Quantitative Aptitude Practice Question and Answer

Q: In a triangle ABC, angle 'a' is the smallest one & A+7B = 112. Find the range of value 'c' ? 1657 0

  • 1
    138 to 164
    Correct
    Wrong
  • 2
    125 to 147
    Correct
    Wrong
  • 3
    148 to 158
    Correct
    Wrong
  • 4
    152 to 164
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 4. "152 to 164"
Explanation :

Answer: D) 152 to 164 Explanation: A+7B=112 it is clear that A = 14, then it becomes A>=B, but A is smallest angle) givenso, range of A is 0.0001 to 13.9999 ( I am taking upto 4 decimal places)so, range of B becomes 14 to 16 ( after rounding off to 4 decimal places)so, range of C becomes 152 to 164 ( after rounding off to 4 decimal places)

Q: In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm) 1657 0

  • 1
    80%
    Correct
    Wrong
  • 2
    70%
    Correct
    Wrong
  • 3
    75%
    Correct
    Wrong
  • 4
    62%
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 1. "80%"
Explanation :

Answer: A) 80% Explanation: Water in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm.   After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm.   So % of water = 100 x 60/75 = 80%.

Q: K, L and M can do a piece of work in 20, 30 and 60 days respectively. In how many days can K do the total work if he is assisted by L and M on every third day ? 1657 0

  • 1
    15 days
    Correct
    Wrong
  • 2
    13 days
    Correct
    Wrong
  • 3
    12 days
    Correct
    Wrong
  • 4
    10 days
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 1. "15 days"
Explanation :

Answer: A) 15 days Explanation: In one day work done by K = 1/20 Work done by K in 2 days = 1/10   Work done by K,L,M on 3rd day =1/20 + 1/30 + 1/60 = 1/10 Therefore, workdone in 3 days is = 1/10 + 1/10 = 1/5   1/5th of the work will be completed at the end of 3 days. The remaining work = 1 - 1/5 = 4/5 1/5 of work is completed in 3 days Total work wiil be done in 3 x 5 = 15 days.

Q: Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is : 1656 0

  • 1
    83
    Correct
    Wrong
  • 2
    89
    Correct
    Wrong
  • 3
    85
    Correct
    Wrong
  • 4
    79
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 3. "85"
Explanation :

Answer: C) 85 Explanation: Since the numbers are co-prime, they contain only 1 as the common factor.Also, the given two products have the middle number in common.So, middle number = H.C.F of 551 and 1073 = 29;First number = 551/29 = 19Third number = 1073/29 = 37.Required sum = 19 + 29 + 37 = 85.

Q: A card is drawn from a pack of 52 cards. The probability of getting a queen of the club or a king of the heart is? 1655 0

  • 1
    1/26
    Correct
    Wrong
  • 2
    1/13
    Correct
    Wrong
  • 3
    2/13
    Correct
    Wrong
  • 4
    1/52
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 1. "1/26"
Explanation :

Answer: A) 1/26 Explanation: Here in this pack of cards, n(S) = 52 Let E = event of getting a queen of the club or a king of the heart Then, n(E) = 2 P(E) = n(E)/n(S) = 2/52 = 1/26

Q: An alloy of copper and bronze weight 50g. It contains 80% Copper. How much copper should be added to the alloy so that percentage of copper is increased to 90%? 1655 0

  • 1
    45 gm
    Correct
    Wrong
  • 2
    50 gm
    Correct
    Wrong
  • 3
    55 gm
    Correct
    Wrong
  • 4
    60 gm
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 2. "50 gm"
Explanation :

Answer: B) 50 gm Explanation: Initial quantity of copper =80100 x 50 = 40 g  And that of Bronze = 50 - 40 = 10 g Let 'p' gm of copper is added to the mixture => 50 + p x 90100 = 40 + p => 45 + 0.9p = 40 + p => p = 50 g Hence, 50 gms of copper is added to the mixture, so that the copper is increased to 90%.

Q: K can lay Highway road between two cities in 16 days. L can do the same job in 12 days. With the help of M, they completes the job in 4 days. How much days does it take for M alone to complete the work ? 1655 0

  • 1
    47/7 days
    Correct
    Wrong
  • 2
    59/6 days
    Correct
    Wrong
  • 3
    48/5 days
    Correct
    Wrong
  • 4
    57/5 days
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 3. "48/5 days"
Explanation :

Answer: C) 48/5 days Explanation: Amount of work K can do in 1 day = 1/16 Amount of work L can do in 1 day = 1/12 Amount of work K, L and M can together do in 1 day = 1/4 Amount of work M can do in 1 day = 1/4 - (1/16 + 1/12) = 3/16 – 1/12 = 5/48 => Hence M can do the job on 48/5 days = 9 (3/5) days

Q: A polygon has 44 diagonals, then the number of its sides are ? 1654 0

  • 1
    13
    Correct
    Wrong
  • 2
    9
    Correct
    Wrong
  • 3
    11
    Correct
    Wrong
  • 4
    7
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 3. "11"
Explanation :

Answer: C) 11 Explanation: Let the number of sides be n.  The number of diagonals is given by nC2 - n   Therefore, nC2 - n = 44, n>0  nC2 - n = 44 n2 - 3n - 88 = 0  n2 -11n + 8n - 88 = 0   n(n - 11) + 8(n - 11) = 0  n = -8 or n = 11.   As n>0, n will not be -8. Therefore, n=11.

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully