Answer: B) decrease 12% Explanation: Given the price of a commodity is decreased by  p = 20% And its consumption is increased by q = 10% Now, required increase or decrease in the expenditure on the commodity can be  p + q + pq/100 = -20 + 10 - 200/100 = -10 - 2 = -12%.   Hence, decrease in the expenditure = 12%

Answer: D) 26 Explanation: Let, Hema attempted 'k' sum correctly, then k x 3 -2 x(35-k) = 605k = 130k = 26 so 26 correct sums.

Answer: B) 106 kmph Explanation: As we know that Speed = Distance / Timefor average speed = Total Distance / Total Time TakenThus, Total Distance = 325 + 470 = 795 kmThus, Total Speed = 7.5 hrsAverage Speed = 795/7.5 => 106 kmph.

Answer: B) Rs. 441 Explanation: Given principal amount = Rs. 8000 Time = 3yrs Rate = 5% C.I for 3 yrs = 8000 x 105100 x 105100 x 105100 - 8000= Rs. 1261   Now, C.I for 2 yrs = 8000 x 105100 x 105100= Rs. 820    Hence, the required difference in C.I is 1261 - 820 = Rs. 441

Answer: A) Rs. 704 Explanation: We know that, S.I. = PTR100⇒ P = S.I x 100T x RAnd also,C.I = P1 + R100n- 1 From given data, P = Rs. 8625 Now, C.I  = 86251+41002-1= 862526252-1= 8625676625-1= 8625 x 51625C.I = Rs. 703.80

Answer: B) Friday Explanation: On 31st December, 2005 it was Monday. Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days. On 31st December 2009, it was Thursday. Thus, on 1st Jan, 2010 it is Friday.

Answer: B) 2 : 1 Explanation: Given that train K crosses a pole in 30 seconds and train L crosses the same pole in one minute and 15 seconds. Let the length of train K be Lk and that of train L be Ll given that Lk = 3/4 Ll As the train K and L crosses the pole in 30 seconds and 80 seconds respectively, => Speed of train K = sk = Lk/30 Speed of train L = sl = Ll/80 Lk = 3/4 Ll => sk = 3/4 Ll/(30) = Ll/40 Ratio of their speeds = sk : sl = Ll/40 : Ll/80 => 1/40 : 1/80  =  2 : 1

Answer: B) 13.63% Explanation: Required % is given by    => 12100-12x100   = 1200/88   = 13.636%