Quantitative Aptitude Practice Question and Answer

Q: Anil purchases two books for Rs.100. He sells first at loss of 5% and second al 20% profit. If he gets Overall profit of 5% then what is cost of first book? 1468 0

  • 1
    58
    Correct
    Wrong
  • 2
    60
    Correct
    Wrong
  • 3
    55
    Correct
    Wrong
  • 4
    45
    Correct
    Wrong
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Answer : 2. "60"
Explanation :

Answer: B) 60 Explanation: -5-----------------------5-------------------20 5-(-5) = 10 20-5= 15 Ratio of cost price of book1 and book2 = 3:2  Then cost price of book 1 is given by (3/5) x 100 = Rs. 60.

Q: 5 + 2 x 10 = 1046 0

  • 1
    70
    Correct
    Wrong
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    20
    Correct
    Wrong
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    25
    Correct
    Wrong
  • 4
    52
    Correct
    Wrong
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Answer : 3. "25"
Explanation :

Answer: C) 25 Explanation: According to BODMAS rule, After multiplication only, addition is done. Hence, 5 + 2 x 10 = 5 + 20 = 25.

Q: Simplify the following equation 55.55 + 155 + 15.55 + 0.5 + 0.05 = ? 2249 0

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    226.65
    Correct
    Wrong
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    196.55
    Correct
    Wrong
  • 3
    202.35
    Correct
    Wrong
  • 4
    216.66
    Correct
    Wrong
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Answer : 1. "226.65"
Explanation :

Answer: A) 226.65 Explanation: 55.55 + 155 + 15.55 + 0.5 + 0.05 = ?    55.55 155.00  15.55    0.5    0.05 _______ 226.65 _______   Hence, the value of the given equation 55.55 + 155 + 15.55 + 0.5 + 0.05 = 226.65.

Q: How many square units in 13 by 9? 1394 0

  • 1
    13
    Correct
    Wrong
  • 2
    9
    Correct
    Wrong
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    117
    Correct
    Wrong
  • 4
    13/9
    Correct
    Wrong
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Answer : 3. "117"
Explanation :

Answer: C) 117 Explanation: Number of square units in 13 by 9 is given by the area it forms with length and breadth as 13 & 9 Area = 13 x 9 = 117   Hence, number of square units in 13 by 9 is 117 sq.units.

Q: In a class 60% of the students pass in English and 45% pass in Hindi. If 25% of them pass in both subjects, what percentage of the students fail in both the subjects? 2339 0

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    20%
    Correct
    Wrong
  • 2
    25%
    Correct
    Wrong
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    30%
    Correct
    Wrong
  • 4
    15%
    Correct
    Wrong
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Answer : 1. "20%"
Explanation :

Answer: A) 20% Explanation: Percentage of students passed in English = 60% Percentage of students passed in Hindi = 45% Percentage of students passed in both subjects = 25% ATQ, Percentage of students passed in only English = 60 - 25 = 35% Percentage of students passed in only Hindi = 45 - 25 = 20% Therefore, Percentage of students failed = 100 - (35 + 25 + 20) = 100 - 80 = 20%.

Q: Find the wrong number in the given number series? 10, 21, 54, 109, 189 8464 0

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    189
    Correct
    Wrong
  • 2
    109
    Correct
    Wrong
  • 3
    54
    Correct
    Wrong
  • 4
    21
    Correct
    Wrong
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Answer : 1. "189"
Explanation :

Answer: A) 189 Explanation: The given number series is 10, 21, 54, 109, 189 The series follows a pattern that 10 + 11 = 21 21 + 33 = 54 54 + 55 = 109 109 + 77 = 186   Hence the wrong number in the given number series is 189.

Q: 5 boys and 3 girls can together cultivate a 23 acre field in 4 days and 3 boys and 2 girls together can cultivate a 7 acre field in 2 days. How many girls will be needed together with 7 boys, if they cultivate 45 acres of field in 6 days? 1280 0

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    4
    Correct
    Wrong
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    3
    Correct
    Wrong
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    2
    Correct
    Wrong
  • 4
    1
    Correct
    Wrong
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Answer : 3. "2"
Explanation :

Answer: C) 2 Explanation: Let workdone 1 boy in 1 day be b and that of 1 girl be g From the given data, 4(5b + 3g) = 23 20b + 12g = 23 .......(a)   2(3b + 2g) = 7 6b + 4g = 7 ........(b)   Solving (a) & (b), we get b = 1, g = 1/4   Let number og girls required be 'p' 6(7 x 1 + p x 1/4) = 45 => p = 2.   Hence, number of girls required = 2

Q: In how many ways the word 'SCOOTY' can be arranged such that 'S' and 'Y' are always at two ends? 1809 0

  • 1
    720
    Correct
    Wrong
  • 2
    360
    Correct
    Wrong
  • 3
    120
    Correct
    Wrong
  • 4
    24
    Correct
    Wrong
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Answer : 4. "24"
Explanation :

Answer: D) 24 Explanation: Given word is SCOOTY ATQ, Except S & Y number of letters are 4(C 2O's T) Hence, required number of arrangements = 4!/2! x 2! = 4! = 4 x 3 x 2 = 24 ways.

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