Quantitative Aptitude Practice Question and Answer
8Q: A, B and C can complete a work in 10, 15 and 20 days respectively. A and B start it together. B is replaced by C after 2 days. A leave it after one more day. In how many days work was completed? 3079 05d1485969aeb0a08f1e67225
5d1485969aeb0a08f1e67225- 113false
- 2\(13 {1 \over 13 }\)true
- 3\(18 {4 \over 3 }\)false
- 418false
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Answer : 2. " \(13 {1 \over 13 }\)"
Q: If 10 men take 15 days to complete a work. In how many days will 37 men complete the work? 3073 05b5cc6bfe4d2b4197774da3d
5b5cc6bfe4d2b4197774da3d- 13 daysfalse
- 24 daystrue
- 35 daysfalse
- 46 daysfalse
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Answer : 2. "4 days"
Explanation :
Answer: B) 4 days Explanation: Given 10 men take 15 days to complete a work => Total mandays = 15 x 10 = 150 Let the work be 150 mandays. => Now 37 men can do 150 mandays in 150/37 =~ 4 days
Q: What is the probability of an impossible event? 3071 05b5cc69ee4d2b4197774c995
5b5cc69ee4d2b4197774c995- 10true
- 2-1false
- 30.1false
- 41false
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Answer : 1. "0"
Explanation :
Answer: A) 0 Explanation: The probability of an impossible event is 0. The event is known ahead of time to be not possible, therefore by definition in mathematics, the probability is defined to be 0 which means it can never happen. The probability of a certain event is 1.
Q: 26 men can complete a piece of work in 17 days. How many more men must be hired to complete the work in 13 days? 3069 15d14995a489f2f135e08df26
5d14995a489f2f135e08df26- 19false
- 28true
- 36false
- 418false
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Answer : 2. "8"
Q: A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement ? 3068 05b5cc6e7e4d2b4197774edb0
5b5cc6e7e4d2b4197774edb0- 11900true
- 22100false
- 31700false
- 42000false
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Answer : 1. "1900"
Explanation :
Answer: A) 1900 Explanation: Given 2000 ---- 54 days The provisions for 2000 men for 39 days can be completed by 'm' men for only 20 days. i.e, 2000 ----- 39 days == m ---- 20 days => m x 20 = 2000 x 39 m = 3900 So total men for 20 days is 3900 => 2000 old and 1900 new reinforcement. Hence, reinforcement = 1900.
Q: A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's husband age is ? 3067 05b5cc720e4d2b4197774f613
5b5cc720e4d2b4197774f613- 145false
- 224false
- 342false
- 454true
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Answer : 4. "54"
Explanation :
Answer: D) 54 Explanation: By trial and error method from the given options, as 54 - 45 = (1/11) x (45+54) = 99/11 = 9 Hence this satisfies the given conditions. Then the woman's husband age is 54.
Q: Find the odd one out of the floowing number series? 270, 261, 279, 252, 289, 243 3057 05b5cc639e4d2b4197774ba8c
5b5cc639e4d2b4197774ba8c- 1270false
- 2279false
- 3289true
- 4243false
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Answer : 3. "289"
Explanation :
Answer: C) 289 Explanation: Here the given number series is 270, 261, 279, 252, 289, 243 270 - 9 = 261 261 + 18 = 279 279 - 27 = 252 252 + 36 = 288 (not equals to 289) 288 - 45 = 243 Hence, the odd number in the given number series is 289.
Q: Sum of the ages of Rajesh, Suresh, Mahesh and Dinesh is 76 years. 7 years hence, their age ratio is 7:6:5:8. Find Mahesh’s present age ? 3048 05b5cc6c2e4d2b4197774dba5
5b5cc6c2e4d2b4197774dba5- 117 yearsfalse
- 213 yearstrue
- 314 yearsfalse
- 416 yearsfalse
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Answer : 2. "13 years"
Explanation :
Answer: B) 13 years Explanation: Given R + S + M + D = 76 => R+7 : S+7 : M+7 : D+7 = 7:6:5:8 => Let the ratio = x => M+7 = 5x => M = 5x-7 => R = 7x-7 => S = 6x-7 => D = 8x-7 => R + S + M + D = 76 => 7x-7 + 6x-7 + 5x-7 + 8x-7 = 76 => 26x - 28 = 76 => 26x = 104 => x = 4 => Mahesh's present age = 5x-7 = 20 - 7 = 13 years.