Quantitative Aptitude Practice Question and Answer
8Q: Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is ? 1446 05b5cc6dfe4d2b4197774eac1
5b5cc6dfe4d2b4197774eac1- 11 : 2false
- 23 : 1false
- 34 : 7false
- 43 : 2true
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Answer : 4. "3 : 2"
Explanation :
Answer: D) 3 : 2 Explanation: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23 => 27 x + 17 y = 23 x + 23 y => 4 x = 6 y => x/y = 3/2.
Q: A man purchases two articles, on selling one at loss of 20% while the other at a profit of 25%, he gains the overall profit of 5% than find the ratio of their selling price ? 1444 05b5cc6c7e4d2b4197774de9b
5b5cc6c7e4d2b4197774de9b- 18 : 62.5true
- 255 : 8false
- 38 : 65false
- 464.4 : 9false
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Answer : 1. "8 : 62.5"
Explanation :
Answer: A) 8 : 62.5 Explanation: Article I Article II -20 25% 5% 20% 25% 4 : 5 Now, Selling of first article = (4-20%) = 0.8 Selling of second article = (5+25%) = 6.25 Therefore the ratio of selling price = 8 : 62.5
Q: A goods truck travels from a place at a certain time and at fixed speed. After 6hrs another truck leaves the same place and move in same direction of uniform speed of 90kmph. The truck catches up the goods truck in 4hrs. Find the speed of the goods truck ? 1444 05b5cc745e4d2b4197774f9fe
5b5cc745e4d2b4197774f9fe- 136 kmphtrue
- 232 kmphfalse
- 328 kmphfalse
- 434 kmphfalse
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Answer : 1. "36 kmph"
Explanation :
Answer: A) 36 kmph Explanation: Let the speed of goods truck be 'p' kmphDistance covered by goods truck in 10hrs (4+6) = Distance covered by other truck in 4 hrs. 10p = 4 x 90p = 36kmph.Therefore, the speed of the goods truck is p = 36 kmph.
Q: If x and y are the two digits of the number 653xy such that this number is divisible by 80, then x+y is equal to ? 1441 05b5cc761e4d2b4197774fd62
5b5cc761e4d2b4197774fd62- 15false
- 24false
- 33false
- 42true
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Answer : 4. "2"
Explanation :
Answer: D) 2 Explanation: Since 653xy is divisible by 5 as well as 2, so y = 0.Now, 653x0 must be divisible by 8.So, 3x0 must be divisible by 8. This happens when x = 2x + y = (2 + 0) = 2.
Q: 60 percent of 2/7 of three-fourth of a number is 2664. What is the number ? 1441 05b5cc6c7e4d2b4197774deb9
5b5cc6c7e4d2b4197774deb9- 120720true
- 221352false
- 325421false
- 424150false
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Answer : 1. "20720"
Explanation :
Answer: A) 20720 Explanation: Let N be the required number. => 60100x27x34xN=2664 => N = 2664x2x7x5/9 => N = 20720.
Q: Simplify the following expression? 40% of (244 x ?) = 48 1437 05b5cc6aae4d2b4197774cf5b
5b5cc6aae4d2b4197774cf5b- 124false
- 222false
- 320true
- 418false
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Answer : 3. "20"
Explanation :
Answer: C) 20 Explanation: We know that 40% = 40100 = 25⇒25 x 244 x ? = 48? = 48 x 5 x 42 x 24 = 20
Q: The price of a car is increased by 25%, by how much percent, must the new price of this car be decreased to restore its original price ? 1436 05b5cc6c5e4d2b4197774dda0
5b5cc6c5e4d2b4197774dda0- 120%true
- 224%false
- 321%false
- 425%false
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Answer : 1. "20%"
Explanation :
Answer: A) 20% Explanation: Suppose that the original price of the car = Rs. x Then new price of the car => (x) + (x ×25/100) = Rs. 5x/4 To restore the original price, the new price must be decreased by 5x/4 − x = x/4 So required percentage =(x/4)/(5x/4) × 100% = 20%
Q: A class consists of both boys and girls along with a teacher. After a class, the teacher drinks 9 litres of water, a boy drinks 7 litres of water and a girl drinks 4 litres of water. If after a class 42 litres of water was consumed, find the number of girls in the class ? 1436 05b5cc745e4d2b4197774fa2c
5b5cc745e4d2b4197774fa2c- 18false
- 26false
- 35false
- 43true
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Answer : 4. "3"
Explanation :
Answer: D) 3 Explanation: Given teacher drinks 9 ltrLet number of boys be 'A'.Let number of girls be 'B'.Boy drinks 7 ltr and girl drinks 4 ltrAfter class total water consumed = 42 ltrThen,9 + 7A + 4B = 42=> 7A + 4B = 33By trial and error method,The only integers which satisfy the equation is A = 3 and B = 3Therefore, number of girls in the class = 3.