Quantitative Aptitude Practice Question and Answer

Q: In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm) 1608 0

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    80%
    Correct
    Wrong
  • 2
    70%
    Correct
    Wrong
  • 3
    75%
    Correct
    Wrong
  • 4
    62%
    Correct
    Wrong
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Answer : 1. "80%"
Explanation :

Answer: A) 80% Explanation: Water in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm.   After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm.   So % of water = 100 x 60/75 = 80%.

Q: In how many ways can letter of the word RAILINGS arrange so that R and S always come together? 1608 0

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    1260
    Correct
    Wrong
  • 2
    2520
    Correct
    Wrong
  • 3
    5040
    Correct
    Wrong
  • 4
    1080
    Correct
    Wrong
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Answer : 3. "5040"
Explanation :

Answer: C) 5040 Explanation: The number of ways in which the letters of the word RAILINGS can be arranged such that R & S always come together is   Count R & S as only 1 space or letter so that RS or SR can be arranged => 7! x 2!   But in the word RAILINGS, I repeated for 2 times => 7! x 2!/2! = 7! ways = 5040 ways.

Q: A can do a piece of work in 15 days and B can do it in 16 days and C can do it 24 days. They started the work together and A leaves after 3 days and B leaves after 4 days from the beginning. How long will work lost ? 1607 0

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    10 2/3 days
    Correct
    Wrong
  • 2
    13 1/5 days
    Correct
    Wrong
  • 3
    12 2/3 days
    Correct
    Wrong
  • 4
    11 5/7 days
    Correct
    Wrong
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Answer : 2. "13 1/5 days"
Explanation :

Answer: B) 13 1/5 days Explanation: 3/15 + 4/16 + x/24 = 1 ⇒x=1315

Q: What will be the ratio of simple interest earned by certain amount at the same rate of interestfor 4 years and 6 years ? 1607 0

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    1:2
    Correct
    Wrong
  • 2
    2:1
    Correct
    Wrong
  • 3
    2:3
    Correct
    Wrong
  • 4
    3:2
    Correct
    Wrong
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Answer : 3. "2:3"
Explanation :

Answer: C) 2:3 Explanation: Let p be the principle amount And R% be the rate of interest Then, required ratio =P×4×R100P×6×R100    ⇒4PR6PR= 2:3

Q: An alloy of copper and bronze weight 50g. It contains 80% Copper. How much copper should be added to the alloy so that percentage of copper is increased to 90%? 1606 0

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    45 gm
    Correct
    Wrong
  • 2
    50 gm
    Correct
    Wrong
  • 3
    55 gm
    Correct
    Wrong
  • 4
    60 gm
    Correct
    Wrong
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Answer : 2. "50 gm"
Explanation :

Answer: B) 50 gm Explanation: Initial quantity of copper =80100 x 50 = 40 g  And that of Bronze = 50 - 40 = 10 g Let 'p' gm of copper is added to the mixture => 50 + p x 90100 = 40 + p => 45 + 0.9p = 40 + p => p = 50 g Hence, 50 gms of copper is added to the mixture, so that the copper is increased to 90%.

Q: Simplify 2392-21+8-72=?2 1605 0

  • 1
    4
    Correct
    Wrong
  • 2
    5
    Correct
    Wrong
  • 3
    6
    Correct
    Wrong
  • 4
    9
    Correct
    Wrong
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Answer : 3. "6"
Explanation :

Answer: C) 6 Explanation: ?2 = 2×78-21+8+49-148= 57 - 21=36=> ? = ±6

Q: Find the compound interest on Rs. 2680 at 8% per annum for 2 years ? 1604 0

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    Rs. 664.21
    Correct
    Wrong
  • 2
    Rs. 548.68
    Correct
    Wrong
  • 3
    Rs. 445.95
    Correct
    Wrong
  • 4
    Rs. 692.57
    Correct
    Wrong
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Answer : 3. "Rs. 445.95"
Explanation :

Answer: C) Rs. 445.95 Explanation: We know Compound Interest = C.I. = P1+r100t - 1 Here P = 2680, r = 8 and t = 2 C.I. = 26801 + 81002-1= 268027252-12= 26802725+12725-1= 2680 5225×225 = (2680 x 52 x 2)/625 = 445.95   Compound Interest = Rs. 445.95

Q: If a girl cycles at 10 kmph, then she arrives at a certain place at 1 p.m. If she cycles at 15 kmph, she will arrive at the same place at 11 a.m. At what speed must she cycle to get there at noon? 1603 0

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    14 kmph
    Correct
    Wrong
  • 2
    13 kmph
    Correct
    Wrong
  • 3
    12 kmph
    Correct
    Wrong
  • 4
    11 kmph
    Correct
    Wrong
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Answer : 3. "12 kmph"
Explanation :

Answer: C) 12 kmph Explanation: The distance is constant in this case. Let the time taken for travel with a speed of 10 kmph be 't'. Now the speed of 15 kmph is 3/2 times the speed of 10 kmph. Therefore, time taken with the speed of 15 kmph will be 2t/3 (speed is inversely proportional to time) Extra time taken = t - 2t/3 = t/3 => 1pm - 11am = 2hrs => t/3 = 2h => t = 6 hrs. Now, Distance = speed x time = 10 x 6 = 60 kms Time he takes to reach at noon = 6 - 1 = 5 hrs Now, Speed = 60/5 = 12 kmph.

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