Quantitative Aptitude Practice Question and Answer
8Q: A goods truck travels from a place at a certain time and at fixed speed. After 6hrs another truck leaves the same place and move in same direction of uniform speed of 90kmph. The truck catches up the goods truck in 4hrs. Find the speed of the goods truck ? 1360 05b5cc745e4d2b4197774f9fe
5b5cc745e4d2b4197774f9fe- 136 kmphtrue
- 232 kmphfalse
- 328 kmphfalse
- 434 kmphfalse
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Answer : 1. "36 kmph"
Explanation :
Answer: A) 36 kmph Explanation: Let the speed of goods truck be 'p' kmphDistance covered by goods truck in 10hrs (4+6) = Distance covered by other truck in 4 hrs. 10p = 4 x 90p = 36kmph.Therefore, the speed of the goods truck is p = 36 kmph.
Q: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is ? 1359 05b5cc6dfe4d2b4197774eac1
5b5cc6dfe4d2b4197774eac1- 11 : 2false
- 23 : 1false
- 34 : 7false
- 43 : 2true
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Answer : 4. "3 : 2"
Explanation :
Answer: D) 3 : 2 Explanation: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23 => 27 x + 17 y = 23 x + 23 y => 4 x = 6 y => x/y = 3/2.
Q: The angle between the minute hand and the hour hand of a clock when the time is 4.15 is 1359 05b5cc6cfe4d2b4197774e328
5b5cc6cfe4d2b4197774e328- 10false
- 237.5true
- 327false
- 415false
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Answer : 2. "37.5"
Explanation :
Answer: B) 37.5 Explanation: Angle between hands of a clock When the minute hand is behind the hour hand, the angle between the two hands at M minutes past H 'o clock => 30H-M5+M2 degrees Here H = 4, M = 15 and the minute hand is behind the hour hand. Hence the angle = 30[4-(15/5)]+15/2 = 30(1)+7.5 = 37.5 degrees
Q: 112 × 54 = 1358 05b5cc6b9e4d2b4197774d752
5b5cc6b9e4d2b4197774d752- 168947false
- 269874false
- 370000true
- 476000false
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Answer : 3. "70000"
Explanation :
Answer: C) 70000 Explanation: 112 × 54112 × 1024= 112 × 1000024= 1120000/16 = 70,000.
Q: On the occasion of New Year, each student of a class sends greeting cards to the others. If there are 21 students in the class, what is the total number of greeting cards exchanged by the students? 1358 05b5cc6b9e4d2b4197774d757
5b5cc6b9e4d2b4197774d757- 1380false
- 2420true
- 3441false
- 4400false
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Answer : 2. "420"
Explanation :
Answer: B) 420 Explanation: Given total number of students in the class = 21 So each student will have 20 greeting cards to be send or receive (21 - 1(himself)) Therefore, the total number of greeting cards exchanged by the students = 20 x 21 = 420.
Q: A woman fills a bucket in 6 minutes. 1845 buckets have to be filled from 8 am. to 9:30 am. How many woman employees should be employed for this task? 1356 05b5cc6b5e4d2b4197774d543
5b5cc6b5e4d2b4197774d543- 1111false
- 2117false
- 3123true
- 4139false
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Answer : 3. "123"
Explanation :
Answer: C) 123 Explanation: We know that, M1 × D1W1 = M2 × D2W2 Here M1 = 1, D1 = 6 min, W1 = 1 and M2 = M, D2 = 90 min, W2 = 1845 1 × 61 = M × 901845 => M = 123
Q: K, L and M can do a piece of work in 20, 30 and 60 days respectively. In how many days can K do the total work if he is assisted by L and M on every third day ? 1355 05b5cc754e4d2b4197774fb86
5b5cc754e4d2b4197774fb86- 115 daystrue
- 213 daysfalse
- 312 daysfalse
- 410 daysfalse
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Answer : 1. "15 days"
Explanation :
Answer: A) 15 days Explanation: In one day work done by K = 1/20 Work done by K in 2 days = 1/10 Work done by K,L,M on 3rd day =1/20 + 1/30 + 1/60 = 1/10 Therefore, workdone in 3 days is = 1/10 + 1/10 = 1/5 1/5th of the work will be completed at the end of 3 days. The remaining work = 1 - 1/5 = 4/5 1/5 of work is completed in 3 days Total work wiil be done in 3 x 5 = 15 days.
Q: If x = 2 + 223 + 213 then find the value of x3-6x2+6x ? 1354 05b5cc745e4d2b4197774fa09
5b5cc745e4d2b4197774fa09- 11false
- 22true
- 33false
- 44false
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Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: Given that x = 2+ 223 + 213 So x - 2 = 223 + 213 Now cubing on both sides, we get => x3-8-6x2+12x = 4 + 2 + 6(x-2) Therefore, x3-6x2+6x = -6 + 8 = 2

