Quantitative Aptitude Practice Question and Answer
8Q: Praveena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest ? 1311 05b5cc6e7e4d2b4197774edab
5b5cc6e7e4d2b4197774edab- 16true
- 27false
- 39false
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Answer : 1. "6"
Explanation :
Answer: A) 6 Explanation: Let rate = R% and time = R years. Then, (1200 x R x R) / 100 = 432 => R = 6.
Q: The length of a rectangle is 10 cm more than the breadth. Find the diagonal length of rectangle if perimeter is 44 cm ? 1308 05b5cc6cae4d2b4197774e06d
5b5cc6cae4d2b4197774e06d- 112.50 cmfalse
- 214.21 cmfalse
- 315.98 cmfalse
- 417.08 cmtrue
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Answer : 4. "17.08 cm"
Explanation :
Answer: D) 17.08 cm Explanation: Let the length of the rectangle = L cm Then the breadth of the rectangle = (L - 10) cm Perimeter of a rectangle = 2(L + B) cm => 44 = 2(L + L - 10) => 44 = 4L - 20 => 4L = 64 => L = 16 cm => B = L - 10 = 6 cm Diagonal = L2+B2 = 162+62 = 17.08 cm
Q: A train travelling at 48 kmph crosses another train, having half its length and travelling in opposite direction at 42 kmph, in 12 sec. It also covers a bridge in 45 sec. Find the length of the bridge ? 1305 05b5cc6c4e4d2b4197774dcc3
5b5cc6c4e4d2b4197774dcc3- 1250 mtsfalse
- 2400 mtstrue
- 3320 mtsfalse
- 4390 mtsfalse
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Answer : 2. "400 mts"
Explanation :
Answer: B) 400 mts Explanation: Let the length of the 1st train = L mts Speed of 1st train = 48 kmph Now the length of the 2nd train = L/2 mts Speed of 2nd train = 42 kmph Let the length of the bridge = D mts Distance = L + L/2 = 3L/2 Relative speed = 48 + 42 = 90 kmph = 90 x 5/18 = 25 m/s(opposite) Time = 12 sec => 3L/2x25 = 12 => L = 200 mts Now it covers the bridge in 45 sec => distance = D + 200 Time = 45 sec Speed = 48 x5/18 = 40/3 m/s => D + 200/(40/3) = 45 => D = 600 - 200 = 400 mts Hence, the length of the bridge = 400 mts.
Q: In a mixture, the ratio of juice and water is 4 : 3. By adding 6 litre water the ratio of juice and water will be 8 : 7. What is the amount of juice in the original mixture ? 1301 05b5cc6c9e4d2b4197774dfbb
5b5cc6c9e4d2b4197774dfbb- 138 litfalse
- 296 litfalse
- 348 littrue
- 452 litfalse
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Answer : 3. "48 lit"
Explanation :
Answer: C) 48 lit Explanation: Let the amount of juice and water in original mixture '4x' litre and '3x' litre respectively. According to given data, 4x/3x+6 =8/7 28x=24x+48 28x–24x=48 4x = 48 x = 12 Amount of juice = 4x = 4×12 = 48 litre.
Q: Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train? 1297 05b5cc6bee4d2b4197774d97e
5b5cc6bee4d2b4197774d97e- 127 7/9 mtstrue
- 225 8/7 mtsfalse
- 321 1/4 mtsfalse
- 422 mtsfalse
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Answer : 1. "27 7/9 mts"
Explanation :
Answer: A) 27 7/9 mts Explanation: Relative speed = (40 - 20) km/hr = 20 x 5 m/sec = 50 m/sec. 18 9 Length of faster train = 50 x 5 m = 250 m = 27 7 m. 9 9 9
Q: A simple interest earned on certain amount is triple the money when invested for 16 years.what is the interest rate offered ? 1297 05b5cc745e4d2b4197774fa13
5b5cc745e4d2b4197774fa13- 113.33 %false
- 214.25 %false
- 316.98 %false
- 418.75 %true
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Answer : 4. "18.75 %"
Explanation :
Answer: D) 18.75 % Explanation: Given,S.I = 3 Principal Amount=> 3A = A x 16 x R/100By solving, we get => R = 18.75%
Q: Find the value of 1.21x0.91.1x0.11? 1292 05b5cc6cae4d2b4197774e001
5b5cc6cae4d2b4197774e001- 10false
- 21false
- 33true
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Answer : 3. "3"
Explanation :
Answer: C) 3 Explanation: Given 1.21x0.91.1x0.11 = 1.21x100x0.9x101.1x10x0.11x100 = 9 = 3.
Q: One-third of the boys and one-half of the girls of a college participated in a sport. If the number of participating students is 300, out of which 100 are boys. What is the total number of students in the college ? 1291 05b5cc6c3e4d2b4197774dc8b
5b5cc6c3e4d2b4197774dc8b- 1550false
- 2575false
- 3625false
- 4700true
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Answer : 4. "700"
Explanation :
Answer: D) 700 Explanation: Let number of boys = B Number of girls = G From the given data, 1B/3 + 1G/2 = 300 But given B/3 = 100 => B = 300 G/2 = 300 - 100 G = 200 x 2 => G = 400 Therefore, total number of students in the college = B + G = 700.