Quantitative Aptitude Practice Question and Answer
8Q: Equal quantities of three mixtures of milk and water are mixed in the ratio 1:2, 2:3 and 3:4. The ratio of water and milk in the mixture is ? 3109 05b5cc73ae4d2b4197774f8c9
5b5cc73ae4d2b4197774f8c9- 1193 : 122true
- 297 : 102false
- 3115 : 201false
- 4147 : 185false
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Answer : 1. "193 : 122"
Explanation :
Answer: A) 193 : 122 Explanation: Given the three mixtures ratio as (1:2),(2:3),(3:4) (1+2),(2+3),(3+4) Total content = 3,5,7 Given equal quantities of the three mixtures are mixed, then LCM of 3, 5, 7 = 105 105/3 = 35 , 105/5 = 21 , 105/7 = 15 Now, the individual equal quantity ratios are (35x1, 35x2), (21x2, 21x3), (15x3, 15x4) i.e (35,70), (42,63), (45,60) So overall mixture ratio of milk and water is 35+42+45 : 70+63+60 122:193 But in the question asked the ratio of water to milk = 193 : 122
Q: P and Q were assigned to do a work for an amount of 1200. P alone can do it in 15 days while Q can do it in 12 days. With the help of R they finish the work in 6 days. Find the share of R ? 3108 05b5cc731e4d2b4197774f814
5b5cc731e4d2b4197774f814- 1120true
- 2240false
- 3360false
- 4180false
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Answer : 1. "120"
Explanation :
Answer: A) 120 Explanation: 1/15 + 1/12 + 1/R = 1/6, we got R = 60 (it means R will take 60 days to complete the work alone) so ratio of work done by P:Q:R = 1/15 : 1/12 : 1/60 = 5 : 4 : 1 so R share = (1/10) x 1200 = 120.
Q: The age of Sohail, Afzal and Bilal are 17,16 and 12 respectively. If the age of Aslam also included the average of the ages is increased by 5. What is the age of Aslam? 3104 05b5cc61ee4d2b4197774b77e
5b5cc61ee4d2b4197774b77e- 132false
- 233false
- 334false
- 435true
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Answer : 4. "35"
Explanation :
Answer: D) 35 Explanation: Given S = 17 yrs A = 16 yrs B = 12 yrs Average = 17 + 16 + 12/3 = 15 yrs Given if Aslam added to them, their average increases by 5 => Average of 4 members = 20 Let the age of Aslam be 'x' Then, 17 + 16 + 12 + x /4 = 20 => x = 80 - 45 => x = 35. Hence, the age of Aslam is 35 yrs.
Q: If (89)2 is added to the square of a number, the answer so obtained is 16202. What is the (1/26) of that number? 3103 05b5cc6bde4d2b4197774d947
5b5cc6bde4d2b4197774d947- 15.65false
- 22.7false
- 33.5true
- 46.66false
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Answer : 3. "3.5"
Explanation :
Answer: C) 3.5 Explanation: Let the number is = x (89)2 + x2 = 16202 x2 = 8281 x = 91 => (1/26) of 91 = 3.5
Q: Mother’s age today is thrice as her daughter’s. After 10 years it would be just double. How old is the daughter today ? 3101 05b5cc75ee4d2b4197774fcde
5b5cc75ee4d2b4197774fcde- 18 yearsfalse
- 29 yearsfalse
- 310 yearstrue
- 411 yearsfalse
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Answer : 3. "10 years"
Explanation :
Answer: C) 10 years Explanation: Let the age of the daughter today be ‘x’ years. Mother’s age today = 3x years After 10 years, we have 3x + 10 = 2(x + 10) x = 10 years.
Q: A merchant buys two articles for Rs.600. He sells one of them at a profit of 22% and the other at a loss of 8% and makes no profit or loss in the end. What is the selling price of the article that he sold at a loss ? 3101 05b5cc71be4d2b4197774f4fe
5b5cc71be4d2b4197774f4fe- 1Rs. 404.80true
- 2Rs. 536.80false
- 3Rs.440false
- 4Rs. 160false
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Answer : 1. "Rs. 404.80"
Explanation :
Answer: A) Rs. 404.80 Explanation: Let C1 be the cost price of the first article and C2 be the cost price of the second article.Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%. We know, C1 + C2 = 600.The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2. The total selling price of the first and second article = 1.22C1 + 0.92C2. As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2. Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get1.22C1 + 0.92(600 - C1) = 600or 1.22C1 - 0.92C1 = 600 - 0.92*600or 0.3C1 = 0.08*600 = 48or C1 = 48/(0.3) = 160.If C1 = 160, then C2 = 600 - 160 = 440.The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.
Q: In a class 60% of the students pass in English and 45% pass in Hindi. If 25% of them pass in both subjects, what percentage of the students fail in both the subjects? 3099 15b5cc601e4d2b4197774b440
5b5cc601e4d2b4197774b440- 120%true
- 225%false
- 330%false
- 415%false
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Answer : 1. "20%"
Explanation :
Answer: A) 20% Explanation: Percentage of students passed in English = 60% Percentage of students passed in Hindi = 45% Percentage of students passed in both subjects = 25% ATQ, Percentage of students passed in only English = 60 - 25 = 35% Percentage of students passed in only Hindi = 45 - 25 = 20% Therefore, Percentage of students failed = 100 - (35 + 25 + 20) = 100 - 80 = 20%.
Q: What is 90 days from today? Hints : Today is 20th January 2017, Sunday 3098 05b5cc6b5e4d2b4197774d516
5b5cc6b5e4d2b4197774d516- 118th April, Fridayfalse
- 220th April, Saturdaytrue
- 321th April, Sundayfalse
- 419th April, Saturdayfalse
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Answer : 2. "20th April, Saturday"
Explanation :
Answer: B) 20th April, Saturday Explanation: Given Today is 20th January 2017, Sunday In january, we have 31 days February - 28 days (Non leap year) March - 31 days April - 30 days => Remaining days => 31 - 20 = 11 in Jan + 28 in Feb + 31 in Mar = 11 + 28 + 31 = 70 days More 20 days to complete 90 days => upto 20th April Therefore, after 90 days from today i.e, 20th Jan 2017 is 20th Apr 2017. Now, the day of the week will be 90/7 => Remainder '6' As the day starts with '0' on sunday 6 => Saturday. Required day is 20th April, Saturday.