Quantitative Aptitude Practice Question and Answer
8Q: John sells his laptop to Mark at a loss of 20% who subsequently sells it to Kevin at a profit of 25%. Kevin after finding some defect in the laptop, returns it to Mark but could recover only Rs.4.50 for every Rs. 5 he had paid. Find the amount of Kevin’s loss if John had paid Rs. 1,75,000 for the laptop ? 4020 05b5cc75ce4d2b4197774fc84
5b5cc75ce4d2b4197774fc84- 1Rs.16,500false
- 2Rs.17,500true
- 3Rs.14,200false
- 4Rs.15,520false
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Answer : 2. "Rs.17,500"
Explanation :
Answer: B) Rs.17,500 Explanation: Let’s assume John bought the laptop for Rs. 100He then sells it to Mark at a loss of 20% => Rs. 80,Who consequently sells it to Kevin at a profit of 25% => Rs. 100Then, Kevin sells it back to Mark for Rs. 90 (Rs.4.50 for every Rs. 5 that he had paid initially), so he suffers a loss of Rs. 10Therefore, for Rs. 100 there is a loss of Rs. 10,Then for Rs. 1,75,000 there will be a loss of Rs. 17,500.
Q: Ten years ago, Karan was thrice as old as Shiva was but 10 years hence, he will be only twice as old. Find Shiva’s present age ? 3997 05b5cc75ee4d2b4197774fcca
5b5cc75ee4d2b4197774fcca- 170 yearsfalse
- 230 yearstrue
- 360 yearsfalse
- 440 yearsfalse
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Answer : 2. "30 years"
Explanation :
Answer: B) 30 years Explanation: Let Karan’s present age be x years and Shiva’s present age be y years.Then, according to the first condition,x - 10 = 3(y - 10) or x - 3y = - 20 ..(1) Now, Karan’s age after 10 years = (x + 10) yearsShiva’s age after 10 years = (y + 10)(x + 10) = 2 (y + 10) or x - 2y = 10 ..(2) Solving (1) and (2), we get x = 70 and y = 30Karan’s age = 70 years and Shiva’s age = 30 years.
Q: Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.85. How much was lent at 5% ? 3993 05b5cc6e9e4d2b4197774eded
5b5cc6e9e4d2b4197774eded- 1Rs. 500true
- 2Rs. 245false
- 3Rs. 1250false
- 4Rs. 635false
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Answer : 1. "Rs. 500"
Explanation :
Answer: A) Rs. 500 Explanation: (kx5x1)/100 + [(1500 - k)x6x1]/100 = 85 5k/100 + 90 – 6k/100 = 85 k/100 = 5 => k = 500
Q: Fresh grapes contain 60% water, while dry grapes contain 40% water. How many kgs of dry grapes can be obtained by 60 kg of fresh grapes? 3946 05b5cc6afe4d2b4197774d1e2
5b5cc6afe4d2b4197774d1e2- 125 kgsfalse
- 230 kgsfalse
- 335 kgsfalse
- 440 kgstrue
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Answer : 4. "40 kgs"
Explanation :
Answer: D) 40 kgs Explanation: The fruit content in both the fresh fruit and dry fruit is the same. Let 'p' kgs of dry grapes are obtained from the 60 kgs of fresh grapes => 60 x 40100 = p x 60100=> p = 40 kgs. Therefore, 40 kgs of Dry grapes are obtained from 60 kgs of Fresh grapes.
Q: A machine was sold at 10% Profit had it been sold for Rs 80 less the seller would have incurred 10% loss. What is cost price of Machine? 3945 25d132ae909a40f38019e53ab
5d132ae909a40f38019e53ab- 1350false
- 2400true
- 3450false
- 4520false
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Answer : 2. "400"
Q: A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current ? 3939 05b5cc6e2e4d2b4197774ec52
5b5cc6e2e4d2b4197774ec52- 11 kmphfalse
- 23.2 kmphfalse
- 31.5 kmphtrue
- 42 kmphfalse
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Answer : 3. "1.5 kmph"
Explanation :
Answer: C) 1.5 kmph Explanation: 72 --- 9 ? ---- 1 => Down Stream = 8 45 ---- 9 ? ---- 1 => Up Stream = 5 Speed od current S = ? S = (8 - 5)/2 = 1.5 kmph.
Q: The ratio of two positive numbers is 3 : 5 and the average of the number is 48. What is the product of numbers? 3910 15b5cc607e4d2b4197774b558
5b5cc607e4d2b4197774b558- 13365false
- 22160true
- 31854false
- 41632false
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Answer : 2. "2160"
Explanation :
Answer: B) 2160 Explanation: Let the number be 3p and 5p ATQ, 8p = 2 x 48 p = 96/8 p = 12 The numbers are 36 and 60. Hence, the product of the numbers = 36 x 60 = 2160.
Q: Complete the missing number in the given series. 5, 20, 76, (—), 448 3907 05b5cc6f4e4d2b4197774f009
5b5cc6f4e4d2b4197774f009- 1185false
- 2225true
- 3415false
- 4232false
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Answer : 2. "225"
Explanation :
Answer: B) 225 Explanation: The series follows the following pattern 5 X 5 – 5 = 20 20 X 4 – 4 = 76 76 X 3 – 3 = 225 225 X 2 – 2 = 448 Hence, the term 225 denoted by (d) completes the series

