Quantitative Aptitude Practice Question and Answer
8Q: Raju got married 8years ago. His present age is 6/5 times his age at the time of his marriage Raju's sister was 10years younger to him at the time of his marriage. The present age of Raju's sister is ? 4580 05b5cc6e2e4d2b4197774ec61
5b5cc6e2e4d2b4197774ec61- 130false
- 232false
- 338true
- 4Nonefalse
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Answer : 3. "38"
Explanation :
Answer: C) 38 Explanation: Let Raju's age at the time of his marriage = X years Then from given data => X + 8 = 6/5 X X = 40. Since got married 8 years ago, his present age = 48 His sister is 10 years younger => 48 - 10 = 38 years.
Q: A group of men can complete a job in K hours. After every 4 hours, half the number of men working at that point of time leave the job. Continuing this way if the job is finished in 16 hours, what is the value of K ? 4575 05b5cc73ae4d2b4197774f8d8
5b5cc73ae4d2b4197774f8d8- 17 hrsfalse
- 27.5 hrstrue
- 38 hrsfalse
- 48.25 hrsfalse
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Answer : 2. "7.5 hrs"
Explanation :
Answer: B) 7.5 hrs Explanation: Let there are L men job requires LK man hours. job completed in first 4 hrs = L x 4 = 4L job completed in next 4 hrs = 4 x L/2 = 2L job completed in next 4 hrs = 4 x L/4 = L job completed in last 4 hrs = 4 x L/8 = L/2 4L + 2L + L + L/2 = KL K = 7+1/2 = 7.5 hours.
Q: A company requires 12,100 strength. Present employees are 400 ladies and 6400 gents. To reach the target how many ladies required to maintain the same ratio ? 4571 05b5cc741e4d2b4197774f99f
5b5cc741e4d2b4197774f99f- 1400false
- 2600false
- 3900true
- 4700false
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Answer : 3. "900"
Explanation :
Answer: C) 900 Explanation: 6,400 gents, 2400 ladies in that company.So total 8,800employees.for 8,800 employees, we want 2400 ladies.for 12,100employees we want how many ladies ?=> (12,100/8,800) x 2400 = 3300.So we want 3300 - 2400 = 900 more ladies.
Q: Ram and Naresh can complete a work in 20 days while Naresh takes 36 days. They get Rs 720 for it. Find salary of Ram. 4556 25d1497e1489f2f135e08ded4
5d1497e1489f2f135e08ded4- 1Rs 300false
- 2Rs 380false
- 3Rs 400false
- 4Rs 320true
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Answer : 4. "Rs 320"
Q: In a class 60% of the students pass in English and 45% pass in Hindi. If 25% of them pass in both subjects, what percentage of the students fail in both the subjects? 4553 15b5cc601e4d2b4197774b440
5b5cc601e4d2b4197774b440- 120%true
- 225%false
- 330%false
- 415%false
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Answer : 1. "20%"
Explanation :
Answer: A) 20% Explanation: Percentage of students passed in English = 60% Percentage of students passed in Hindi = 45% Percentage of students passed in both subjects = 25% ATQ, Percentage of students passed in only English = 60 - 25 = 35% Percentage of students passed in only Hindi = 45 - 25 = 20% Therefore, Percentage of students failed = 100 - (35 + 25 + 20) = 100 - 80 = 20%.
Q: Two boys are playing on a ground. Both the boys are less than 10 years old. Age of the younger boy is equal to the cube root of the product of the age of the two boys. If we place the digit representing the age of the younger boy to the left of the digit representing the age of the elder boy, we get the age of the father of the younger boy. Similarly, we place the digit representing the age of the elder boy to the left of the digit representing the age of the younger boy and divide the figure by 2, we get the age of the mother of the younger boy. The mother of the younger boy is younger than his father by 3 years. Then, what are the ages of elder and younger boys ? 4529 05b5cc73ae4d2b4197774f8ce
5b5cc73ae4d2b4197774f8ce- 1E = 15 & Y = 3false
- 2E = 14 & Y = 12false
- 3E = 40 & Y = 22false
- 4E = 4 & Y = 2true
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Answer : 4. "E = 4 & Y = 2"
Explanation :
Answer: D) E = 4 & Y = 2 Explanation: Let the the age of the elder boy = E Let the the age of the younger boy = Y Given that Y = cube root of EY => Y3 = EY => E = Y2 .....(1)By the condition of number replacement the age of the father is YE The Mother's age = EY/2 But she is 3 years less than father => EY/2 + 3 = YE2YE = EY + 6 ......(2) Then now from the given options we can identify which satisfies the all the conditions. Here Y =2 and E = 4 satisfies all the conditions.
Q: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ? 4515 05b5cc74fe4d2b4197774faea
5b5cc74fe4d2b4197774faea- 11124false
- 21420false
- 31345false
- 41250true
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Answer : 4. "1250"
Explanation :
Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.
Q: A bus starts from point A to reach at B at 6 am at 60 kmph speed. Another bus starts from point B to reach at A at 50 kmph speed at 8 am. The distance between the two points is 450 km, find at what time both buses will meet. 4512 05d15e1c37567c2609b5685aa
5d15e1c37567c2609b5685aa- 19 amfalse
- 210 amfalse
- 311 amtrue
- 4none of thesefalse
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