Quantitative Aptitude Practice Question and Answer
8Q: If 35% of a number is 24 less than 50% of that number, then the number is ? 1696 05b5cc6e1e4d2b4197774eba2
5b5cc6e1e4d2b4197774eba2- 180false
- 2160true
- 3100false
- 4120false
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Answer : 2. "160"
Explanation :
Answer: B) 160 Explanation: Let the number be n. Then, 50% of n - 35% of n = 24 50/100 n - 35/100 n = 24 n = (24 x 100)/15 = 160.
Q: The number of sequences in which 4 players can sing a song, so that the youngest player may not be the last is ? 1694 05b5cc6e1e4d2b4197774ebac
5b5cc6e1e4d2b4197774ebac- 12580false
- 23687false
- 34320true
- 45460false
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Answer : 3. "4320"
Explanation :
Answer: C) 4320 Explanation: Let 'Y' be the youngest player. The last song can be sung by any of the remaining 3 players. The first 3 players can sing the song in (3!) ways. The required number of ways = 3(3!) = 4320.
Q: The average age of a class is 15.8 years. The average age of the boys in the class is 16.4 years and that of the girls is 15.4 years. What is the ratio of boys to girls in the class ? 1693 05b5cc75ee4d2b4197774fcd4
5b5cc75ee4d2b4197774fcd4- 11:3false
- 22:3true
- 33:2false
- 43:1false
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Answer : 2. "2:3"
Explanation :
Answer: B) 2:3 Explanation: Let number of boys = x , Let number of girls = yTotal numbers of students = x + y(x + y) × 15.8 = 16.4x + 15.4y 0.6x = 0.4yx/y = 0.4/0.6 = 2/3 Ratio of boys and girls in the class is 2:3
Q: In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will beat B by ? 1693 05b5cc74fe4d2b4197774faf4
5b5cc74fe4d2b4197774faf4- 125 mtrue
- 221 mfalse
- 322 mfalse
- 419 mfalse
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Answer : 1. "25 m"
Explanation :
Answer: A) 25 m Explanation: A:B = 200 : 169A:C = 200 : 182 CB = CA×AB 182200×200169 => 182:169 When C covers 182 m , B Covers 169 mWhen C covers 350 m , B Covers 169182×350=> 325 m So C beats B by (350 - 325) = 25 m.
Q: Question : What is the sum which earned interest ? Statements : a. The total simple interest was Rs. 9000 after 9 years.b. The total of sum and simple interest was double of the sum after 6 years. 1692 05b5cc767e4d2b4197774fe10
5b5cc767e4d2b4197774fe10- 1Only a is sufficientfalse
- 2Neither a nor b is sufficientfalse
- 3Only b is sufficientfalse
- 4Both a and b sufficienttrue
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Answer : 4. "Both a and b sufficient"
Explanation :
Answer: D) Both a and b sufficient Explanation: Let the sum be Rs. x a. gives, S.I = Rs. 9000 and time = 9 years. b. gives, Sum + S.I for 6 years = 2 x Sum --> Sum = S.I for 6 years. Now, S.I for 9 years = Rs. 9000 S.I for 1 year = Rs. 9000/9 = Rs. 1000. S.I for 6 years = Rs. (1000 x 6)= Rs. 6000. --> x = Rs. 6000 Thus, both a and b are necessary to answer the question.
Q: At a game of billiards, A can give B 20 points in 60 and A can give C 15 points in 60. How many points can C give B in a game of 90 ? 1691 05b5cc723e4d2b4197774f69a
5b5cc723e4d2b4197774f69a- 19 pointsfalse
- 210 pointstrue
- 311 pointsfalse
- 48 pointsfalse
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Answer : 2. "10 points"
Explanation :
Answer: B) 10 points Explanation: a:b = 60:40a:c = 60:45c/a x a/b = 45/60 x 60/40 = 45/40 = 90/80So C gives B => 10 points.
Q: Find the compound interest on Rs. 2680 at 8% per annum for 2 years ? 1691 05b5cc6b4e4d2b4197774d4de
5b5cc6b4e4d2b4197774d4de- 1Rs. 664.21false
- 2Rs. 548.68false
- 3Rs. 445.95true
- 4Rs. 692.57false
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Answer : 3. "Rs. 445.95"
Explanation :
Answer: C) Rs. 445.95 Explanation: We know Compound Interest = C.I. = P1+r100t - 1 Here P = 2680, r = 8 and t = 2 C.I. = 26801 + 81002-1= 268027252-12= 26802725+12725-1= 2680 5225×225 = (2680 x 52 x 2)/625 = 445.95 Compound Interest = Rs. 445.95
Q: The compound interest on a certain sum for 2 years at 10% per annum is Rs. 1155. The simple interest on the same sum for double the time at half the rate percent per annum is ? 1690 15b5cc767e4d2b4197774fdfc
5b5cc767e4d2b4197774fdfc- 1Rs. 1100true
- 2Rs. 5500false
- 3Rs. 1400false
- 4Rs. 4120false
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Answer : 1. "Rs. 1100"
Explanation :
Answer: A) Rs. 1100 Explanation: Let the sum be Rs.x. Then, x1+101002-x=1155 ⇒x11102-1=1155 => x =5500 sum = Rs. 5500. So, S.I = Rs. 5500×5×4100 = 1100