Quantitative Aptitude Practice Question and Answer

Q: A rectangular block has the dimensions 5x6x7 cm it is dropped into a cylindrical vessel of radius 6cm and height 10 cm. If the level of the fluid in the cylinder rises by 4 cm, What portion of the block is immersed in the fluid ? 3295 0

  • 1
    22/7 x 24/35
    Correct
    Wrong
  • 2
    22/7 x 36 x 4
    Correct
    Wrong
  • 3
    22/7 x 36/5
    Correct
    Wrong
  • 4
    22/7 x 37/21
    Correct
    Wrong
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Answer : 1. "22/7 x 24/35"
Explanation :

Answer: A) 22/7 x 24/35 Explanation: Since level of water increased in cylinder by height 4.  This is because of the rectangular block .   Therefore , area of rectangular block immersed in water is  = 227×6×6×4   Thats why portion of block immersed in water is  = (22/7 * 36 * 4) / total vol. of rectangle  = (22/7 * 36 * 4)/ (7*5*6)  = (22/7 * 24)/ 35.

Q: Cube root of 729 then square it 3293 0

  • 1
    9
    Correct
    Wrong
  • 2
    36
    Correct
    Wrong
  • 3
    81
    Correct
    Wrong
  • 4
    144
    Correct
    Wrong
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Answer : 3. "81"
Explanation :

Answer: C) 81 Explanation: 729 = 9 x 9 x 9 => Cube root of 729 = 9   Now, required square of 9 = 9 x 9 = 81.

Q: A certain work can be completed in 100 days by a certain number of men. But, due to the absence of 10 people it could be completed in 110 days. How many workers were employed initially? 3279 0

  • 1
    100
    Correct
    Wrong
  • 2
    110
    Correct
    Wrong
  • 3
    55
    Correct
    Wrong
  • 4
    50
    Correct
    Wrong
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Answer : 2. " 110"

Q: Find the odd one out of the floowing number series? 270, 261, 279, 252, 289, 243 3278 0

  • 1
    270
    Correct
    Wrong
  • 2
    279
    Correct
    Wrong
  • 3
    289
    Correct
    Wrong
  • 4
    243
    Correct
    Wrong
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Answer : 3. "289"
Explanation :

Answer: C) 289 Explanation: Here the given number series is 270, 261, 279, 252, 289, 243 270 - 9 = 261 261 + 18 = 279 279 - 27 = 252 252 + 36 = 288 (not equals to 289) 288 - 45 = 243   Hence, the odd number in the given number series is 289.

Q: Three men, four women and six children can complete a work in 9 days. A women does  double the work a man does and a child does half the work a man does. How many women alone can complete this work in 9 days? 3274 0

  • 1
    7
    Correct
    Wrong
  • 2
    8
    Correct
    Wrong
  • 3
    9
    Correct
    Wrong
  • 4
    6
    Correct
    Wrong
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Answer : 1. "7"
Explanation :

Answer: A) 7 Explanation: Given (3 Men + 4 Women + 6 Children) -----> 9 days But W = 2M and C = M/2 Now, convert Men and Children into Women by 3W2 + 4W + 6W4=> 32 + 4 + 32 = 7 Women  Therefore, 7 women alone can complete this work in 9 days.

Q: How many parallelograms will be formed if 7 parallel horizontal lines intersect 6 parallel vertical lines? 3272 0

  • 1
    215
    Correct
    Wrong
  • 2
    315
    Correct
    Wrong
  • 3
    415
    Correct
    Wrong
  • 4
    115
    Correct
    Wrong
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Answer : 2. "315"
Explanation :

Answer: B) 315 Explanation: Parallelograms are formed when any two pairs of parallel lines (where each pair is not parallel to the other pair) intersect.   Hence, the given problem can be considered as selecting pairs of lines from the given 2 sets of parallel lines.   Therefore, the total number of parallelograms formed = 7C2 x 6C2 = 315

Q: How many zeros are there from 1 to 10000 ? 3269 0

  • 1
    2893
    Correct
    Wrong
  • 2
    4528
    Correct
    Wrong
  • 3
    6587
    Correct
    Wrong
  • 4
    4875
    Correct
    Wrong
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Answer : 1. "2893"
Explanation :

Answer: A) 2893 Explanation: For solving this problem first we would break the whole range in 5 sections 1) From 1 to 9Total number of zero in this range = 0 2) From 10 to 99Total possibilities = 9*1 = 9 ( here 9 is used for the possibilities of a non zero integer) 3) From 100 to 999 - three type of numbers are there in this range a) x00 b) x0x c) xx0 (here x represents a non zero number)Total possibilities for x00 = 9*1*1 = 9, hence total zeros = 9*2 = 18for x0x = 9*1*9 = 81, hence total zeros = 81similarly for xx0 = 81 total zeros in three digit numbers = 18 + 81 +81 = 180 4) From 1000 to 9999 - seven type of numbers are there in this rangea)x000 b)xx00 c)x0x0 d)x00x e)xxx0 f)xx0x g)x0xxTotal possibilities for x000 = 9*1*1*1 = 9, hence total zeros = 9*3 = 27 for xx00 = 9*9*1*1 = 81, hence total zeros = 81*2 = 162 for x0x0 = 9*1*9*1 = 81, hence total zeros = 81*2 = 162for x00x = 9*1*1*9 = 81, hence total zeros = 81*2 = 162 for xxx0 = 9*9*9*1 = 729, hence total zeros = 729*1 = 729for xx0x = 9*9*1*9 = 729, hence total zeros = 729*1 = 729for x0xx = 9*1*9*9 = 729, hence total zeros = 729*1 = 729total zeros in four digit numbers = 27 + 3*162 + 3*729 = 2700thus total zeros will be 0+9+180+2700+4 (last 4 is for 4 zeros of 10000)= 2893

Q: The average age of a couple and their son was 40 years, the son got married and a child was born just two years after their marriage. When child turned to 10 years, then the average age of the family becomes 38 years. What was the age of the daughter in law at the time of marriage ? 3263 0

  • 1
    12 years
    Correct
    Wrong
  • 2
    10 years
    Correct
    Wrong
  • 3
    14 years
    Correct
    Wrong
  • 4
    13 years
    Correct
    Wrong
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Answer : 1. "12 years"
Explanation :

Answer: A) 12 years Explanation: Given the average age of couple and their son = 40 => Sum of age (H +W +S) = 40×3 Let the age of daughter in law at the time of marriage = D years Now after 10 years, (H + S +W) + 3×12 + D +12 + 10 = 38×5 178 + D = 190 D = 190 -178 = 12 years

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