Quantitative Aptitude Practice Question and Answer
8Q: P is 30% more efficient than Q. How much time will they, working together, take to complete a job which P alone could have done in 23 days? 1625 05b5cc6bde4d2b4197774d910
5b5cc6bde4d2b4197774d910- 116 daysfalse
- 213 daystrue
- 315 daysfalse
- 412 daysfalse
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Answer : 2. "13 days"
Explanation :
Answer: B) 13 days Explanation: Ratio of times taken by P & Q = 100 : 130 = 10:13 Let Q takes x days to do the work Then, 10:13 :: 23:x => x = 23x13/10 => x = 299/10 P's 1 day's work = 1/23 Q's 1 day's work = 10/299 (P+Q)'s 1 day's work = (1/23 + 10/299) = 23/299 = 1/13 Hence, P & Q together can complete the work in 13 days.
Q: What should come in place of x in the following equation? x128 = 162x 1625 05b5cc6bee4d2b4197774d9ab
5b5cc6bee4d2b4197774d9ab- 113false
- 212true
- 317false
- 416false
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Answer : 2. "12"
Explanation :
Answer: B) 12 Explanation: x128 = 162x Then x2 = 162x128 = Sqrt of 82 x 62 x 32 = 8 x 6 x 3 x2 = 144. x = 12.
Q: The number of sequences in which 4 players can sing a song, so that the youngest player may not be the last is ? 1625 05b5cc6e1e4d2b4197774ebac
5b5cc6e1e4d2b4197774ebac- 12580false
- 23687false
- 34320true
- 45460false
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Answer : 3. "4320"
Explanation :
Answer: C) 4320 Explanation: Let 'Y' be the youngest player. The last song can be sung by any of the remaining 3 players. The first 3 players can sing the song in (3!) ways. The required number of ways = 3(3!) = 4320.
Q: A shopkeeper who deals in books sold a book at 16% loss. Had she charged an additional Rs.60 while selling it , her profit would have been 14%. Find the cost price, in rupees, of the book ? 1625 05b5cc723e4d2b4197774f677
5b5cc723e4d2b4197774f677- 1Rs. 185false
- 2Rs. 154false
- 3Rs. 200true
- 4Rs. 177false
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Answer : 3. "Rs. 200"
Explanation :
Answer: C) Rs. 200 Explanation: Let the C.P be 'x'Then, the selling price S.P = x - 16x/100= 84x/100 = 21x/25Now, if the S.P is 60 more, then the profit is 14% => 21x/25 + 60 = x + 14x/100=> 114x/100 - 21x/25 = 60=> (57 - 42)x/50 = 60=> 15x/50 = 60x = 3000/15 = 200 Therefore, the Cost price C.P = x = Rs. 200
Q: The difference between two numbers is 3355. When the larger number is divided by the smaller one, the quotient is 6 and the remainder is 15. The smaller number and larger number respectively ? 1623 05b5cc754e4d2b4197774fb81
5b5cc754e4d2b4197774fb81- 1546, 3901false
- 2415, 3770false
- 3668, 4023true
- 4404, 3759false
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Answer : 3. "668, 4023"
Explanation :
Answer: C) 668, 4023 Explanation: Let the smaller number be k.Then, larger number = (3355 + k)Therefore 3355 + k = (6k + 15)‹=› 5k = 3340‹=› k = 668. Therefore, the smaller number k = 668 and now the larger number = 3355+668 = 4023.
Q: What is 70 of 50? 1622 05b5cc675e4d2b4197774c13e
5b5cc675e4d2b4197774c13e- 135true
- 238false
- 342false
- 444false
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Answer : 1. "35"
Explanation :
Answer: A) 35 Explanation: what is 70 of 50 means 70% of 50 ⇒70 x 50100= 7 x 5= 35 Hence, 70 of 50 is 35.
Q: At present, the ratio between the ages of Arun and Harish is 4:3. After 6 years, Arun's age will be 26 years. What is the age of Harish at present ? 1621 05b5cc6e1e4d2b4197774ebfc
5b5cc6e1e4d2b4197774ebfc- 115 yearstrue
- 216 yearsfalse
- 318 yearsfalse
- 421 yearsfalse
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Answer : 1. "15 years"
Explanation :
Answer: A) 15 years Explanation: Let the present ages of Arun and Harish be 4x and 3x years respectively. Then, 4x + 6 = 26 => x = 5 Harish's age = 3x = 15 years.
Q: The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age og the youngest child ? 1621 05b5cc718e4d2b4197774f49a
5b5cc718e4d2b4197774f49a- 18 yrsfalse
- 216 yrsfalse
- 36 yrsfalse
- 44 yrstrue
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Answer : 4. "4 yrs"
Explanation :
Answer: D) 4 yrs Explanation: Let the age of the youngest child is 'X' years.Then the child elder than the yongest is 'X + 3' yrsSince each have 3yrs difference upto 5 childrenAnd given that=> X + X+3 + X+6 + X+9 + X+12 = 50=> 5X + 30 = 50=> X = 4 yrs.

