Quantitative Aptitude Practice Question and Answer
8Q: Ten years ago, Karan was thrice as old as Shiva was but 10 years hence, he will be only twice as old. Find Shiva’s present age ? 3659 05b5cc75ee4d2b4197774fcca
5b5cc75ee4d2b4197774fcca- 170 yearsfalse
- 230 yearstrue
- 360 yearsfalse
- 440 yearsfalse
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Answer : 2. "30 years"
Explanation :
Answer: B) 30 years Explanation: Let Karan’s present age be x years and Shiva’s present age be y years.Then, according to the first condition,x - 10 = 3(y - 10) or x - 3y = - 20 ..(1) Now, Karan’s age after 10 years = (x + 10) yearsShiva’s age after 10 years = (y + 10)(x + 10) = 2 (y + 10) or x - 2y = 10 ..(2) Solving (1) and (2), we get x = 70 and y = 30Karan’s age = 70 years and Shiva’s age = 30 years.
Q: A bus starts from point A to reach at B at 6 am at 60 kmph speed. Another bus starts from point B to reach at A at 50 kmph speed at 8 am. The distance between the two points is 450 km, find at what time both buses will meet. 3642 05d15e1c37567c2609b5685aa
5d15e1c37567c2609b5685aa- 19 amfalse
- 210 amfalse
- 311 amtrue
- 4none of thesefalse
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Answer : 3. "11 am "
Q: A and B together can complete a work in 10 days. A alone can do it in 40 days. In how many days B alone can complete it? 3641 45d14622a249afd05f7b7b405
5d14622a249afd05f7b7b405- 1true
- 210false
- 38false
- 430/7false
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Answer : 1. " "
Q: At 6′o clock a clock ticks 6 times. The time between first and last ticks is 30 seconds. How long does it tick at 12′o clock ? 3626 05b5cc731e4d2b4197774f7ec
5b5cc731e4d2b4197774f7ec- 166 sectrue
- 255 secfalse
- 336 secfalse
- 424 secfalse
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Answer : 1. "66 sec"
Explanation :
Answer: A) 66 sec Explanation: For ticking 6 times, there are 5 intervals. Each interval has time duration of 30/5 = 6 secs At 12 o'clock, there are 11 intervals,so total time for 11 intervals = 11 x 6 = 66 secs.
Q: At the university entrance exam, a candidate is admitted according to whether he has passed or failed the test. Of the candidates who are really capable, 80 % pass the test and of the incapable, 30 % pass the test. Given that 40 % of the candidates are really capable, then the proportion of the really capable students who can pass the test to the total students who can pass is about ? 3619 05b5cc74ae4d2b4197774fa77
5b5cc74ae4d2b4197774fa77- 111/24false
- 21/5false
- 316/25true
- 46/5false
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Answer : 3. "16/25"
Explanation :
Answer: C) 16/25 Explanation: If there are total 100 candidates, 40 candidates are really capable and 60 candidates are incapable.Of the candidates who are really capable = 80% 40*(80/100)=32 pass the test andof the incapable= 30%60*(30/100)=18 pass the test.Total candidates who passed the test = 32+18 = 50The proportion of the really capable students who can pass the test to the total students who can pass = 32/50 = 16/25.
Q: Complete the missing number in the given series. 5, 20, 76, (—), 448 3604 05b5cc6f4e4d2b4197774f009
5b5cc6f4e4d2b4197774f009- 1185false
- 2225true
- 3415false
- 4232false
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Answer : 2. "225"
Explanation :
Answer: B) 225 Explanation: The series follows the following pattern 5 X 5 – 5 = 20 20 X 4 – 4 = 76 76 X 3 – 3 = 225 225 X 2 – 2 = 448 Hence, the term 225 denoted by (d) completes the series
Q: Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 3 ½ hours if they are walking in the same direction ? 3598 05b5cc6eee4d2b4197774ef11
5b5cc6eee4d2b4197774ef11- 12 9/7 kmfalse
- 23 7/5 kmfalse
- 31 3/4 kmfalse
- 44 3/8 kmtrue
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Answer : 4. "4 3/8 km"
Explanation :
Answer: D) 4 3/8 km Explanation: Relative Speed = 5 ¾ - 4 ½ = 1 ¼ Time = 3 ½ h. Distance = 5/4 x 7/2 = 35/8 = 4 3/8 km.
Q: Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.85. How much was lent at 5% ? 3594 05b5cc6e9e4d2b4197774eded
5b5cc6e9e4d2b4197774eded- 1Rs. 500true
- 2Rs. 245false
- 3Rs. 1250false
- 4Rs. 635false
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Answer : 1. "Rs. 500"
Explanation :
Answer: A) Rs. 500 Explanation: (kx5x1)/100 + [(1500 - k)x6x1]/100 = 85 5k/100 + 90 – 6k/100 = 85 k/100 = 5 => k = 500