Quantitative Aptitude Practice Question and Answer
8Q: In how many different ways can the letters of the word 'HAPPYHOLI' be arranged? 1794 05b5cc6a7e4d2b4197774ce0e
5b5cc6a7e4d2b4197774ce0e- 189,972false
- 290,720true
- 372,000false
- 481,000false
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Answer : 2. "90,720"
Explanation :
Answer: B) 90,720 Explanation: The given word HAPPYHOLI has 9 letters These 9 letters can e arranged in 9! ways. But here in the given word letters H & P are repeated twice each Therefore, Number of ways these 9 letters can be arranged is 9!2! x 2! = 9 x 8 x 7 x 6 x 5 x 4 x 32 = 90,720 ways.
Q: If 35% of a number is 24 less than 50% of that number, then the number is ? 1794 05b5cc6e1e4d2b4197774eba2
5b5cc6e1e4d2b4197774eba2- 180false
- 2160true
- 3100false
- 4120false
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Answer : 2. "160"
Explanation :
Answer: B) 160 Explanation: Let the number be n. Then, 50% of n - 35% of n = 24 50/100 n - 35/100 n = 24 n = (24 x 100)/15 = 160.
Q: A person lends Rs. 1540 for five years and Rs. 1800 for four years. If he gets Rs. 1788 as interest on both amounts, what is the rate of interest ? 1792 05b5cc6c8e4d2b4197774deec
5b5cc6c8e4d2b4197774deec- 114.5%false
- 211%false
- 312%true
- 410.5%false
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Answer : 3. "12%"
Explanation :
Answer: C) 12% Explanation: Let the interest rate be r% We know that, S.I = PTR/100 => (1540 x 5 x r)/100 + (1800 x 4 x r)/100 = 1788 => r = 178800/14900 = 12%
Q: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B ? 1790 05b5cc6e7e4d2b4197774ed6f
5b5cc6e7e4d2b4197774ed6f- 110 yrstrue
- 211 yrsfalse
- 312 yrsfalse
- 413 yrsfalse
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Answer : 1. "10 yrs"
Explanation :
Answer: A) 10 yrs Explanation: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years. (2x + 2) + 2x + x = 27 5x = 25 => x = 5 Hence, B's age = 2x = 10 years.
Q: A began a business with Rs. 85000. He was joined afterwards by B with Rs. 42,500. For how much perod does B join, if the profits at the end of the year are divided in the ratio of 3:1 ? 1783 05b5cc767e4d2b4197774fe2c
5b5cc767e4d2b4197774fe2c- 18 monthstrue
- 26 monthsfalse
- 37 monthsfalse
- 49 monthsfalse
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Answer : 1. "8 months"
Explanation :
Answer: A) 8 months Explanation: Suppose B joined for x months. Given profit is divided in the ratio 3:1. Then, 85000×1242500×x=31 --> x = 8 months.
Q: Prasanna invested certain amount in three different schemes X, Y and Z with the rate of interest 10% p.a, 12% p.a and 15% p.a respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme Z was 150% of the amount invested in Scheme X and 240% of the amount invested in Scheme Y, what was the amount invested in Scheme Y by Prasanna ? 1783 05b5cc6c5e4d2b4197774ddb9
5b5cc6c5e4d2b4197774ddb9- 1Rs.6000false
- 2Rs.4500false
- 3Rs.7500false
- 4Rs.5000true
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Answer : 4. "Rs.5000"
Explanation :
Answer: D) Rs.5000 Explanation: Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then, As we know: Simple interest (S.I.) = PTR/100 (a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200 = 10a + 12b + 15c = 320000 .........(1) Now, c = 240% of b = 12b/5 .........(2) And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3) From (1), (2) and (3), we have 16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000 ∴ Sum invested in Scheme Y = Rs.5000.
Q: The number of ways that 7 teachers and 6 students can sit around a table so that no two students are together is 1782 05b5cc7b4e4d2b419777508a1
5b5cc7b4e4d2b419777508a1- 17! x 7!false
- 27! x 6!true
- 36! x 6!false
- 47! x 5!false
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Answer : 2. "7! x 6!"
Explanation :
Answer: B) 7! x 6! Explanation: The students should sit in between two teachers. There are 7 gaps in between teachers when they sit in a roundtable. This can be done in 7P6ways. 7 teachers can sit in (7-1)! ways. Required no.of ways is = 7P6.6! = 7!.6!
Q: What should come in place of x in the following equation? x128 = 162x 1782 05b5cc6bee4d2b4197774d9ab
5b5cc6bee4d2b4197774d9ab- 113false
- 212true
- 317false
- 416false
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Answer : 2. "12"
Explanation :
Answer: B) 12 Explanation: x128 = 162x Then x2 = 162x128 = Sqrt of 82 x 62 x 32 = 8 x 6 x 3 x2 = 144. x = 12.