 1
    1/3
    Correct
    Wrong
  • 2
    1/2
    Correct
    Wrong
  • 3
    2/3
    Correct
    Wrong
  • 4
    2/5
    Correct
    Wrong
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Answer : 1. "1/3"
Explanation :

Answer: A) 1/3 Explanation: In a family with 2 children there are four possibilities:1) the first child is a boy and the second child is a boy (bb)2) the first child is a boy and the second child is a girl (bg)3) the first child is a girl and the second child is a boy (gb)4) the first child is a girl and the second child is a girl (gg) But already given that one child is boy. So we have three possibilities of (bb)(bg)(gb).n(E)= both are boys=BB=1n(S)= 3Required probability P = n(E)/n(S) = 1/3.

Q: A man sell 35 waffers for Rs. 15 each and loses Rs. 40.4. If he sells 35 waffers for Rs. 18, how much does he loss or gain ? 1959 1

  • 1
    Rs. 64
    Correct
    Wrong
  • 2
    Rs. 52
    Correct
    Wrong
  • 3
    Rs. 72
    Correct
    Wrong
  • 4
    Rs. 55
    Correct
    Wrong
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Answer : 1. "Rs. 64"
Explanation :

Answer: A) Rs. 64 Explanation: Given Loss = Rs. 40.4We know loss = cost price - selling price 40.4 = CP - 35(15)=> CP = 40.4 + 525=> CP = Rs. 565.4Now the New selling price of waffer is Rs. 18=> SP = 35(18) = 630Now Gain = SP - CP = 630 -565.4 = Rs. 64.6.

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