Quantitative Aptitude Practice Question and Answer
8Q: An item is sold at a loss of 10%. Had it sold for Rs. 9 more, a profit of 25/2% would have gained. What is the cost price of the item? 1464 05b5cc688e4d2b4197774c2f0
5b5cc688e4d2b4197774c2f0- 1Rs. 90false
- 2Rs. 75false
- 3Rs. 55false
- 4Rs. 40true
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Answer : 4. "Rs. 40"
Explanation :
Answer: D) Rs. 40 Explanation: Let the cost price of the item = Rs. 50 Sold at 10% loss => for Rs. 50 loss S.P = Rs. 45 From the given data, 25/2 % gain if it is sold at Rs. 9 more 56.25 - 45 = 9 => 11.25 = 9 => 22.5 = 18 => 45 = 36 => 50 = ? => C.P = 50 x 3645 = 40 Hence, the Cost price of the item = Rs. 40.
Q: Rajesh rows in still water with a speed of 4.5 kmph to go to a certain place and comes back. Find his average speed for the whole journey, if the river is flowing with a speed of 1.5 kmph? 2494 05b5cc67ee4d2b4197774c245
5b5cc67ee4d2b4197774c245- 12 kmphfalse
- 24 kmphtrue
- 36 kmphfalse
- 48 kmphfalse
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Answer : 2. "4 kmph"
Explanation :
Answer: B) 4 kmph Explanation: Let the distance in one direction = k kms Speed in still water = 4.5 kmph Speed of river = 1.5 Hence, speed in upstream = 4.5 - 1.5 = 3 kmph Speed in downstream = 4.5 + 1.5 = 6 kmph Time taken by Rajesh to row upwards = k/3 hrs Time taken by Rajesh to row downwards = k/6 hrs Now, required Average speed =Total distanceTotal speed = 2kk3 + k6 = 2k x 186k + 3k = 4 kmph Therefore, the average speed of the whole journey = 4kmph.
Q: Two trains are running with speeds 30 kmph and 58 kmph respectively in the same direction. A man in the slower train passes the faster train in 18 seconds. Find the length of the faster train? 1821 05b5cc67ee4d2b4197774c23f
5b5cc67ee4d2b4197774c23f- 1105 mtsfalse
- 2115 mtsfalse
- 3120 mtsfalse
- 4140 mtstrue
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Answer : 4. "140 mts"
Explanation :
Answer: D) 140 mts Explanation: Speeds of two trains = 30 kmph and 58 kmph => Relative speed = 58 - 30 = 28 kmph = 28 x 5/18 m/s = 70/9 m/s Given a man takes time to cross length of faster train = 18 sec Now, required Length of faster train = speed x time = 70/9 x 18 = 140 mts.
Q: Rs. 69 were divided among 115 family members so that each lady gets 50 paise less than each gentleman, and each gentleman received twice the paise as each lady received. Find the number of gentlemen in the family? 2363 05b5cc67be4d2b4197774c1f0
5b5cc67be4d2b4197774c1f0- 123true
- 292false
- 348false
- 452false
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Answer : 1. "23"
Explanation :
Answer: A) 23 Explanation: Total number of female members = 115 Let the number of males = x Number of females = y => x + y = 115 ......(1) According to the given data, x + y(0.50) = 69 ......(2) From (1) & (2), we get 0.5y = 46 => y = 46 x 2 = 92 => x = 115 - 92 = 23 Hence, required number of gentlemen in the family = x = 23.
Q: An alloy contains gold and silver in the ratio 5 : 8 and another alloy contains gold and silver in the ratio 5 : 3. If equal amount of both the alloys are melted together, then the ratio of gold and silver in the resulting alloy is ? 2733 05b5cc67be4d2b4197774c1eb
5b5cc67be4d2b4197774c1eb- 1113/108false
- 2105/103true
- 3108/115false
- 4103/113false
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Answer : 2. "105/103"
Explanation :
Answer: B) 105/103 Explanation: As given equal amounts of alloys are melted, let it be 1 kg. Required ratio of gold and silver = 513 + 58813 + 38 = 105103. Hence, ratio of gold and silver in the resulting alloy = 105/103.
Q: Mohan spends 23% of an amount of money on an insurance policy, 33% on food, 19% on children’s education and 16% on recreation. He deposits the remaining amount of Rs. 504 in bank. How much amount does he spend on food and insurance policy together? 1423 05b5cc678e4d2b4197774c160
5b5cc678e4d2b4197774c160- 1Rs. 2326false
- 2Rs. 5876false
- 3Rs. 1741false
- 4Rs. 3136true
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Answer : 4. "Rs. 3136"
Explanation :
Answer: D) Rs. 3136 Explanation: Let total amount = Rs. P Total expenditure = (23 + 33 + 19 + 16)% of P = 91%ofP Remaining money = (100 - 91)% of P = 9% of P But given in the question that, 9% of P = 504 9p/100 = 504 => P = 50400/9 => P = Rs. 5600 Required money spent on Food & Insurance = 23 + 33 % = 56% of 5600 = 56 x 5600/100 = 56 x 56 = Rs. 3136
Q: One year ago the ratio between Maneela’s and Shanthi’s salary was 3 : 4. The ratios of their individual salaries between last year’s and this year’s salaries are 4 : 5 and 2 : 3 respectively. At present the total of their salary is Rs. 4160. The salary of Maneela, now is? 6005 05b5cc678e4d2b4197774c165
5b5cc678e4d2b4197774c165- 1Rs. 1600true
- 2Rs. 1700false
- 3Rs. 1800false
- 4Rs. 1900false
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Answer : 1. "Rs. 1600"
Explanation :
Answer: A) Rs. 1600 Explanation: Let the salaries of Maneela and Shanthi one year before be M1, S1 & now be M2, S2 respectively. Then, from the given data, M1/S1 = 3/4 .....(1) M1/M2 = 4/5 .....(2) S1/S2 = 2/3 .....(3) and M2 + S2 = 4160 .....(4) Solving all these eqtns, we get M2 = Rs. 1600.
Q: Find the odd man out in the following number series? 71, 88, 113, 150, 203, 277 1899 05b5cc678e4d2b4197774c158
5b5cc678e4d2b4197774c158- 1277true
- 2203false
- 3150false
- 4113false
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Answer : 1. "277"
Explanation :
Answer: A) 277 Explanation: The given number series is 71 88 113 150 203 277 +17 +25 +37 +53 +74 +8 +12 +16 +21 +4 +4 +5 The series should be 71 88 112 150 203 276 i.e, the differences of the difference should be +4. Hence, the odd man in the given series is 277.