Quantitative Aptitude Practice Question and Answer
8 Q: Simplification the following equations shown below
1796 05d4a95c9822faf1e4e7fd6ad
5d4a95c9822faf1e4e7fd6ad- 11512false
- 21521true
- 31251false
- 41531false
- 5None of thesefalse
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Answer : 2. "1521"
Q: 1/8 as a decimal? 1794 05b5cc6a6e4d2b4197774cd6f
5b5cc6a6e4d2b4197774cd6f- 10.125true
- 20.225false
- 30.325false
- 40.425false
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Answer : 1. "0.125"
Explanation :
Answer: A) 0.125 Explanation: 1/8 to convert into decimal, Find an equivalent fraction with a denominator of a power of 10. In this case, we will use 1000. 18 x 125125 = 1251000 This can now be written as a decimal with 3 decimal places (because we have thousandths. i.e, 0.125 Hence, 18 as a decimal = 0.125
Q: 5 + 2 x 10/2 = ? 1792 05b5cc6a6e4d2b4197774cd33
5b5cc6a6e4d2b4197774cd33- 115true
- 235false
- 310false
- 420false
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Answer : 1. "15"
Explanation :
Answer: A) 15 Explanation: Using BODMAS Rule, First solve division, mutiplication and Addition So here 10/2 = 5 Then 2 x 5 = 10 Now, 5 + 10 = 15. Hence, 5 + 2 x 10/2 = 15.
Q: In a joint family, there are 24 members whose age is decreased by 4 months, when one girl aged 24 years is replaced by a new boy. Find the age of the new boy ? 1791 05b5cc6c5e4d2b4197774dd73
5b5cc6c5e4d2b4197774dd73- 118 yearsfalse
- 212 yearsfalse
- 315 yearsfalse
- 416 yearstrue
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Answer : 4. "16 years"
Explanation :
Answer: D) 16 years Explanation: Age of new boy = (Age of moved girl) – (Number of family members × Decreased in average) = 24 – 24×4/12 = 24 – 8 = 16 years.
Q: A sum is equally invested in two different schemes on CI at the rate of 15% and 20% for two years. If interest gained from the sum invested at 20% is Rs. 528.75 more than the sum invested at 15%, find the total sum? 1790 05b5cc658e4d2b4197774bde2
5b5cc658e4d2b4197774bde2- 1Rs. 7000false
- 2Rs. 4500false
- 3Rs. 9000true
- 4Rs. 8200false
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Answer : 3. "Rs. 9000"
Explanation :
Answer: C) Rs. 9000 Explanation: Let Rs. K invested in each scheme Two years C.I on 20% = 20 + 20 + 20x20/100 = 44% Two years C.I on 15% = 15 + 15 + 15x15/100 = 32.25% Now, (P x 44/100) - (P x 32.25/100) = 528.75 => 11.75 P = 52875 => P = Rs. 4500 Hence, total invested money = P + P = 4500 + 4500 = Rs. 9000.
Q: In a competitive examination, the average marks for the entire examination was 60 marks. If 20% of the applicants scored 85 marks and 25% scored 95 marks. What was the average marks of the remaining applicants in the examination ? 1789 05b5cc76fe4d2b4197774ff7b
5b5cc76fe4d2b4197774ff7b- 160false
- 252false
- 345false
- 435true
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Answer : 4. "35"
Explanation :
Answer: D) 35 Explanation: Let the total applicants be 100 Then, 20% got 85 marks i.e 20 x 85 = 1700 and 25% got 95 marks i.e 25 x 95 = 2375 Now, the remaining applicants are 55 and let the average marks scored by them be x. Therefore, 2375 + 1700 + 55x = 60×100 6000 - 4075 = 55x 55x=1925 x=35.
Q: A man sell 35 waffers for Rs. 15 each and loses Rs. 40.4. If he sells 35 waffers for Rs. 18, how much does he loss or gain ? 1789 15b5cc74ae4d2b4197774fa95
5b5cc74ae4d2b4197774fa95- 1Rs. 64true
- 2Rs. 52false
- 3Rs. 72false
- 4Rs. 55false
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Answer : 1. "Rs. 64"
Explanation :
Answer: A) Rs. 64 Explanation: Given Loss = Rs. 40.4We know loss = cost price - selling price 40.4 = CP - 35(15)=> CP = 40.4 + 525=> CP = Rs. 565.4Now the New selling price of waffer is Rs. 18=> SP = 35(18) = 630Now Gain = SP - CP = 630 -565.4 = Rs. 64.6.
Q: The perimeter of a square is equal to twice the perimeter of a rectangle of length 8cm and breadth 7cm. What is the circumference of a semicircle whose diameter is equal to the side of the square ? 1786 05b5cc736e4d2b4197774f841
5b5cc736e4d2b4197774f841- 155.12 cmfalse
- 222.54 cmfalse
- 342.51 cmfalse
- 438.57 cmtrue
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Answer : 4. "38.57 cm"
Explanation :
Answer: D) 38.57 cm Explanation: We know that perimeter of rectangle = 2(l+b) = 2(8+7)= 30cmGiven perimeter of square is twice the perimeter of rectangle = 2(30) = 60cmTherefore, side of the square is = 1/4 x 60 = 15cmCircumference of the required semicircle = πr + 2r = 227× 152 + 2×152 = 23.57 + 15 = 38.57cm.