Quantitative Aptitude Practice Question and Answer
8Q: In how many different ways can the letters of the word 'THERAPY' be arranged so that the vowels never come together? 1879 05b5cc69de4d2b4197774c919
5b5cc69de4d2b4197774c919- 11440false
- 2720false
- 32250false
- 43600true
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Answer : 4. "3600"
Explanation :
Answer: D) 3600 Explanation: Given word is THERAPY. Number of letters in the given word = 7 These 7 letters can be arranged in 7! ways. Number of vowels in the given word = 2 (E, A) The number of ways of arrangement in which vowels come together is 6! x 2! ways Hence, the required number of ways can the letters of the word 'THERAPY' be arranged so that the vowels never come together = 7! - (6! x 2!) ways = 5040 - 1440 = 3600 ways.
Q: Excluding the stoppages, the speed of a bus is 64 km/hr and including the stoppages the speed o the bus is 48km/hr. For how many minutes does the bus stop per hour? 1879 05b5cc7c7e4d2b41977750daa
5b5cc7c7e4d2b41977750daa- 112.5 minutesfalse
- 215 minutestrue
- 310 minutesfalse
- 418 minutesfalse
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Answer : 2. "15 minutes"
Explanation :
Answer: B) 15 minutes Explanation:
Q: Calender Puzzle 1878 05b5cc6d5e4d2b4197774e629
5b5cc6d5e4d2b4197774e629- 1Afalse
- 2Bfalse
- 3Cfalse
- 4Dtrue
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Answer : 4. "D"
Explanation :
Answer: D) D Explanation: We can't determine the last day of the next month which has 31 days because we don't know the days in present month which may be 30 or 31. And the next month may be March which contains 31 days which implies that the present month may be February which contains 28 or 29 days.
Q: The difference between circumference and semidiameter of a circle is 37 cm. What is the diameter of the circle ? 1875 05b5cc6c6e4d2b4197774de27
5b5cc6c6e4d2b4197774de27- 118 cmfalse
- 212 cmfalse
- 316 cmfalse
- 414 cmtrue
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Answer : 4. "14 cm"
Explanation :
Answer: D) 14 cm Explanation: circumference of a circle = 2πr => 2 × 22/7 × r – r = 37 => 37/7 × r = 37 => r = 7 cm. Diameter D = 2r = 7×2 = 14 cm.
Q: Two pipes A and B can separately fill a cistern in 60 min and 75 min respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 min. In how much time, the third pipe alone can empty the cistern ? 1874 05b5cc6e7e4d2b4197774edb5
5b5cc6e7e4d2b4197774edb5- 185 minfalse
- 295 minfalse
- 3105 minfalse
- 4100 mintrue
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Answer : 4. "100 min"
Explanation :
Answer: D) 100 min Explanation: Work done by the third pipe in 1 min = 1/50 - (1/60 + 1/75) = - 1/100.[-ve sign means emptying] The third pipe alone can empty the cistern in 100 min.
Q: Find the odd one in the number series given below ? 17, 9, 10, 18.5, 35, 90 1874 05b5cc6c5e4d2b4197774dd91
5b5cc6c5e4d2b4197774dd91- 19false
- 210false
- 318.5true
- 490false
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Answer : 3. "18.5"
Explanation :
Answer: C) 18.5 Explanation: The given series pattern follows 17 9 10 18.5 35 90 × 0.5 + 0.5, × 1 + 1, × 1.5 + 1.5, × 2 + 2, × 2.5 + 2.5 So here 17x0.5 + 0.5 = 9 9x1 + 1 = 10 10x1.5 + 1.5 = 16.5 16.5x2 + 2 = 35 35x2.5 + 2.5 = 90 Here the odd man in the given series is 18.5
Q: A man walks at a speed of 2 km/hr and runs at a speed of 6 km/hr. How much time will the man require to cover a distance of 20 1/2 km, if he completes half of the distance, i.e., (10 1/4) km on foot and the other half by running ? 1872 05b5cc6dfe4d2b4197774eaf8
5b5cc6dfe4d2b4197774eaf8- 112.4 hrsfalse
- 211.9 hrstrue
- 310.7 hrsfalse
- 49.9 hrsfalse
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Answer : 2. "11.9 hrs"
Explanation :
Answer: B) 11.9 hrs Explanation: We know that Time = Distance/speedRequired time = (10 1/4)/2 + (10 1/4)/6 = 41/8 + 41/6= 287/24 = 11.9 hours.
Q: A sum is equally invested in two different schemes on CI at the rate of 15% and 20% for two years. If interest gained from the sum invested at 20% is Rs. 528.75 more than the sum invested at 15%, find the total sum? 1872 05b5cc658e4d2b4197774bde2
5b5cc658e4d2b4197774bde2- 1Rs. 7000false
- 2Rs. 4500false
- 3Rs. 9000true
- 4Rs. 8200false
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Answer : 3. "Rs. 9000"
Explanation :
Answer: C) Rs. 9000 Explanation: Let Rs. K invested in each scheme Two years C.I on 20% = 20 + 20 + 20x20/100 = 44% Two years C.I on 15% = 15 + 15 + 15x15/100 = 32.25% Now, (P x 44/100) - (P x 32.25/100) = 528.75 => 11.75 P = 52875 => P = Rs. 4500 Hence, total invested money = P + P = 4500 + 4500 = Rs. 9000.

