Quantitative Aptitude Practice Question and Answer
8Q: 80% of 900 + 162 x 4 x ? = 113 - 99 3297 05b5cc669e4d2b4197774bf6d
5b5cc669e4d2b4197774bf6d- 10.5true
- 21false
- 34false
- 40false
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Answer : 1. "0.5"
Explanation :
Answer: A) 0.5 Explanation: 80x900/100 + 256 x 4 x ? = 1331 - 99 720 + 1024 x ? = 1232 ? = 1232 - 720/1024 ? = 512/1024 = 0.5 ? = 0.5
Q: A, B and C can complete a work in 10, 15 and 20 days respectively. A and B start it together. B is replaced by C after 2 days. A leave it after one more day. In how many days work was completed? 3287 05d1485969aeb0a08f1e67225
5d1485969aeb0a08f1e67225- 113false
- 2\(13 {1 \over 13 }\)true
- 3\(18 {4 \over 3 }\)false
- 418false
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Answer : 2. " \(13 {1 \over 13 }\)"
Q: A shopkeeper earns a profit equal to the selling price of 11 meter by selling 22-meter cloth. Find the profit percent. 3279 15d1331bc925caa2d5bbbff70
5d1331bc925caa2d5bbbff70- 150%true
- 252%false
- 345%false
- 455%false
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Answer : 1. "50%"
Q: What is the probability of an impossible event? 3273 05b5cc69ee4d2b4197774c995
5b5cc69ee4d2b4197774c995- 10true
- 2-1false
- 30.1false
- 41false
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Answer : 1. "0"
Explanation :
Answer: A) 0 Explanation: The probability of an impossible event is 0. The event is known ahead of time to be not possible, therefore by definition in mathematics, the probability is defined to be 0 which means it can never happen. The probability of a certain event is 1.
Q: How many 7 digit numbers can be formed using the digits 1, 2, 0, 2, 4, 2, 4? 3269 05b5cc7d1e4d2b41977751295
5b5cc7d1e4d2b41977751295- 1120false
- 2360true
- 3240false
- 4424false
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Answer : 2. "360"
Explanation :
Answer: B) 360 Explanation: There are 7 digits 1, 2, 0, 2, 4, 2, 4 in which 2 occurs 3 times, 4 occurs 2 times. Number of 7 digit numbers = 7!3!×2! = 420 But out of these 420 numbers, there are some numbers which begin with '0' and they are not 7-digit numbers. The number of such numbers beginning with '0'. =6!3!×2! = 60 Hence the required number of 7 digits numbers = 420 - 60 = 360
Q: A batsman scores 26 runs and increases his average from 14 to 15. Find the runs to be made if he wants top increasing the average to 19 in the same match ? 3265 05b5cc745e4d2b4197774fa22
5b5cc745e4d2b4197774fa22- 174true
- 279false
- 372false
- 460false
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Answer : 1. "74"
Explanation :
Answer: A) 74 Explanation: Number of runs scored more to increse the ratio by 1 is 26 - 14 = 12To raise the average by one (from 14 to 15), he scored 12 more than the existing average.Therefore, to raise the average by five (from 14 to 19), he should score 12 x 5 = 60 more than the existing average. Thus he should score 14 + 60 = 74.
Q: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ? 3257 05b5cc6dce4d2b4197774e960
5b5cc6dce4d2b4197774e960- 15:3false
- 21:4false
- 34:1false
- 49:1true
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Answer : 4. "9:1"
Explanation :
Answer: D) 9:1 Explanation: Milk = 3/5 x 20 = 12 liters, water = 8 liters If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters. Remaining milk = 12 - 6 = 6 liters Remaining water = 8 - 4 = 4 liters 10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters. The ratio of milk and water in the new mixture = 16:4 = 4:1 If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 x 10 = 8 liters. Amount of water removed = 2 liters. Remaining milk = (16 - 8) = 8 liters. Remaining water = (4 -2) = 2 liters. Now 10 lts milk is added => total milk = 18 lts The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.
Q: The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ? 3254 05b5cc6dee4d2b4197774ea79
5b5cc6dee4d2b4197774ea79- 12413 sq.mfalse
- 21234 sq.mfalse
- 34312 sq.mtrue
- 42143 sq.mfalse
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Answer : 3. "4312 sq.m"
Explanation :
Answer: C) 4312 sq.m Explanation: Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively. 2πs = 264 and 2πl = 352 s = 2642π and l = 3522π Difference between the areas =πl2-πs2 = π1762π2-1322π2 = 1762π-1322π = (176 - 132)(176 + 132) / π = (44 x 308) / (22/7) = 4312 sq.m