Quantitative Aptitude Practice Question and Answer
8Q: In a slip test, K got the 15th rank and he was 44th from the bottom of the list of passed students. 4 students did not take up the slip test and 3 students were failed. What is the total strenght of the class ? 1259 05b5cc6cee4d2b4197774e241
5b5cc6cee4d2b4197774e241- 163false
- 262false
- 364false
- 465true
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Answer : 4. "65"
Explanation :
Answer: D) 65 Explanation: Total strength of the class is given by 15 + 44 + 4 + 3 - 1 = 65
Q: Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case ? 1256 05b5cc6dae4d2b4197774e8cd
5b5cc6dae4d2b4197774e8cd- 11020false
- 21040false
- 31060false
- 41022true
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Answer : 4. "1022"
Explanation :
Answer: D) 1022 Explanation: Lowest 4-digit number is 1000.LCM of 3, 4 and 5 is 60.Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 - 40) = 1020.Now, add the remainder 2 that's required. Thus, the answer is 1022.
Q: There is a 3 digited number. 3rd digit is the square root of the 1st digit. 2nd digit is the sum of 1st and 3rd. And that number is divisible by 2,3,6,7. What is that number? 1255 05b5cc715e4d2b4197774f40e
5b5cc715e4d2b4197774f40e- 1121false
- 2943false
- 3462true
- 4Nonefalse
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Answer : 3. "462"
Explanation :
Answer: C) 462 Explanation: Assume that the number is taken as XYZ.Condition 1 => Z = sq.root(x) => Possible digits of X is 1,4,9Condition 2 => Y = X + ZX Y Z1 2 14 6 29 12 3 => (wrong because it is 4 digit.) and 121 is not divisible by 2 The answer is 462.
Q: What will come in place of question mark (?) in the following number series? 4, 3, 4, 7, 15, ? 1249 05b5cc6c5e4d2b4197774dde6
5b5cc6c5e4d2b4197774dde6- 142false
- 244true
- 353false
- 456false
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Answer : 2. "44"
Explanation :
Answer: B) 44 Explanation: 4 3 4 7 15 ? ×1-1 ×1+1 ×2-1 ×2+1 ×3-1 15x3 - 1 = 45 - 1 = 44
Q: A lady took loan from a bank at the rate of 12% p.a. simple interest. After 3 years she had to pay Rs. 5400 interest only for the period. The principal amount borrowed by her was : 1242 05b5cc6dbe4d2b4197774e904
5b5cc6dbe4d2b4197774e904- 1Rs. 15,000true
- 2Rs. 1,50,000false
- 3Rs. 1500false
- 4Rs. 1,62,000false
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Answer : 1. "Rs. 15,000"
Explanation :
Answer: A) Rs. 15,000 Explanation: Principal = Rs.(100 x 5400)/(12 x 3)= Rs. 15000.
Q: A can complete a piece of work in 12 days and B is 60% more efficient than A. In how many days B will complete the same work ? 1234 05b5cc6dde4d2b4197774ea05
5b5cc6dde4d2b4197774ea05- 18.7 hrsfalse
- 25.2 hrsfalse
- 35 hrsfalse
- 47.5 hrstrue
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Answer : 4. "7.5 hrs"
Explanation :
Answer: D) 7.5 hrs Explanation: Ratio of times taken by A and B = 160 : 100A can do the work in 12 daysLet B can do the work in "D" days=> 160:100 = 12 : D=> D = 12 x 100/160 = 7.5 hrs
Q: Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 15 ? 1229 05b5cc741e4d2b4197774f9d6
5b5cc741e4d2b4197774f9d6- 16/19false
- 23/10true
- 37/10false
- 46/17false
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Answer : 2. "3/10"
Explanation :
Answer: B) 3/10 Explanation: Here, S = {1, 2, 3, 4, ...., 19, 20}=> n(s) = 20Let E = event of getting a multiple of 4 or 15 =multiples od 4 are {4, 8, 12, 16, 20}And multiples of 15 means multiples of 3 and 5= {3, 6 , 9, 12, 15, 18, 5, 10, 15, 20}.= the common multiple is only (15).=> E = n(E)= 6Required Probability = P(E) = n(E)/n(S) = 6/20 = 3/10.
Q: There are 3 sections with 5 questions each. If four questions are selected from each section, the chance of getting different questions is ? 1226 05b5cc73de4d2b4197774f920
5b5cc73de4d2b4197774f920- 11000false
- 2625false
- 3525false
- 4125true
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Answer : 4. "125"
Explanation :
Answer: D) 125 Explanation: Methods for selecting 4 questions out of 5 in the first section = 5 x 4 x 3 x 2 x 1/4 x 3 x 2 x 1 = 5. Similarly for other 2 sections also i.e 5 and 5 So total methods = 5 x 5 x 5 = 125.