Quantitative Aptitude Practice Question and Answer
8Q: In a triangle ABC, angle 'a' is the smallest one & A+7B = 112. Find the range of value 'c' ? 1657 05b5cc6f4e4d2b4197774efe6
5b5cc6f4e4d2b4197774efe6- 1138 to 164false
- 2125 to 147false
- 3148 to 158false
- 4152 to 164true
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Answer : 4. "152 to 164"
Explanation :
Answer: D) 152 to 164 Explanation: A+7B=112 it is clear that A = 14, then it becomes A>=B, but A is smallest angle) givenso, range of A is 0.0001 to 13.9999 ( I am taking upto 4 decimal places)so, range of B becomes 14 to 16 ( after rounding off to 4 decimal places)so, range of C becomes 152 to 164 ( after rounding off to 4 decimal places)
Q: In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm) 1657 05b5cc73de4d2b4197774f943
5b5cc73de4d2b4197774f943- 180%true
- 270%false
- 375%false
- 462%false
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Answer : 1. "80%"
Explanation :
Answer: A) 80% Explanation: Water in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm. After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm. So % of water = 100 x 60/75 = 80%.
Q: K, L and M can do a piece of work in 20, 30 and 60 days respectively. In how many days can K do the total work if he is assisted by L and M on every third day ? 1657 05b5cc754e4d2b4197774fb86
5b5cc754e4d2b4197774fb86- 115 daystrue
- 213 daysfalse
- 312 daysfalse
- 410 daysfalse
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Answer : 1. "15 days"
Explanation :
Answer: A) 15 days Explanation: In one day work done by K = 1/20 Work done by K in 2 days = 1/10 Work done by K,L,M on 3rd day =1/20 + 1/30 + 1/60 = 1/10 Therefore, workdone in 3 days is = 1/10 + 1/10 = 1/5 1/5th of the work will be completed at the end of 3 days. The remaining work = 1 - 1/5 = 4/5 1/5 of work is completed in 3 days Total work wiil be done in 3 x 5 = 15 days.
Q: Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is : 1656 05b5cc6eee4d2b4197774ef09
5b5cc6eee4d2b4197774ef09- 183false
- 289false
- 385true
- 479false
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Answer : 3. "85"
Explanation :
Answer: C) 85 Explanation: Since the numbers are co-prime, they contain only 1 as the common factor.Also, the given two products have the middle number in common.So, middle number = H.C.F of 551 and 1073 = 29;First number = 551/29 = 19Third number = 1073/29 = 37.Required sum = 19 + 29 + 37 = 85.
Q: A card is drawn from a pack of 52 cards. The probability of getting a queen of the club or a king of the heart is? 1655 05b5cc6bde4d2b4197774d94c
5b5cc6bde4d2b4197774d94c- 11/26true
- 21/13false
- 32/13false
- 41/52false
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Answer : 1. "1/26"
Explanation :
Answer: A) 1/26 Explanation: Here in this pack of cards, n(S) = 52 Let E = event of getting a queen of the club or a king of the heart Then, n(E) = 2 P(E) = n(E)/n(S) = 2/52 = 1/26
Q: An alloy of copper and bronze weight 50g. It contains 80% Copper. How much copper should be added to the alloy so that percentage of copper is increased to 90%? 1655 05b5cc6aee4d2b4197774d179
5b5cc6aee4d2b4197774d179- 145 gmfalse
- 250 gmtrue
- 355 gmfalse
- 460 gmfalse
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Answer : 2. "50 gm"
Explanation :
Answer: B) 50 gm Explanation: Initial quantity of copper =80100 x 50 = 40 g And that of Bronze = 50 - 40 = 10 g Let 'p' gm of copper is added to the mixture => 50 + p x 90100 = 40 + p => 45 + 0.9p = 40 + p => p = 50 g Hence, 50 gms of copper is added to the mixture, so that the copper is increased to 90%.
Q: K can lay Highway road between two cities in 16 days. L can do the same job in 12 days. With the help of M, they completes the job in 4 days. How much days does it take for M alone to complete the work ? 1655 05b5cc6cfe4d2b4197774e32d
5b5cc6cfe4d2b4197774e32d- 147/7 daysfalse
- 259/6 daysfalse
- 348/5 daystrue
- 457/5 daysfalse
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Answer : 3. "48/5 days"
Explanation :
Answer: C) 48/5 days Explanation: Amount of work K can do in 1 day = 1/16 Amount of work L can do in 1 day = 1/12 Amount of work K, L and M can together do in 1 day = 1/4 Amount of work M can do in 1 day = 1/4 - (1/16 + 1/12) = 3/16 – 1/12 = 5/48 => Hence M can do the job on 48/5 days = 9 (3/5) days
Q: A polygon has 44 diagonals, then the number of its sides are ? 1654 05b5cc754e4d2b4197774fbb9
5b5cc754e4d2b4197774fbb9- 113false
- 29false
- 311true
- 47false
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Answer : 3. "11"
Explanation :
Answer: C) 11 Explanation: Let the number of sides be n. The number of diagonals is given by nC2 - n Therefore, nC2 - n = 44, n>0 nC2 - n = 44 n2 - 3n - 88 = 0 n2 -11n + 8n - 88 = 0 n(n - 11) + 8(n - 11) = 0 n = -8 or n = 11. As n>0, n will not be -8. Therefore, n=11.

