Quantitative Aptitude Practice Question and Answer
8Q: Find the odd one out of the following options. 3891 05b5cc6d6e4d2b4197774e679
5b5cc6d6e4d2b4197774e679- 1Sapphirefalse
- 2Rubyfalse
- 3Topazfalse
- 4Granitetrue
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Answer : 4. "Granite"
Explanation :
Answer: D) Granite Explanation: Except Granite all other options belong to the group of precious stones.
Q: In an election between two candidates K and L, the number of valid votes received by K exceeds those received by L by 15% of the total number of votes polled. If 20% of the votes polled were invalid and a total of 8720 votes were polled, then how many valid votes did L get ? 3890 05b5cc6d7e4d2b4197774e6fb
5b5cc6d7e4d2b4197774e6fb- 13241false
- 22457false
- 32642false
- 42834true
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Answer : 4. "2834"
Explanation :
Answer: D) 2834 Explanation: Let the total number of votes polled in the election be 100k.Number of valid votes = 100k - 20% (100k) = 80kLet the number of votes polled in favour of K and L be a and b respectively.a - b = 15% (100k) => a = b + 15k=> a + b = b + 15k + bNow, 2b + 15k = 80k and hence b = 32.5kIt is given that 100k = 872032.5k = 32.5k/100k x 8720 = 2834 The number of valid votes polled in favour of L is 2834.
Q: The age of Sohail, Afzal and Bilal are 17,16 and 12 respectively. If the age of Aslam also included the average of the ages is increased by 5. What is the age of Aslam? 3886 05b5cc61ee4d2b4197774b77e
5b5cc61ee4d2b4197774b77e- 132false
- 233false
- 334false
- 435true
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Answer : 4. "35"
Explanation :
Answer: D) 35 Explanation: Given S = 17 yrs A = 16 yrs B = 12 yrs Average = 17 + 16 + 12/3 = 15 yrs Given if Aslam added to them, their average increases by 5 => Average of 4 members = 20 Let the age of Aslam be 'x' Then, 17 + 16 + 12 + x /4 = 20 => x = 80 - 45 => x = 35. Hence, the age of Aslam is 35 yrs.
Q: A batsman in his 17th innings makes a score of 85 and their by increasing his average by 3. What is his average after the 17th innings ? 3875 05b5cc6e9e4d2b4197774ee01
5b5cc6e9e4d2b4197774ee01- 134false
- 236false
- 335false
- 437true
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Answer : 4. "37"
Explanation :
Answer: D) 37 Explanation: 16x + 85 = 17(x + 3) x = 34 + 3 = 37
Q: Ram can complete ¼ th part of work in 8 days and Shyam can complete 2/4 th of the work in 6 days and Naresh can complete ¾th the work in 12 days. In how many days can they together complete it? 3863 15d147f2b9aeb0a08f1e6721a
5d147f2b9aeb0a08f1e6721a- 1\(6 {11 \over 17 }\)false
- 2\(5 {11 \over 17 }\)true
- 3\(8 {11 \over 17 }\)false
- 4\(7 {11 \over 17 }\)false
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Answer : 2. "\(5 {11 \over 17 }\)"
Q: If 6 engines consume 24 metric tonnes of coal, when each is working 8 hours day, how much coal will be required for 9 engines, each running 13hours a day, it being given that 2 engines of former type consume as much as 3 engines of latter type ? 3860 05b5cc723e4d2b4197774f672
5b5cc723e4d2b4197774f672- 145 metric tonnestrue
- 247 metric tonnesfalse
- 355 metric tonnesfalse
- 434 metric tonnesfalse
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Answer : 1. "45 metric tonnes"
Explanation :
Answer: A) 45 metric tonnes Explanation: 2 engines of former type for one hour consumes (2 x 24)/(6 x8) = 1 metric ton i.e. 3 engines of latter type consumes 1 ton for one hour Hence 9 engines consumes 3 tons for one hour For 15 hours it is 15 x 3 = 45 metric tonnes.
Q: The total number of students in a school is 1224. If the number of girls in the school is 600, what is the respective ratio of the total number of boys to the total number of girls in the school? 3855 15d1b02d11fc62311c7736856
5d1b02d11fc62311c7736856- 126:25true
- 221:17false
- 318:13false
- 45:4false
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Answer : 1. "26:25"
Q: A merchant buys two articles for Rs.600. He sells one of them at a profit of 22% and the other at a loss of 8% and makes no profit or loss in the end. What is the selling price of the article that he sold at a loss ? 3834 05b5cc71be4d2b4197774f4fe
5b5cc71be4d2b4197774f4fe- 1Rs. 404.80true
- 2Rs. 536.80false
- 3Rs.440false
- 4Rs. 160false
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Answer : 1. "Rs. 404.80"
Explanation :
Answer: A) Rs. 404.80 Explanation: Let C1 be the cost price of the first article and C2 be the cost price of the second article.Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%. We know, C1 + C2 = 600.The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2. The total selling price of the first and second article = 1.22C1 + 0.92C2. As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2. Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get1.22C1 + 0.92(600 - C1) = 600or 1.22C1 - 0.92C1 = 600 - 0.92*600or 0.3C1 = 0.08*600 = 48or C1 = 48/(0.3) = 160.If C1 = 160, then C2 = 600 - 160 = 440.The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.