Quantitative Aptitude Practice Question and Answer
8Q: A container contains 120 lit of Diesel. From this container, 12 lit of Diesel was taken out and replaced by kerosene. This process was further repeated for two times. How much diesel is now there in the container ? 1709 05b5cc6c3e4d2b4197774dc86
5b5cc6c3e4d2b4197774dc86- 188.01 litfalse
- 287.48 littrue
- 387.51 litfalse
- 487.62 litfalse
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Answer : 2. "87.48 lit"
Explanation :
Answer: B) 87.48 lit Explanation: For these type of problems, Quantity of Diesel remained = q1-pqn Here p = 12 , q = 120 => 1201-121203 = 120 x 0.9 x 0.9 x 0.9 = 87.48 lit.
Q: What will come in place of the question mark (?) in the following question ? 52.5% of 800 + 30.5% of 2800 = ? + 87.30 1707 05b5cc6c1e4d2b4197774db2d
5b5cc6c1e4d2b4197774db2d- 11096.30false
- 21226.70false
- 31124.20false
- 41186.70true
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Answer : 4. "1186.70"
Explanation :
Answer: D) 1186.70 Explanation: 52.5% of 800 + 30.5% of 2800 = ? + 87.30 420 + 854 - 87.30 = ? 1274 - 87.30 = ? ? = 1186.70
Q: Ratio between heights of two cylinder in the ratio 3:5. Their volumes are in the ratio 27:80. Find ratio between their radius ? 1707 05b5cc6c5e4d2b4197774dde1
5b5cc6c5e4d2b4197774dde1- 11:3false
- 22:1false
- 33:4true
- 44:7false
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Answer : 3. "3:4"
Explanation :
Answer: C) 3:4 Explanation:
Q: 83% of 2350 = ? 1702 05b5cc6bce4d2b4197774d87c
5b5cc6bce4d2b4197774d87c- 11889.95false
- 21912.35false
- 31875.25false
- 41950.50true
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Answer : 4. "1950.50"
Explanation :
Answer: D) 1950.50 Explanation: 83% of 2350 = ? 83/100 x 2350 =8.3 x 235 =1950.50
Q: There are 11 True or False questions. How many ways can these be answered ? 1698 05b5cc6d0e4d2b4197774e385
5b5cc6d0e4d2b4197774e385- 111!/2false
- 21024false
- 311!false
- 42048true
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Answer : 4. "2048"
Explanation :
Answer: D) 2048 Explanation: Given 11 questions of type True or False Then, Each of these questions can be answered in 2 ways (True or false) Therefore, no. of ways of answering 11 questions = 211 = 2048 ways.
Q: On dividing a number by 96, we get 271 as quotient and 0 as remainder. On dividing the same number by 95, what will be the remainder ? 1697 05b5cc6dde4d2b4197774e9ce
5b5cc6dde4d2b4197774e9ce- 187false
- 259false
- 392false
- 481true
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Answer : 4. "81"
Explanation :
Answer: D) 81 Explanation: Number = 271 x 96 + 0 = 26016 => 95) 26016 (273 25935 -------- 81 Required number = 81.
Q: Manisha went to shop with certain amount, with which she can buy 50 Chacobar or 40 Fivestar. She uses 10% amount for petrol and out of the remaining balance, she purchases 20 Fivestar and some Chacobar. Find the number of Chacobar she can buy? 1697 05b5cc6b3e4d2b4197774d441
5b5cc6b3e4d2b4197774d441- 120true
- 224false
- 326false
- 428false
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Answer : 1. "20"
Explanation :
Answer: A) 20 Explanation: Let the total amount be 200 {L.C.M of 40 and 50} Chacobar C.P. = 200/50 = 4 Fivestar C.P = 200/40 = 5 Remaining Money after petrol = [200 - 200×10%] = 180 Remaining money after buying fivestars = [180 - 20×5] = 80 So number of Chacobar she can buy = 80/4 = 20
Q: One card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn find the probability the card drawn is red. 1696 05b5cc6c8e4d2b4197774df1e
5b5cc6c8e4d2b4197774df1e- 12/3false
- 21/2true
- 31/52false
- 413/51false
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Answer : 2. "1/2"
Explanation :
Answer: B) 1/2 Explanation: We know that: When one card is drawn from a pack of 52 cards The numbers of possible outcomes n(s) = 52 We know that there are 26 red cards in the pack of 52 cards⇒ The numbers of favorable outcomes n(E) = 26 Probability of occurrence of an event: P(E)=Number of favorable outcomes/Numeber of possible outcomes=n(E)/n(S) ∴ required probability = 26/52 = 1/2.