Quantitative Aptitude Practice Question and Answer
8Q: Evaluate : 3.392-2.6123.39-2.69? 1759 05b5cc728e4d2b4197774f700
5b5cc728e4d2b4197774f700- 13false
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- 36true
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Answer : 3. "6"
Explanation :
Answer: C) 6 Explanation: It is in the form of a2-b2a-b = a+ba-ba-b = a+b Here a = 3.39 b = 2.61 = 3.39 + 2.61 = 6.
Q: The cost price of 40 Magazines is the same as the selling price of 'P' articles. If the profit is 25%, then the value of 'P' is: 1759 05b5cc76ae4d2b4197774fe4f
5b5cc76ae4d2b4197774fe4f- 132true
- 240false
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Answer : 1. "32"
Explanation :
Answer: A) 32 Explanation: Let C.P. of each Magazine be Rs. 1 C.P. of P articles = Rs. P. S.P. of P articles = Rs. 40. Profit = Rs. (40 - P) Now, Gain% = ProfitC.P×100 = 40-PP×100 Here 40-PP×100= 25 -->P = 32.
Q: What will come in place of the question mark (?) in the following number series? 5, 7, ?, 25, 45, 75 1758 05b5cc6cae4d2b4197774dfc0
5b5cc6cae4d2b4197774dfc0- 111false
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Answer : 2. "13"
Explanation :
Answer: B) 13 Explanation: The series given follow the pattern +2, +2+4, +2+4+6, +2+4+6+8, +2+4+6+8+10,... Here ? = 7 + 2 + 4 = 13.
Q: 12 men complete a work in 9 days. After they have worked for 6 days, 4 more men join them. How many days will they take to complete the remaining work ? 1757 05b5cc6d7e4d2b4197774e700
5b5cc6d7e4d2b4197774e700- 12 daysfalse
- 22.5 daysfalse
- 32.25 daystrue
- 43 daysfalse
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Answer : 3. "2.25 days"
Explanation :
Answer: C) 2.25 days Explanation: 1 man's 1 day work = 1/108 12 men's 6 day's work = 1/9 x 6 = 2/3 Remaining work = 1 - 2/3 = 1/3 16 men's 1 day work = 1/108 x 16 = 4/274/27 work is done by them in 1 day. 1/3 work is done by them in 27/4 x 1/3 = 9/4 days.
Q: K, L and M can do a piece of work in 20, 30 and 60 days respectively. In how many days can K do the total work if he is assisted by L and M on every third day ? 1756 05b5cc754e4d2b4197774fb86
5b5cc754e4d2b4197774fb86- 115 daystrue
- 213 daysfalse
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Answer : 1. "15 days"
Explanation :
Answer: A) 15 days Explanation: In one day work done by K = 1/20 Work done by K in 2 days = 1/10 Work done by K,L,M on 3rd day =1/20 + 1/30 + 1/60 = 1/10 Therefore, workdone in 3 days is = 1/10 + 1/10 = 1/5 1/5th of the work will be completed at the end of 3 days. The remaining work = 1 - 1/5 = 4/5 1/5 of work is completed in 3 days Total work wiil be done in 3 x 5 = 15 days.
Q: Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is : 1752 05b5cc6eee4d2b4197774ef09
5b5cc6eee4d2b4197774ef09- 183false
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Answer : 3. "85"
Explanation :
Answer: C) 85 Explanation: Since the numbers are co-prime, they contain only 1 as the common factor.Also, the given two products have the middle number in common.So, middle number = H.C.F of 551 and 1073 = 29;First number = 551/29 = 19Third number = 1073/29 = 37.Required sum = 19 + 29 + 37 = 85.
Q: The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age og the youngest child ? 1752 05b5cc718e4d2b4197774f49a
5b5cc718e4d2b4197774f49a- 18 yrsfalse
- 216 yrsfalse
- 36 yrsfalse
- 44 yrstrue
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Answer : 4. "4 yrs"
Explanation :
Answer: D) 4 yrs Explanation: Let the age of the youngest child is 'X' years.Then the child elder than the yongest is 'X + 3' yrsSince each have 3yrs difference upto 5 childrenAnd given that=> X + X+3 + X+6 + X+9 + X+12 = 50=> 5X + 30 = 50=> X = 4 yrs.
Q: The length of two superfast trains are 140 mts and 160 mts respectively. If they run at the speed of 60 km/hr and 80 km/hr respectively in opposite direction, find the time in which they will cross each other ? 1752 05b5cc6cde4d2b4197774e1ae
5b5cc6cde4d2b4197774e1ae- 17.71 sectrue
- 210.48 secfalse
- 39.36 secfalse
- 48.45 secfalse
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Answer : 1. "7.71 sec"
Explanation :
Answer: A) 7.71 sec Explanation: Given L1 = 140 m L2 = 160 m S1 = 60 km/hr S2 = 80 km/hr From the question we get, S1 + S2 = (L1 + L2) / T => (60 + 80) 5/18 m/s = 140 + 160/T => T = 54/7 = 7.71 sec

