Quantitative Aptitude Practice Question and Answer

Q: The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8,748, its purchase price was ? 3209 0

  • 1
    Rs.14,000
    Correct
    Wrong
  • 2
    Rs.12,000
    Correct
    Wrong
  • 3
    Rs. 12,800
    Correct
    Wrong
  • 4
    Rs. 15,000
    Correct
    Wrong
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Answer : 2. "Rs.12,000"
Explanation :

Answer: B) Rs.12,000 Explanation: We have P = 8748, R = -10 and n = 3Therefore, the purchase price of the machine= P1+R100n= 87481-101003= 8748 x (100/90) x (100/90) x (100/90)= 12,000.   Therefore, the purchase price of the machine was Rs. 12,000.

Q: The ratio of two positive numbers is 3 : 5 and the average of the number is 48. What is the product of numbers? 3204 1

  • 1
    3365
    Correct
    Wrong
  • 2
    2160
    Correct
    Wrong
  • 3
    1854
    Correct
    Wrong
  • 4
    1632
    Correct
    Wrong
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Answer : 2. "2160"
Explanation :

Answer: B) 2160 Explanation: Let the number be 3p and 5p ATQ, 8p = 2 x 48 p = 96/8 p = 12   The numbers are 36 and 60.   Hence, the product of the numbers = 36 x 60 = 2160.

Q: A bus is running at 60 kmph without any stoppage. But, with stoppages its average speed is 50 kmph. Find the time of stoppage by bus per hour. 3187 0

  • 1
    15 minutes/hour
    Correct
    Wrong
  • 2
    20 minutes/hour
    Correct
    Wrong
  • 3
    12 minutes/hour
    Correct
    Wrong
  • 4
    10 minutes/hour
    Correct
    Wrong
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Answer : 4. "10 minutes/hour"

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Answer : 4. "2834"
Explanation :

Answer: D) 2834 Explanation: Let the total number of votes polled in the election be 100k.Number of valid votes = 100k - 20% (100k) = 80kLet the number of votes polled in favour of K and L be a and b respectively.a - b = 15% (100k) => a = b + 15k=> a + b = b + 15k + bNow, 2b + 15k = 80k and hence b = 32.5kIt is given that 100k = 872032.5k = 32.5k/100k x 8720 = 2834 The number of valid votes polled in favour of L is 2834.

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Answer : 2. "2 x (18!)"
Explanation :

Answer: B) 2 x (18!) Explanation: A person can be chosen out of 18 people in 18 ways to be seated between Musharraf and Manmohan. Now consider Musharraf, Manmohan, and the third person, sitting between them, as a single personality, we can arrange them in 17! ways but Musharraf and Manmohan can also be arranged in 2 ways.    Required number of permutations = 18 x (17!) x 2 = 2 x 18!

Q: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ? 3133 0

  • 1
    145
    Correct
    Wrong
  • 2
    165
    Correct
    Wrong
  • 3
    175
    Correct
    Wrong
  • 4
    135
    Correct
    Wrong
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Answer : 3. "175"
Explanation :

Answer: C) 175 Explanation: Given that,  working days = 5  working hours = 8  A man get rupess per hour is Rs.2.40  So in one day the man get total rupees is 2.40 x 8 = 19.2  So in 5 days week the man get total rupees is 19.2 x 5 = 96  So in 4 week the man get total rupees is 96 x 4 = 384  So the man worked for = 160hours in 4 weeks    But given that the man earned Rs.432    Hence remaning money is (432-384 = 48)which is earn by doing overtime work   Overtime hours  = 48/3.20 = 15 So total worked hours is = 15 + 160 = 175.

Q: A does half as much work as Band C does half as much work as A and B together. If C alone can finish the work in 40 days, then together ,all will finish the work in  ? 3121 0

  • 1
    17 + 4/7 days
    Correct
    Wrong
  • 2
    13 + 1/3 days
    Correct
    Wrong
  • 3
    15 + 3/2 days
    Correct
    Wrong
  • 4
    16 days
    Correct
    Wrong
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Answer : 2. "13 + 1/3 days"
Explanation :

Answer: B) 13 + 1/3 days Explanation: C alone can finish the work in 40 days.As given C does half as much work as A and B together => (A + B) can do it in 20 days(A + B)s 1 days wok = 1/20.A's 1 days work : B's 1 days Work = 1/2 : 1 = 1:2(given)A's 1 day’s work = (1/20) x (1/3) = (1/60) [Divide 1/20 in the raio 1:2]B's 1 days work = (1/20) x (2/3) = 1/30(A+B+C)'s 1 day's work = (1/60) + (1/30) + (1/40) = 9/120 = 3/40 All the three together will finish it in 40/3 = 13 and 1/3 days.

Q: A person sold two cows each for Rs.9900. If he gained 10% on one and lost 20% on the other, then which of the following is true ? 3119 0

  • 1
    He lost Rs. 200
    Correct
    Wrong
  • 2
    He gained Rs. 200
    Correct
    Wrong
  • 3
    Neither he gained nor lost
    Correct
    Wrong
  • 4
    None of the above
    Correct
    Wrong
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Answer : 4. "None of the above"
Explanation :

Answer: D) None of the above Explanation: In first he got Rs. 990 But in second he lost Rs. 1980 So he lost Rs. 990.

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