Quantitative Aptitude Practice Question and Answer
8Q: In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm) 1605 05b5cc73de4d2b4197774f943
5b5cc73de4d2b4197774f943- 180%true
- 270%false
- 375%false
- 462%false
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Answer : 1. "80%"
Explanation :
Answer: A) 80% Explanation: Water in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm. After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm. So % of water = 100 x 60/75 = 80%.
Q: Robert is traveling on his cycle and has calculated to reach point A at 2 p.m. if he travels at 10 km/hr; he will reach there at 12 noon if he travels at 15 km/hr. At what speed must he travel to reach A at 1 p.m. ? 1604 05b5cc6dae4d2b4197774e899
5b5cc6dae4d2b4197774e899- 120 kmphfalse
- 218 kmphfalse
- 312 kmphtrue
- 416 kmphfalse
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Answer : 3. "12 kmph"
Explanation :
Answer: C) 12 kmph Explanation: Let the distance traveled be x km.Then, x/10 - x/15 = 23x - 2x = 60 => x = 60 km.Time taken to travel 60 km at 10 km/hr = 60/10 = 6 hrs.So, Robert started 6 hours before 2. p.m. i.e., at 8 a.m.Required speed = 60/5 = 12 kmph.
Q: A can do a piece of work in 15 days and B can do it in 16 days and C can do it 24 days. They started the work together and A leaves after 3 days and B leaves after 4 days from the beginning. How long will work lost ? 1604 05b5cc6dae4d2b4197774e8dc
5b5cc6dae4d2b4197774e8dc- 110 2/3 daysfalse
- 213 1/5 daystrue
- 312 2/3 daysfalse
- 411 5/7 daysfalse
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Answer : 2. "13 1/5 days"
Explanation :
Answer: B) 13 1/5 days Explanation: 3/15 + 4/16 + x/24 = 1 ⇒x=1315
Q: Simplify 2392-21+8-72=?2 1604 05b5cc6b9e4d2b4197774d775
5b5cc6b9e4d2b4197774d775- 14false
- 25false
- 36true
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Answer : 3. "6"
Explanation :
Answer: C) 6 Explanation: ?2 = 2×78-21+8+49-148= 57 - 21=36=> ? = ±6
Q: What will be the ratio of simple interest earned by certain amount at the same rate of interestfor 4 years and 6 years ? 1603 05b5cc767e4d2b4197774fe15
5b5cc767e4d2b4197774fe15- 11:2false
- 22:1false
- 32:3true
- 43:2false
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Answer : 3. "2:3"
Explanation :
Answer: C) 2:3 Explanation: Let p be the principle amount And R% be the rate of interest Then, required ratio =P×4×R100P×6×R100 ⇒4PR6PR= 2:3
Q: A town has a population of 4000 requires 140 liters of water per head. It has a tank measuring 18m x 12m x 8m. The water of this tank will suffice for ____ days? 1602 05b5cc6bfe4d2b4197774da60
5b5cc6bfe4d2b4197774da60- 13true
- 24false
- 35false
- 42false
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Answer : 1. "3"
Explanation :
Answer: A) 3 Explanation: Water required = 4000 x 140 = 560000 lit = 560 cu.m (1 cu.m = 1000 lit) Volume of tank = 18 x 12 x 8 = 1728 cu.m Water of this tank will suffice for = 1728/560 = 3 days.
Q: An alloy of copper and bronze weight 50g. It contains 80% Copper. How much copper should be added to the alloy so that percentage of copper is increased to 90%? 1602 05b5cc6aee4d2b4197774d179
5b5cc6aee4d2b4197774d179- 145 gmfalse
- 250 gmtrue
- 355 gmfalse
- 460 gmfalse
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Answer : 2. "50 gm"
Explanation :
Answer: B) 50 gm Explanation: Initial quantity of copper =80100 x 50 = 40 g And that of Bronze = 50 - 40 = 10 g Let 'p' gm of copper is added to the mixture => 50 + p x 90100 = 40 + p => 45 + 0.9p = 40 + p => p = 50 g Hence, 50 gms of copper is added to the mixture, so that the copper is increased to 90%.
Q: If a girl cycles at 10 kmph, then she arrives at a certain place at 1 p.m. If she cycles at 15 kmph, she will arrive at the same place at 11 a.m. At what speed must she cycle to get there at noon? 1601 05b5cc6bfe4d2b4197774da42
5b5cc6bfe4d2b4197774da42- 114 kmphfalse
- 213 kmphfalse
- 312 kmphtrue
- 411 kmphfalse
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Answer : 3. "12 kmph"
Explanation :
Answer: C) 12 kmph Explanation: The distance is constant in this case. Let the time taken for travel with a speed of 10 kmph be 't'. Now the speed of 15 kmph is 3/2 times the speed of 10 kmph. Therefore, time taken with the speed of 15 kmph will be 2t/3 (speed is inversely proportional to time) Extra time taken = t - 2t/3 = t/3 => 1pm - 11am = 2hrs => t/3 = 2h => t = 6 hrs. Now, Distance = speed x time = 10 x 6 = 60 kms Time he takes to reach at noon = 6 - 1 = 5 hrs Now, Speed = 60/5 = 12 kmph.