Quantitative Aptitude Practice Question and Answer
8Q: Manju borrows Rs.5000 for 2 years at 4% p.a. simple interest from Sudha. She immediately lends it to another person at 6 1⁄4% p.a for 2 years. Find her gain in the transaction per year. 1546 05b5cc6cfe4d2b4197774e332
5b5cc6cfe4d2b4197774e332- 1Rs. 101false
- 2Rs. 98.5false
- 3Rs. 124.3false
- 4Rs. 112.5true
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Answer : 4. "Rs. 112.5"
Explanation :
Answer: D) Rs. 112.5 Explanation: Manju borrows Rs. 5000 for 2 years at 4% p.a. simple interest She also lends it at 6 1⁄4% p.a for 2 years => Total Gain = 6 1/4% − 4% = 2 1/4% So her gain in the transaction for 1 year = The simple interest she gets for Rs.5000 for 1 year at 2 1⁄4% per annum = PTR100=5000×94×1100 = Rs. 112.5/ year.
Q: A man can row 8 kmh in still water. If the river is running at 2 kmh, it takes 4 hrs more upstream than to go downstream for the same distance. Then the distance is given by 1542 05b5cc6c8e4d2b4197774df00
5b5cc6c8e4d2b4197774df00- 154 kmsfalse
- 232 kmsfalse
- 345 kmsfalse
- 460 kmstrue
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Answer : 4. "60 kms"
Explanation :
Answer: D) 60 kms Explanation: Let the distance be d. d8-2-d8+2 = 4 => 2d = 120 => d = 60 kms.
Q: Find the lowest 4-digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case ? 1536 05b5cc6dae4d2b4197774e8cd
5b5cc6dae4d2b4197774e8cd- 11020false
- 21040false
- 31060false
- 41022true
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Answer : 4. "1022"
Explanation :
Answer: D) 1022 Explanation: Lowest 4-digit number is 1000.LCM of 3, 4 and 5 is 60.Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 - 40) = 1020.Now, add the remainder 2 that's required. Thus, the answer is 1022.
Q: There is a 3 digited number. 3rd digit is the square root of the 1st digit. 2nd digit is the sum of 1st and 3rd. And that number is divisible by 2,3,6,7. What is that number? 1531 05b5cc715e4d2b4197774f40e
5b5cc715e4d2b4197774f40e- 1121false
- 2943false
- 3462true
- 4Nonefalse
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Answer : 3. "462"
Explanation :
Answer: C) 462 Explanation: Assume that the number is taken as XYZ.Condition 1 => Z = sq.root(x) => Possible digits of X is 1,4,9Condition 2 => Y = X + ZX Y Z1 2 14 6 29 12 3 => (wrong because it is 4 digit.) and 121 is not divisible by 2 The answer is 462.
Q: In a slip test, K got the 15th rank and he was 44th from the bottom of the list of passed students. 4 students did not take up the slip test and 3 students were failed. What is the total strenght of the class ? 1529 05b5cc6cee4d2b4197774e241
5b5cc6cee4d2b4197774e241- 163false
- 262false
- 364false
- 465true
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Answer : 4. "65"
Explanation :
Answer: D) 65 Explanation: Total strength of the class is given by 15 + 44 + 4 + 3 - 1 = 65
Q: Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 15 ? 1515 05b5cc741e4d2b4197774f9d6
5b5cc741e4d2b4197774f9d6- 16/19false
- 23/10true
- 37/10false
- 46/17false
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Answer : 2. "3/10"
Explanation :
Answer: B) 3/10 Explanation: Here, S = {1, 2, 3, 4, ...., 19, 20}=> n(s) = 20Let E = event of getting a multiple of 4 or 15 =multiples od 4 are {4, 8, 12, 16, 20}And multiples of 15 means multiples of 3 and 5= {3, 6 , 9, 12, 15, 18, 5, 10, 15, 20}.= the common multiple is only (15).=> E = n(E)= 6Required Probability = P(E) = n(E)/n(S) = 6/20 = 3/10.
Q: Simplify the following : 4 15 × 3 13 + ? = 20% of 120 1512 05b5cc6a8e4d2b4197774ce71
5b5cc6a8e4d2b4197774ce71- 110true
- 224false
- 336false
- 440false
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Answer : 1. "10"
Explanation :
Answer: A) 10 Explanation: Given equation can be written as 215 x 103 + ? = 24=> 14 + ? = 24=> ? = 24 - 14=> ? = 10
Q: A town having teenagers(boys & girls) of 5000 requires 150 litre of water per head. It has a tank measuring 20 m × 15 m × 5 m. The water of this tank will sufficient for ____ days. 1510 05b5cc6c5e4d2b4197774dd82
5b5cc6c5e4d2b4197774dd82- 18false
- 26false
- 34false
- 42true
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Answer : 4. "2"
Explanation :
Answer: D) 2 Explanation: Total Water reqduired = 5000 × 150 lit = 750,000 litres = 750 cu.m. Volume of tank = 20 × 15 × 5 = 1500 Cu.m. Number of days required =1500/750 = 2 days.