Answer: A) Rs. 3550 Explanation: Let the cost price of the article be 'P' Then from given data, P + 28P100 = 4544=> 128P = 454400=> P = 3550 Hence, the cost price of the article = P = Rs. 3550

Answer: C) Rs. 7000 Explanation: Let the sum be Rs. S.(S x 18 x 2)/100 - (S x 12 x 2)/100 = 840 => 36S/100 - 24S/100 = 840 => 12S/100 = 840 => S = 7000.

Answer: B) 1/2 Explanation: We know that: When one card is drawn from a pack of 52 cards The numbers of possible outcomes n(s) = 52 We know that there are 26 red cards in the pack of 52 cards⇒ The numbers of favorable outcomes n(E) = 26 Probability of occurrence of an event: P(E)=Number of favorable outcomes/Numeber of possible outcomes=n(E)/n(S) ∴ required probability = 26/52 = 1/2.

Answer: D) 360 mts Explanation: Speed of the Train K is given by s = d/t = 240/20 = 12 m/sDistance covered by Train K in 50 seconds = 12 x 50 = 600 mts.But it crosses Train L in 50 seconds Therefore, the length of the Train L is = 600 - 240 = 360 mts.

Answer: B) 30 Explanation: 332 + 3 = 12552 + 5 = 30

Answer: D) 7:3 Explanation: Ratio of Milk and water in a vessel A is 4 : 1   Ratio of Milk and water in a vessel B is 3 : 2   Ratio of only milk in vessel A = 4 : 5   Ratio of only milk in vessel B = 3 : 5   Let 'x' be the quantity of milk in vessel C   Now as equal quantities are taken out from both vessels A & B   => 4/5     :     3/5               x   3/5-x          x - 4/5   => 35-xx-45 = 11 (equal quantities)   => x = 7/10   Therefore, quantity of milk in vessel C  = 7   => Water quantity = 10 - 7 = 3   Hence the ratio of milk & water in vessel 3 is 7 : 3

Answer: B) 15.69 cm Explanation: Draw the two chords as shown in the figure. Let O be the center of the circle. Draw OC perpendicular to both chords. That divides the two chords in half.So CD = 10 and AB = 14. Draw radii OA and OD, both equal to radius r.We are given that BC = 5, the distance between the two chords. LetOB = x. We use the Pythagorean theorem on right triangle ABO AO² = AB² + OB² r² = 14² + x² We use the Pythagorean theorem on right triangle DCO DO² = CD² + OC² We see that OC = OB+BC = x+5, so r² = 10² + (x+5)² So we have a system of two equations: r² = 14² + x² r² = 10² + (x+5)² Since both left sides equal r², set the right sidesequal to each other. 14² + x² = 10² + (x+5)² 196 + x² = 100 + x² + 10x + 25 196 = 125 + 10x 71 = 10x 7.1 = x r² = 14² + x² r² = 196 + (7.1)² r² = 196 + 50.41 r² = 246.41 r = √246.41 r = 15.69745202 cm

Answer: C) 28 hrs Explanation: 1/K + 1/L + 1/M = 1/8 (Given)Also given that K = 2L and L = 2M=> 1/2L + 1/L + 2/L = 1/8=> (1 + 2 + 4)/2L = 1/8=> 2L/7 = 8=> L = 28 hours.