Quantitative Aptitude Practice Question and Answer

Q: If a 36 cm thread is used to wrap a book, lengthwise twice and breadth wise once, what is the size of the book ? 1498 0

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    288 sq.cm
    Correct
    Wrong
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    188 sq.cm
    Correct
    Wrong
  • 3
    144 sq.cm
    Correct
    Wrong
  • 4
    244 sq.cm
    Correct
    Wrong
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Answer : 1. "288 sq.cm"
Explanation :

Answer: A) 288 sq.cm Explanation: Length of the thread is 36 cms. length wise twice breath wise once then totally thrice.so 36/3 = 12.so length is 12 x 2 = 24 cmsbreath is 12 cmsArea of the book = length x breath = 24 x 12 = 288 sq.cm

Q: If x = 2 + 223 + 213 then find the value of x3-6x2+6x ? 1497 0

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    1
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    2
    Correct
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    3
    Correct
    Wrong
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    4
    Correct
    Wrong
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Answer : 2. "2"
Explanation :

Answer: B) 2 Explanation: Given that x = 2+ 223 + 213   So x - 2 = 223 + 213   Now cubing on both sides, we get     => x3-8-6x2+12x = 4 + 2 + 6(x-2)   Therefore, x3-6x2+6x = -6 + 8 = 2

Q: Ratio between heights of two cylinder in the ratio 3:5. Their volumes are in the ratio 27:80. Find ratio between their radius ? 1492 0

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    1:3
    Correct
    Wrong
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    2:1
    Correct
    Wrong
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    3:4
    Correct
    Wrong
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    4:7
    Correct
    Wrong
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Answer : 3. "3:4"
Explanation :

Answer: C) 3:4 Explanation:

Q: What least number must be substracted from 627349 so that the remaining number is divisible by 15 ? 1492 0

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    1
    Correct
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    2
    Correct
    Wrong
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    3
    Correct
    Wrong
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    4
    Correct
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Answer : 4. "4"
Explanation :

Answer: D) 4 Explanation: On dividing 627349 by 15, we get remainder = 4.Therefore, the obtained remainder is the least number to be subtracted from the given number so that the the mnumber is divisible by 15.Here 4 is the least number to be subtracted from 627349 so that it is divisible by 15.

Q: 112 × 54 = 1490 0

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    68947
    Correct
    Wrong
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    69874
    Correct
    Wrong
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    70000
    Correct
    Wrong
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    76000
    Correct
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Answer : 3. "70000"
Explanation :

Answer: C) 70000 Explanation: 112 × 54112 × 1024= 112 × 1000024= 1120000/16 = 70,000.

Q: What is the difference between the compound interests on Rs. 5000 for 11⁄2 years at 4% per annum compounded yearly and half-yearly? 1486 0

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    Rs. 1.80
    Correct
    Wrong
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    Rs. 2.04
    Correct
    Wrong
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    Rs. 3.18
    Correct
    Wrong
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    Rs. 4.15
    Correct
    Wrong
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Answer : 2. "Rs. 2.04"
Explanation :

Answer: B) Rs. 2.04 Explanation: Compound Interest for 1 1⁄2 years when interest is compounded yearly = Rs.(5304 - 5000) Amount after 11⁄2 years when interest is compounded half-yearly Compound Interest for 1 1⁄2 years when interest is compounded half-yearly = Rs.(5306.04 - 5000) Difference in the compound interests = (5306.04 - 5000) - (5304 - 5000)= 5306.04 - 5304 = Rs. 2.04

Q: How many weekends in a year? 1485 0

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    52
    Correct
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    53
    Correct
    Wrong
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    103
    Correct
    Wrong
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    104
    Correct
    Wrong
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Answer : 4. "104"
Explanation :

Answer: D) 104 Explanation: In normal we have 104 Weekend Days. We know that a Each normal year has 365 days or 52 weeks plus one day, and each week has two weekend days, which means there are approximately 104 weekend days each year. Whereas in a leap year we have 366 days it adds one more day to the year. And what makes the change is the starting day of the year.

Q: Rajeev's age is four more than the age of Shilpa. The age of Shilpa can be obtained by subtracting four times her age 4 years ago from the four times her age after 4 years. What was Rajeev's age before 4 years ? 1485 0

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    36 years
    Correct
    Wrong
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    28 years
    Correct
    Wrong
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    32 years
    Correct
    Wrong
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    40 years
    Correct
    Wrong
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Answer : 3. "32 years"
Explanation :

Answer: C) 32 years Explanation: Let Shilpa's present age is p years According to question, p = 4(x+4) – 4(x–4) p = 4x+16 – 4x+16 p = 32 Shilpa's present age = 32 years Rajeev is four years older than Shilpa => Shilpa's present age = Rajeev's age 4 years before. => Rajeev's age 4 years before = 32 years.

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