Quantitative Aptitude Practice Question and Answer
8Q: An owner of a Dry fruits shop sold small packets of mixed nuts for Rs. 150 each and large packets for Rs. 250 each. One day he sold 5000 packets, for a total of Rs. 10.50 lakh. How many small packets were sold ? 1806 05b5cc6cfe4d2b4197774e308
5b5cc6cfe4d2b4197774e308- 12000true
- 23000false
- 32500false
- 43500false
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Answer : 1. "2000"
Explanation :
Answer: A) 2000 Explanation: Let 's' be the number of small packets and 'b' the number of large packets sold on that day. Therefore, s + b = 5000 ... eqn (1) Each small packet was sold for Rs.150.Therefore, 's' small packets would have fetched Rs.150s. Each large packets was sold for Rs.250.Therefore, 'b' large packets would have fetched Rs.250b. Total value of sale = 150s + 250b = Rs. 10.5 Lakhs (Given) Or 150s + 250b = 10,50,000 ... eqn (2) Multiplying equation (1) by 150, we get 150s + 150b = 7,50,000 ... eqn (3) Subtracting eqn (3) from eqn (2), we get 100b = 3,00,000Or b = 3000 We know that s + b = 5000So, s = 5000 - b = 5000 - 3000 = 2000. 2000 small packets were sold.
Q: A sum of Rs. 4,300 is distributed among M, N and O, such that M receives 25% more than N and N receives 25% less than O. What is O’s share in the amount? 1804 05b5cc6b0e4d2b4197774d2d0
5b5cc6b0e4d2b4197774d2d0- 11564false
- 21600true
- 31632false
- 41714false
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Answer : 2. "1600"
Explanation :
Answer: B) 1600 Explanation: Let O's share = Rs. P => N's share = 75100 x P = 3P4 M's share = 54 x 3P4 = 15P16 15P16 + 3P4 + P = 4300=> P = 4300 x 1643 = 1600
Q: A town has a population of 4000 requires 140 liters of water per head. It has a tank measuring 18m x 12m x 8m. The water of this tank will suffice for ____ days? 1802 05b5cc6bfe4d2b4197774da60
5b5cc6bfe4d2b4197774da60- 13true
- 24false
- 35false
- 42false
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Answer : 1. "3"
Explanation :
Answer: A) 3 Explanation: Water required = 4000 x 140 = 560000 lit = 560 cu.m (1 cu.m = 1000 lit) Volume of tank = 18 x 12 x 8 = 1728 cu.m Water of this tank will suffice for = 1728/560 = 3 days.
Q: One card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn find the probability the card drawn is red. 1802 05b5cc6c8e4d2b4197774df1e
5b5cc6c8e4d2b4197774df1e- 12/3false
- 21/2true
- 31/52false
- 413/51false
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Answer : 2. "1/2"
Explanation :
Answer: B) 1/2 Explanation: We know that: When one card is drawn from a pack of 52 cards The numbers of possible outcomes n(s) = 52 We know that there are 26 red cards in the pack of 52 cards⇒ The numbers of favorable outcomes n(E) = 26 Probability of occurrence of an event: P(E)=Number of favorable outcomes/Numeber of possible outcomes=n(E)/n(S) ∴ required probability = 26/52 = 1/2.
Q: The calendar for the year 1988 is same as which upcoming year ? 1801 05b5cc6cfe4d2b4197774e2e3
5b5cc6cfe4d2b4197774e2e3- 12012false
- 22014false
- 32016true
- 42010false
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Answer : 3. "2016"
Explanation :
Answer: C) 2016 Explanation: We already know that the calendar after a leap year repeats again after 28 years. Here year 1988 is a Leap year, then the same calendar will be in the year = 1988 + 28 = 2016.
Q: How many more words can be formed by using the letters of the given word 'CREATIVITY'? 1796 05b5cc6bce4d2b4197774d8d9
5b5cc6bce4d2b4197774d8d9- 1851250false
- 2751210false
- 3362880false
- 4907200true
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Answer : 4. "907200"
Explanation :
Answer: D) 907200 Explanation: The number of letters in the given word CREATIVITY = 10 Here T & I letters are repeated => Number of Words that can be formed from CREATIVITY = 10!/2!x2! = 3628800/4 = 907200
Q: If rupee two produces rupees eleven over a period of 30 years, find the rate of simple interest ? 1796 05b5cc6e2e4d2b4197774ec7f
5b5cc6e2e4d2b4197774ec7f- 117.25 %false
- 218.14 %false
- 318.33 %true
- 417.35 %false
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Answer : 3. "18.33 %"
Explanation :
Answer: C) 18.33 % Explanation: We know that I = PTR/100 11 = (2x30xR)/100 R = 18.333 %
Q: Simple interest on a certain sum at 7% per annum for 4 years is Rs. 2415. What will be the compound interest on the same principal at 4% per annum in two years? 1795 05b5cc6a7e4d2b4197774ce22
5b5cc6a7e4d2b4197774ce22- 1Rs. 704true
- 2Rs. 854false
- 3Rs. 893false
- 4Rs. 914false
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Answer : 1. "Rs. 704"
Explanation :
Answer: A) Rs. 704 Explanation: We know that, S.I. = PTR100⇒ P = S.I x 100T x RAnd also,C.I = P1 + R100n- 1 From given data, P = Rs. 8625 Now, C.I = 86251+41002-1= 862526252-1= 8625676625-1= 8625 x 51625C.I = Rs. 703.80