Quantitative Aptitude Practice Question and Answer
8Q: Two candidates fought in a municipality election. One of them got 54% of the total votes pooled and won by 1080 votes. What was the total number of votes polled ? 1728 05b5cc74fe4d2b4197774fb2b
5b5cc74fe4d2b4197774fb2b- 112000false
- 213500true
- 315400false
- 411000false
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Answer : 2. "13500"
Explanation :
Answer: B) 13500 Explanation: Given in municipality election 54% votes have won by 1080 Let the total number of votes be x. 54x100 - 46x100 = 1080 8x = 108000 x = 13,500 Therefore, total number of votes = 13,500.
Q: What is the sum of all 3 digits number that can be formed using digits 0,1,2,3,4,5 with no repitition ? 1727 05b5cc709e4d2b4197774f2a3
5b5cc709e4d2b4197774f2a3- 128450false
- 226340false
- 332640true
- 436450false
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Answer : 3. "32640"
Explanation :
Answer: C) 32640 Explanation: We know that zero can't be in hundreds place. But let's assume that our number could start with zero. The formula to find sum of all numbers in a permutation is 111 x no of ways numbers can be formed for a number at given position x sum of all given digits No of 1 s depends on number of digits So,the answer us 111 x 20 x (0+1+2+3+4+5) = 33300 We got 20 as follows. If we have 0 in units place we can form a number in 4*5 ways. This is for all numbers. So we have substituted 20 in formula. Now, this is not the final answer because we have included 0 in hundreds place. so we have to remove the sum of all numbers that starts with 0. This is nothing but the sum of all 2 digits numbers formed by 1 2 3 4 5. Because 0 at first place makes it a 2 digit number. So the sum for this is 11 x 4 x (1+2+3+4+5). =660 Hope u understood why we use 4. Each number can be formed in 4x1 ways So, the final answer is 33300-660 = 32640
Q: The total of the ages of Ashok, Akbar and Anil is 65 years. What was the total of their ages six years ago ? 1727 05b5cc723e4d2b4197774f695
5b5cc723e4d2b4197774f695- 159false
- 243false
- 357false
- 447true
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Answer : 4. "47"
Explanation :
Answer: D) 47 Explanation: Let their ages be x, y, zHence given that x + y + z = 65Now, six years ago x age is x - 6, y is y - 6 and that of z is z - 6Then the sum of their ages six years ago is (x + y + z) - (6 + 6 + 6) = 65 - 18 = 47
Q: At what rate percent on simple interest will Rs.415 amount to Rs.514 in 4 years ? 1727 05b5cc6d6e4d2b4197774e656
5b5cc6d6e4d2b4197774e656- 14.58 %false
- 25.96 %true
- 36.52 %false
- 44.98 %false
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Answer : 2. "5.96 %"
Explanation :
Answer: B) 5.96 % Explanation: Difference in amount = 514 - 415 = 99 99 = (415 x 4 x R)/100 R = 5.96%
Q: In the following question a number series is given which has only one wrong number. You have to find out the wrong number? 7.5 47.5 87.5 157.5 247.5 357.5 487.5 1726 05b5cc7c9e4d2b41977750e9f
5b5cc7c9e4d2b41977750e9f- 147.5true
- 287.5false
- 3247.5false
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Answer : 1. "47.5"
Explanation :
Answer: A) 47.5 Explanation:
Q: About 4 out of 5 students are left handed. If there are totally 40 students in an class. How many would be left handed ? 1725 05b5cc705e4d2b4197774f220
5b5cc705e4d2b4197774f220- 140false
- 245false
- 332true
- 430false
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Answer : 3. "32"
Explanation :
Answer: C) 32 Explanation: Probability of left handed = 4/5total student = 40total left handed = 40 x(4/5)= 32
Q: There are two numbers such that the sum of twice the first number and thrice the second number is 300 and the sum of thrice the first number and twice the second number is 265. Which is the largest number ? 1724 05b5cc7c7e4d2b41977750db4
5b5cc7c7e4d2b41977750db4- 124false
- 239false
- 385false
- 474true
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Answer : 4. "74"
Explanation :
Answer: D) 74 Explanation:
Q: The age of Manisha and Sudeshna are in the ratio of 5 : 6 respectively. After 8 years the ratio of their ages will be 7 : 8. What is the difference of their ages ? 1723 05b5cc6c3e4d2b4197774dc1d
5b5cc6c3e4d2b4197774dc1d- 16false
- 24true
- 38false
- 410false
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Answer : 2. "4"
Explanation :
Answer: B) 4 Explanation: Let the age of Manisha and Sudeshna is 5x and 6x years respectively. According to the given data, 5x+8/6x+8 = 7/8 42x + 56 = 40x + 64 x = 4 Required Difference of their ages = (6 × 4) – (5 × 4) = 4 years.

