Quantitative Aptitude Practice Question and Answer
8Q: If x = 2 + 223 + 213 then find the value of x3-6x2+6x ? 1676 05b5cc745e4d2b4197774fa09
5b5cc745e4d2b4197774fa09- 11false
- 22true
- 33false
- 44false
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Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: Given that x = 2+ 223 + 213 So x - 2 = 223 + 213 Now cubing on both sides, we get => x3-8-6x2+12x = 4 + 2 + 6(x-2) Therefore, x3-6x2+6x = -6 + 8 = 2
Q: Find the Missing number in the given Series ? 2, 3, 6, 15, ? , 157.5 1674 05b5cc6bce4d2b4197774d8ac
5b5cc6bce4d2b4197774d8ac- 187false
- 278.5false
- 356.5false
- 445true
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Answer : 4. "45"
Explanation :
Answer: D) 45 Explanation: Here given 2, 3, 6, 15, ? , 157.5 2 x 1.5 = 3 3 x 2 = 6 6 x 2.5 = 15 15 x 3 = 45 45 x 3.5 = 157.5 Therefore, the missing number is 45
Q: Train K crosses a pole in 30 seconds and train L crosses the same pole in one minute and 20 seconds. The length of train K is three-fourths the length of train L. What is the ratio of the speed of train K to that of train L ? 1670 05b5cc6e0e4d2b4197774eb39
5b5cc6e0e4d2b4197774eb39- 11 : 3false
- 22 : 1true
- 33 : 1false
- 41 : 2false
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Answer : 2. "2 : 1"
Explanation :
Answer: B) 2 : 1 Explanation: Given that train K crosses a pole in 30 seconds and train L crosses the same pole in one minute and 15 seconds. Let the length of train K be Lk and that of train L be Ll given that Lk = 3/4 Ll As the train K and L crosses the pole in 30 seconds and 80 seconds respectively, => Speed of train K = sk = Lk/30 Speed of train L = sl = Ll/80 Lk = 3/4 Ll => sk = 3/4 Ll/(30) = Ll/40 Ratio of their speeds = sk : sl = Ll/40 : Ll/80 => 1/40 : 1/80 = 2 : 1
Q: The calendar for the year 1988 is same as which upcoming year ? 1670 05b5cc6cfe4d2b4197774e2e3
5b5cc6cfe4d2b4197774e2e3- 12012false
- 22014false
- 32016true
- 42010false
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Answer : 3. "2016"
Explanation :
Answer: C) 2016 Explanation: We already know that the calendar after a leap year repeats again after 28 years. Here year 1988 is a Leap year, then the same calendar will be in the year = 1988 + 28 = 2016.
Q: A man pays Rs. 6.40 per litre of milk. He adds water and sells the mixture at Rs. 8 per litre, thereby making 37.5% profit. The proportion of water to milk received by the customers is 1668 05b5cc6afe4d2b4197774d25e
5b5cc6afe4d2b4197774d25e- 11 : 10true
- 210 : 1false
- 39 : 11false
- 411 : 9false
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Answer : 1. "1 : 10"
Explanation :
Answer: A) 1 : 10 Explanation: Customer ratio of Milk and Water is given by Milk :: Water 6.4 0 81 + 38 =6411 6411 6410 - 6411 => Milk : Water = 110 : 11 = 10 : 1 Therefore, the proportionate of Water to Milk for Customer is 1 : 10
Q: 112 × 54 = 1664 05b5cc6b9e4d2b4197774d752
5b5cc6b9e4d2b4197774d752- 168947false
- 269874false
- 370000true
- 476000false
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Answer : 3. "70000"
Explanation :
Answer: C) 70000 Explanation: 112 × 54112 × 1024= 112 × 1000024= 1120000/16 = 70,000.
Q: Navaneet has thrice the money Poonam has and Poonam has 25% more money than Hebah. If the average money of the three is Rs. 350, What is the amount that Navaneet has ? 1662 05b5cc6c4e4d2b4197774dceb
5b5cc6c4e4d2b4197774dceb- 1Rs. 175false
- 2Rs. 220.75false
- 3Rs. 218.55false
- 4Rs. 656.25true
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Answer : 4. "Rs. 656.25"
Explanation :
Answer: D) Rs. 656.25 Explanation: Assume Hebah has Rs. M Since 25% more money at Poonam => Money at Poonam = M + (25% of M) => Money at Poonam = M + 0.25M = Rs. 1.25M Money with Navaneet is thrice the money with Poonam, => Money at Navaneet = 3(1.25M) = Rs. 3.75M Now, sum of all Money = (M + 1.25M + 3.75M) = Rs. 6M But given the average of the money is Rs. 350 => 6M/3 = 350 => 2M = 350 => M = 350/2 = Rs. 175 => Amount of money Navaneet has = Rs. 3.75M = 3.75 x 175 = Rs. 656.25.
Q: A train running at the speed of 40 km/hr crosses a signal pole in 9 seconds. Find the length of the train ? 1659 05b5cc76fe4d2b4197774ff4e
5b5cc76fe4d2b4197774ff4e- 190 mtsfalse
- 2150 mtsfalse
- 3120 mtsfalse
- 4100 mtstrue
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Answer : 4. "100 mts"
Explanation :
Answer: D) 100 mts Explanation: We know that Speed=distancetime distance= speed * time ⇒ d=40×518×9 d= 100 mts.

