Quantitative Aptitude Practice Question and Answer
8Q: The number of sequences in which 4 players can sing a song, so that the youngest player may not be the last is ? 1867 05b5cc6e1e4d2b4197774ebac
5b5cc6e1e4d2b4197774ebac- 12580false
- 23687false
- 34320true
- 45460false
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Answer : 3. "4320"
Explanation :
Answer: C) 4320 Explanation: Let 'Y' be the youngest player. The last song can be sung by any of the remaining 3 players. The first 3 players can sing the song in (3!) ways. The required number of ways = 3(3!) = 4320.
Q: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B ? 1866 05b5cc6e7e4d2b4197774ed6f
5b5cc6e7e4d2b4197774ed6f- 110 yrstrue
- 211 yrsfalse
- 312 yrsfalse
- 413 yrsfalse
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Answer : 1. "10 yrs"
Explanation :
Answer: A) 10 yrs Explanation: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years. (2x + 2) + 2x + x = 27 5x = 25 => x = 5 Hence, B's age = 2x = 10 years.
Q: Maneela lent Rs. 8000 partly at the rate of 5% and partly at the rate of 6% per annum simple interest. The total interest she get after 2 years is Rs. 820, then in which ratio will Rs. 8000 is to be divided? 1865 05b5cc6bee4d2b4197774d9b5
5b5cc6bee4d2b4197774d9b5- 17:1true
- 213:5false
- 315:7false
- 42:7false
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Answer : 1. "7:1"
Explanation :
Answer: A) 7:1 Explanation: Maneela lent Rs. 8000 in two parts,
Q: Raju sold an article by giving a discount of 8% for Rs. 17,940 and earn profit of 19.6 %. If he did not give discount then how much profit percentage he gets ? 1865 05b5cc6cde4d2b4197774e1a9
5b5cc6cde4d2b4197774e1a9- 127%false
- 230%true
- 332%false
- 425%false
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Answer : 2. "30%"
Explanation :
Answer: B) 30% Explanation: Let the M.R.P of an article be 100 % Selling price of article =Rs. 17940 If he give a discount of 8 % then S.P = 92 % 92 % = 17490 100 % = 19500 Now C.P of the article is 17490 x 100/119.6 = 15000 If he did not give the discount, then Required profit percentage =
Q: A person lends Rs. 1540 for five years and Rs. 1800 for four years. If he gets Rs. 1788 as interest on both amounts, what is the rate of interest ? 1861 05b5cc6c8e4d2b4197774deec
5b5cc6c8e4d2b4197774deec- 114.5%false
- 211%false
- 312%true
- 410.5%false
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Answer : 3. "12%"
Explanation :
Answer: C) 12% Explanation: Let the interest rate be r% We know that, S.I = PTR/100 => (1540 x 5 x r)/100 + (1800 x 4 x r)/100 = 1788 => r = 178800/14900 = 12%
Q: Question : What is the sum which earned interest ? Statements : a. The total simple interest was Rs. 9000 after 9 years.b. The total of sum and simple interest was double of the sum after 6 years. 1860 05b5cc767e4d2b4197774fe10
5b5cc767e4d2b4197774fe10- 1Only a is sufficientfalse
- 2Neither a nor b is sufficientfalse
- 3Only b is sufficientfalse
- 4Both a and b sufficienttrue
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Answer : 4. "Both a and b sufficient"
Explanation :
Answer: D) Both a and b sufficient Explanation: Let the sum be Rs. x a. gives, S.I = Rs. 9000 and time = 9 years. b. gives, Sum + S.I for 6 years = 2 x Sum --> Sum = S.I for 6 years. Now, S.I for 9 years = Rs. 9000 S.I for 1 year = Rs. 9000/9 = Rs. 1000. S.I for 6 years = Rs. (1000 x 6)= Rs. 6000. --> x = Rs. 6000 Thus, both a and b are necessary to answer the question.
Q: A bus covers its journey at the speed of 80km/hr in 10hours. If the same distance is to be covered in 4 hours, by how much the speed of bus will have to increase ? 1860 05b5cc6cfe4d2b4197774e2dc
5b5cc6cfe4d2b4197774e2dc- 185 km/hrfalse
- 295 km/hrfalse
- 3105 km/hrfalse
- 4120 km/hrtrue
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Answer : 4. "120 km/hr"
Explanation :
Answer: D) 120 km/hr Explanation: Initial speed = 80km/hrTotal distance = 80 x 10 = 800kmNew speed = 800/4 =200km/hrIncrease in speed = 200 - 80 = 120km/hr
Q: K, L and M can do a piece of work in 20, 30 and 60 days respectively. In how many days can K do the total work if he is assisted by L and M on every third day ? 1860 05b5cc754e4d2b4197774fb86
5b5cc754e4d2b4197774fb86- 115 daystrue
- 213 daysfalse
- 312 daysfalse
- 410 daysfalse
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Answer : 1. "15 days"
Explanation :
Answer: A) 15 days Explanation: In one day work done by K = 1/20 Work done by K in 2 days = 1/10 Work done by K,L,M on 3rd day =1/20 + 1/30 + 1/60 = 1/10 Therefore, workdone in 3 days is = 1/10 + 1/10 = 1/5 1/5th of the work will be completed at the end of 3 days. The remaining work = 1 - 1/5 = 4/5 1/5 of work is completed in 3 days Total work wiil be done in 3 x 5 = 15 days.

