Quantitative Aptitude Practice Question and Answer
8Q: How many 7 digit numbers can be formed using the digits 1, 2, 0, 2, 4, 2, 4? 3070 05b5cc7d1e4d2b41977751295
5b5cc7d1e4d2b41977751295- 1120false
- 2360true
- 3240false
- 4424false
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Answer : 2. "360"
Explanation :
Answer: B) 360 Explanation: There are 7 digits 1, 2, 0, 2, 4, 2, 4 in which 2 occurs 3 times, 4 occurs 2 times. Number of 7 digit numbers = 7!3!×2! = 420 But out of these 420 numbers, there are some numbers which begin with '0' and they are not 7-digit numbers. The number of such numbers beginning with '0'. =6!3!×2! = 60 Hence the required number of 7 digits numbers = 420 - 60 = 360
Q: A batsman scores 26 runs and increases his average from 14 to 15. Find the runs to be made if he wants top increasing the average to 19 in the same match ? 3069 05b5cc745e4d2b4197774fa22
5b5cc745e4d2b4197774fa22- 174true
- 279false
- 372false
- 460false
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Answer : 1. "74"
Explanation :
Answer: A) 74 Explanation: Number of runs scored more to increse the ratio by 1 is 26 - 14 = 12To raise the average by one (from 14 to 15), he scored 12 more than the existing average.Therefore, to raise the average by five (from 14 to 19), he should score 12 x 5 = 60 more than the existing average. Thus he should score 14 + 60 = 74.
Q: Rs. 2600 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/2:1/3:1/4 ? 3065 05b5cc6d8e4d2b4197774e7bf
5b5cc6d8e4d2b4197774e7bf- 1600true
- 2300false
- 3150false
- 475false
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Answer : 1. "600"
Explanation :
Answer: A) 600 Explanation: 1/2:1/3:1/4 = 6:4:3 As the difference is 3 => 3/13x2600 = 600
Q: Ram and Raj start a business with investments of Rs. 2500 and Rs. 2250 respectively. After 2 months, Ram takes out Rs.1250 from his capital. After 1 more month, Raj takes out Rs.750 of his capital while Rakesh joins them with a capital of Rs. 3500. At the end of 6 months, they earn a profit of Rs. 2540. Which of the following is the share of each member in the profit ? 3063 05b5cc72ce4d2b4197774f783
5b5cc72ce4d2b4197774f783- 1Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 840true
- 2Ram - Rs. 900, Raj - Rs. 800, Rakesh - Rs. 840false
- 3Ram - Rs. 840, Raj - Rs. 920, Rakesh - Rs. 840false
- 4Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 940false
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Answer : 1. "Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 840"
Explanation :
Answer: A) Ram - Rs. 800, Raj - Rs. 900, Rakesh - Rs. 840 Explanation: Initial investment of Ram = Rs.2500.After 2 months he withdraw Rs.1250 from his capital.Therefore, we have, Ram invested Rs.2500 for 2 months and Rs.(2500-1250=) 1250 for 4 months. Raj invested Rs. 2250 for 3 months and Rs.(2250-750=) 1500 for 3 months. And, Rakesh invested Rs.3500 for 3 months; Their investing ratio:Ram:Raj:Rakesh = (2500x2 + 1250x4):(2250x3 + 1500x3):(3500x3)= (10,000):(11,250):(10,500) = 1000:1125:1050 = 40:45:42 Total profit for 6 months = Rs.2540Therefore, Ram's share = Rs.(2540 x 40/(40+45+42)) = Rs.(2540 x 40/127) = Rs.800Raj's share = Rs.(2540 x 45/127) = Rs.900Rakesh's share = Rs.(2540 x 42/127) = Rs.840
Q: Find the odd man out in the following number series? 5, 4, 9, 32, 273 3060 05b5cc695e4d2b4197774c500
5b5cc695e4d2b4197774c500- 14false
- 29false
- 332true
- 4273false
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Answer : 3. "32"
Explanation :
Answer: C) 32 Explanation: The given number series follows 5, 4, 9, 32, 308 pattern that 5 5 x 1 - 1 = 4 4 x 3 - 3 = 9 9 x 5 - 5 = 40 (not equals to 32) 40 x 7 - 7 = 273 Hence, the odd man in the given number series is 32.
Q: If 34 men completed 2/5th of a work in 8 days working 9 hours a day. How many more man should be engaged to finish the rest of the work in 6 days working 9 hours a day ? 3040 05b5cc6d9e4d2b4197774e807
5b5cc6d9e4d2b4197774e807- 1101 menfalse
- 2112 menfalse
- 3102 mentrue
- 4120 menfalse
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Answer : 3. "102 men"
Explanation :
Answer: C) 102 men Explanation: From the above formula i.e (m1 x t1/w1) = (m2 x t2/w2) so, [(34 x 8 x 9)/(2/5)] = [(M x 6 x 9)/(3/5)] so, M = 136 men Number of men to be added to finish the work = 136-34 = 102 men.
Q: If 10 men take 15 days to complete a work. In how many days will 37 men complete the work? 3036 05b5cc6bfe4d2b4197774da3d
5b5cc6bfe4d2b4197774da3d- 13 daysfalse
- 24 daystrue
- 35 daysfalse
- 46 daysfalse
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Answer : 2. "4 days"
Explanation :
Answer: B) 4 days Explanation: Given 10 men take 15 days to complete a work => Total mandays = 15 x 10 = 150 Let the work be 150 mandays. => Now 37 men can do 150 mandays in 150/37 =~ 4 days
Q: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ? 3034 05b5cc6dce4d2b4197774e960
5b5cc6dce4d2b4197774e960- 15:3false
- 21:4false
- 34:1false
- 49:1true
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Answer : 4. "9:1"
Explanation :
Answer: D) 9:1 Explanation: Milk = 3/5 x 20 = 12 liters, water = 8 liters If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters. Remaining milk = 12 - 6 = 6 liters Remaining water = 8 - 4 = 4 liters 10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters. The ratio of milk and water in the new mixture = 16:4 = 4:1 If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 x 10 = 8 liters. Amount of water removed = 2 liters. Remaining milk = (16 - 8) = 8 liters. Remaining water = (4 -2) = 2 liters. Now 10 lts milk is added => total milk = 18 lts The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.

